ATI TEAS TEST PRACTICE EXAM
QUESTIONS WITH CORRECT
ANSWERS
The |price |of |a |20" |television |changed |from |$450 |to |$400. |Find |the |percentage |change |in |price.
A.
-10%
B.
-11%
C.
-13%
D.
-15% |- |CORRECT |ANSWER✔✔-Correct |answer: |-11%
Change |in |price: |450 |- |400 |= |50
To |determine |the |percentage |change, |divide |the |change |in |price |by |the |initial |price:
| 50 |= |0.1111
450
Multiply |by |100 |to |determine |the |percentage: |0.1111 |× |100 |= |11.11%
,Because |the |price |decreased, |the |change |in |price |is |negative: |-11.11%, |or |about |-11%
Which |of |the |following |is |not |a |type |of |natural |lipid?
A.
Supersaturated
B.
Polyunsaturated
C.
Saturated
D.
Unsaturated |- |CORRECT |ANSWER✔✔-Correct |answer: |Supersaturated
There |are |three |types |of |natural |lipids: |unsaturated, |polyunsaturated, |and |saturated. |
Supersaturation |is |a |not |a |naturally |occurring |lipid.
Unsaturated |and |polyunsaturated |lipids |have |one |or |more |double |bonds |between |carbon |
atoms |of |fatty |acid |chains; |saturated |lipids |share |no |such |double |bonds.
A |common |example |of |supersaturation |is |rock |candy, |which |is |created |from |a |supersaturated |
sugar |solution.
Which |of |the |following |is |not |true |of |mitosis?
, A.
Daughter |cells |are |different |than |parent |cells
B.
Daughter |cells |are |identical |to |parent |cells
C.
It |produces |daughter |cells
D.
It |occurs |only |in |eukaryotic |cells |- |CORRECT |ANSWER✔✔-Correct |answer: |Daughter |cells |are |
different |than |parent |cells
Mitosis |is |a |cell |cycle |during |which |a |parent |cell |produces |an |identical |daughter |cell. |It |has |
four |main |phases: |prophase, |metaphase, |anaphase, |and |telophase. |Since |the |parent |and |
daughter |cells |are |identical, |both |diploids |and |haploids |can |undergo |mitosis.
Mitosis |is |a |four-stage |process |that |creates |two |identical |cells |from |one |original |cell.
Prophase |is |the |first |and |longest |stage |of |mitosis. |In |this |stage, |the |chromosomes |become |
visible |and |the |centrioles |separate |and |move |to |opposite |poles |of |the |cell.
Metaphase |is |the |second |stage |of |mitosis. |In |this |stage, |the |chromosomes |line |up |across |the |
center |of |the |cell |and |become |connected |to |the |spindle |fiber |at |their |centromere.
Anaphase |is |the |third |stage |of |mitosis. |In |this |stage, |the |sister |chromatids |separate |into |
individual |chromosomes |and |are |pulled |apart.
Telophase |is |the |fourth |and |last |stage |of |mitosis. |During |this |stage, |the |chromosomes |gather |
at |opposite |ends |of |the |cell |and |lose |their |distinct |rod-like |shapes. |Two |new |nuclear |
QUESTIONS WITH CORRECT
ANSWERS
The |price |of |a |20" |television |changed |from |$450 |to |$400. |Find |the |percentage |change |in |price.
A.
-10%
B.
-11%
C.
-13%
D.
-15% |- |CORRECT |ANSWER✔✔-Correct |answer: |-11%
Change |in |price: |450 |- |400 |= |50
To |determine |the |percentage |change, |divide |the |change |in |price |by |the |initial |price:
| 50 |= |0.1111
450
Multiply |by |100 |to |determine |the |percentage: |0.1111 |× |100 |= |11.11%
,Because |the |price |decreased, |the |change |in |price |is |negative: |-11.11%, |or |about |-11%
Which |of |the |following |is |not |a |type |of |natural |lipid?
A.
Supersaturated
B.
Polyunsaturated
C.
Saturated
D.
Unsaturated |- |CORRECT |ANSWER✔✔-Correct |answer: |Supersaturated
There |are |three |types |of |natural |lipids: |unsaturated, |polyunsaturated, |and |saturated. |
Supersaturation |is |a |not |a |naturally |occurring |lipid.
Unsaturated |and |polyunsaturated |lipids |have |one |or |more |double |bonds |between |carbon |
atoms |of |fatty |acid |chains; |saturated |lipids |share |no |such |double |bonds.
A |common |example |of |supersaturation |is |rock |candy, |which |is |created |from |a |supersaturated |
sugar |solution.
Which |of |the |following |is |not |true |of |mitosis?
, A.
Daughter |cells |are |different |than |parent |cells
B.
Daughter |cells |are |identical |to |parent |cells
C.
It |produces |daughter |cells
D.
It |occurs |only |in |eukaryotic |cells |- |CORRECT |ANSWER✔✔-Correct |answer: |Daughter |cells |are |
different |than |parent |cells
Mitosis |is |a |cell |cycle |during |which |a |parent |cell |produces |an |identical |daughter |cell. |It |has |
four |main |phases: |prophase, |metaphase, |anaphase, |and |telophase. |Since |the |parent |and |
daughter |cells |are |identical, |both |diploids |and |haploids |can |undergo |mitosis.
Mitosis |is |a |four-stage |process |that |creates |two |identical |cells |from |one |original |cell.
Prophase |is |the |first |and |longest |stage |of |mitosis. |In |this |stage, |the |chromosomes |become |
visible |and |the |centrioles |separate |and |move |to |opposite |poles |of |the |cell.
Metaphase |is |the |second |stage |of |mitosis. |In |this |stage, |the |chromosomes |line |up |across |the |
center |of |the |cell |and |become |connected |to |the |spindle |fiber |at |their |centromere.
Anaphase |is |the |third |stage |of |mitosis. |In |this |stage, |the |sister |chromatids |separate |into |
individual |chromosomes |and |are |pulled |apart.
Telophase |is |the |fourth |and |last |stage |of |mitosis. |During |this |stage, |the |chromosomes |gather |
at |opposite |ends |of |the |cell |and |lose |their |distinct |rod-like |shapes. |Two |new |nuclear |
