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Solution Manual for Trigonometry, 5th Edition by Cynthia Y. Young. Fully Solved trigonometry solutions.

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Solution Manual for Trigonometry, 5th Edition by Cynthia Y. Young helps students take the guesswork out of studying by offering them an easy to read and clear roadmap that tells them what to do, how to do it, and whether they did it right. With this revision, Cynthia Young tackles the most challenging topics in trigonometry, bringing clarity to those learning objectives. Trigonometry, Fifth Edition is written in a voice that speaks to students and mirrors how effective instructors communicate in lecture. Young's hallmark pedagogy enables students to become independent, successful learners. Key features like "Parallel Words and Math" and "Catch the Mistake" exercises are taken directly from classroom experience and keep the learning fresh and motivating.

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Institución
Trigonometry, 5th Edition
Grado
Trigonometry, 5th Edition

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Solution Manual
Trigonometry, 5th Edition
by Cynthia Y. Young




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1

, CHAPTER 1
Section 1.1 Solutions --------------------------------------------------------------------------------
1 x 1 x
1. Solve for x:  2. Solve for x: 
2 360∘ 4 360∘
360∘  2x, so that x  180∘ . 360∘  4x, so that x  90∘ .

1 x 2 x
3. Solve for x:   4. Solve for x:  
3 360∘ 3 360∘
360∘  3x, so that x  120∘ . 720∘  2(360∘ )  3x, so that x  240∘ .
(Note: The angle has a negative (Note: The angle has a negative




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measure since it is a clockwise measure since it is a clockwise rotation.)
rotation.)

5. Solve for x:
5
6

360∘
x LE 6. Solve for x:
7
12

x
360∘
1800∘  5(360∘ )  6x, so that x  300∘ . 2520∘  7(360∘ )  12x, so that x  210∘ .
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4 x 5 x
7. Solve for x:   8. Solve for x:  
5 360∘ 9 360∘
1440∘  4(360∘ )  5x, so that 1800∘  5(360∘ )  9x, so that
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x  288∘ . x  200∘ .
(Note: The angle has a negative (Note: The angle has a negative
measure since it is a clockwise measure since it is a clockwise rotation.)
rotation.)

9. 10.
a) complement: 90∘ 18∘  72∘ a) complement: 90∘  39∘  51∘
b) supplement: 180∘ 18∘  162∘ b) supplement: 180∘  39∘  141∘

11. 12.
a) complement: 90∘  42∘  48∘ a) complement: 90∘  57∘  33∘
b) supplement: 180∘  42∘  138∘ b) supplement: 180∘  57∘  123∘



2

, Section 1.1


13. 14.
a) complement: 90∘  89∘  1∘ a) complement: 90∘  75∘  15∘
b) supplement: 180∘  89∘  91∘ b) supplement: 180∘  75∘  105∘

15. Since the angles with measures 4x∘ and 6x∘ are assumed to be
complementary, we know that 4x∘  6x∘  90∘. Simplifying this yields

10x∘  90∘ , so that x  9. So, the two angles have measures 36∘and 54∘ .

16. Since the angles with measures 3x∘ and 15x∘ are assumed to be
supplementary, we know that 3x∘  15x∘  180∘. Simplifying this yields

18x∘  180∘, so that x  10.




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So, the two angles have measures 30∘ and 150∘ .

17. Since the angles with measures 8x∘ and 4x∘ are assumed to be
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supplementary, we know that 8x∘  4x∘  180∘. Simplifying this yields

12x∘  180∘, so that x  15. So, the two angles have measures 60∘ and 120∘ .
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18. Since the angles with measures 3x 15∘ and 10x 10∘ are assumed to be
complementary, we know that 3x 15∘  10x 10∘  90∘. Simplifying this yields
13x  25∘  90∘, so that 13x∘  65∘ and thus, x  5.
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So, the two angles have
measures 30∘and 60∘ .

19. Since       180∘, we know 20. Since       180∘, we know
that that
1 17∘ –33∘    180∘ and so,   30∘ . 1 10∘ –45∘    180∘ and so,   25∘ .
– –
 150∘  155∘



21. Since       180∘, we know 22. Since       180∘, we know
that that
 4          180∘ and so,   30∘. 3         180∘ and so,   36∘.
–– –– –– ––
 6   5

Thus,   4  120∘ and     30∘ . Thus,   3  108∘ and     36∘ .


3

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Institución
Trigonometry, 5th Edition
Grado
Trigonometry, 5th Edition

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Subido en
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Escrito en
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