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Instructor's Solution Manual for Elementary Statistics: Picturing the World 7th Edition by Ron Larson, Chapter 1-11 | All Chapters

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Instructor's Solution Manual for Elementary Statistics: Picturing the World 7th Edition by Ron Larson, Chapter 1-11 | All Chapters

Institución
Elementary Statistics, 7th Edition
Grado
Elementary Statistics, 7th Edition











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Institución
Elementary Statistics, 7th Edition
Grado
Elementary Statistics, 7th Edition

Información del documento

Subido en
8 de septiembre de 2025
Número de páginas
208
Escrito en
2025/2026
Tipo
Examen
Contiene
Preguntas y respuestas

Temas

Vista previa del contenido

SOLUTION MANUAL
t




bra U U M
ionby s

,Contents


1 Linear Algebra and Optimization: An Introduction
U U U U U 1


2 Linear Transformations and Linear Systems
U U U U 17


3 Diagonalizable Matrices and Eigenvectors U U U 35


4 OptimizationBasics:AMachineLearningView U U U U U 47


5 Optimization Challenges and Advanced Solutions
U U U U 57


6 Lagrangian Relaxation and Duality
U U U 63


7 Singular Value Decomposition
U U 71


8 Matrix Factorization
U 81


9 The Linear Algebra of Similarity
U U U U 89


10 The Linear Algebra of Graphs
U U U U 95


11 Optimization in Computational GraphsU U U 101

,Chapter 1 U




Linear Algebra and Optimization: An Introduction
U U U U U




1. For any two vectors x and y, which are each of length a, show that (i)
U U U U U U U U U U U U U U U




x− y is orthogonal tox+y, and(ii) the dot product of x−3y and x+3y is
U U U U U U U U U U U U U U U U U U




negative.
U




(i) The first is simp·ly−x x y y using the distributive property of matrix
U U U U U U U U U U U U U




multiplication. The d· ot product of a vector with itself is its squared length.
U U U
U



U U U U U U U U U U




Sincebothvectorsareofthesamelength,itfollowsthattheresultis0.(ii)
U U U U U U U U U U U U U U U U




In the second case, one can use a similar argument to show that the result is a2 −
U U U U U U U U U U U U U U U U
U




9a2, which is negative.
U U U U




2. Consider a situation in which you have three matrices A, B, and C, of sizes U U U U U U U U U U U U U U




10×2, 2×10,and 10×10, respectively. U U U U




(a) Suppose you had to compute the matrix product ABC. From an efficiency per- U U U U U U U U U U U U




spective, wouldit computationally makemore sensetocompute (AB)C or would
U U t U U U U U




itmakemoresensetocomputeA(BC)?
U U U U U U U




(b) If you had to compute the matrix product CAB, would it make more sense to
U U U U U U U U U U U U U U




compute (CA)B or C(AB)? U U U U




The main point is to keep the size of the intermediate matrix as small as
U U U U U U U U U U U U U U




possible in order to reduce both computational and space requirements. In
U U U U U U U U U U U




the case of ABC, it makes sense to compute BC first. In the case of CAB it
U U U U U U U U U U U U U U U U U




makes sense to compute CA first. This type of associativity property
U U U U U U U U U U U




isused frequently inmachinelearningin orderto reducecomputational
U U U U U




requirements.
U




3. Show that if a matrix A satisfies A = AT,then allthe diagonal elements
U U U U U U U U U U U U U




of thematrixare0.
U U U U




Note that A + AT = 0. However, this matrix also contains twice the
U U U U
U



U U U U U U U U




diagonal elements of A on its diagonal. Therefore, the diagonal
U U U U U U U U U U




elementsofAmustbe0.
U U U U U U




4. Show that ifwe have a matrix satisfying A= UAT,thenforanycolumn U U U U U U U U U U




vectorx,wehave x Ax=0.
U
T
U U U U
U



U U




Note that the transpose of the scalar xT Ax remains unchanged. Therefore,
U U U U U U
U



U U U




1

, we have
U




xTAx=(xTAx)T =xTATx=−xTAx. Therefore, we have 2xTAx=0.
U U
U U



U U U U U U U U U




2
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