WGU D335-Introduction to Programming in Python Newest Exam with precise answers

W GU D335-Intr oduction to |! |! |!




Pr ogr am m in g in Python New est |! |! |! |!




Exam w ith pr ecise answ er s |! |! |!




Create a solution that accepts three integer inputs representing the number of
|! |! |! |! |! |! |! |! |! |! |!




times an employee travels to a job site. Output the total distance traveled to
|! |! |! |! |! |! |! |! |! |! |! |! |! |! |!




two decimal places given the following miles per employee commute to the
|! |! |! |! |! |! |! |! |! |! |! |!




job site. Output the total distance traveled to two decimal places given the
|! |! |! |! |! |! |! |! |! |! |! |! |!




following miles per employee commute to the job site:
|! |! |! |! |! |! |! |!




Employee A: 15.62 miles |! |! |!




Employee B: 41.85 miles |! |! |!




Employee C: 32.67 miles |! |! |!




The solution output should be in the format
|! |! |! |! |! |! |!




Distance: total_miles_traveled miles - Correct answer ✔travels = {
|! |! |! |! |! |! |! |!




"A": int(input()),
|!




"B": int(input()),
|!




"C": int(input())
|!




}

miles_per_employee = {"A": 15.62, "B":41.85, "C": 32.67} |! |! |! |! |! |!




total_miles_traveled = sum(travels[employee] * |! |! |! |!




miles_per_employee[employee] for employee in travels) |! |! |! |!




print(f"Distance: {total_miles_traveled:.2f} miles") |! |!

, Create a solution that accepts an integer input representing any number of
|! |! |! |! |! |! |! |! |! |! |! |!




ounces. Output the converted total number of tons, pounds, and remaining
|! |! |! |! |! |! |! |! |! |! |!




ounces based on the input ounces value. There are 16 ounces in a pound and
|! |! |! |! |! |! |! |! |! |! |! |! |! |! |!




2,000 pounds in a ton.
|! |! |! |!




The solution output should be in the format
|! |! |! |! |! |! |!




Tons: value_1 Pounds: value_2 Ounces: value_3 - Correct answer ✔ounces =
|! |! |! |! |! |! |! |! |! |! |!




int(input())

value_1 = ounces // (16 * 2000) |! |! |! |! |! |!




value_2 = (ounces % (16 * 2000)) // 16
|! |! |! |! |! |! |! |!




value_3 = ounces % 16 |! |! |! |!




print(f"Tons: {value_1}") |!




print(f"Pounds: {value_2}") |!




print(f"Ounces: {value_3}") |!




Create a solution that accepts an integer input representing the index value
|! |! |! |! |! |! |! |! |! |! |! |!




for any any of the five elements in the following list:
|! |! |! |! |! |! |! |! |! |!




various_data_types = [516, 112.49, True, "meow", ("Western", "Governors", |! |! |! |! |! |! |! |!




"University"), {"apple": 1, "pear": 5}] |! |! |! |!




Using the built-in function type() and getting its name by using the .name
|! |! |! |! |! |! |! |! |! |! |! |! |!




attribute, output data type (e.g., int", "float", "bool", "str") based on the input
|! |! |! |! |! |! |! |! |! |! |! |! |!




index value of the list element.
|! |! |! |! |!




The solution output should be in the format
|! |! |! |! |! |! |!




Element index_value: data_type - Correct answer ✔index_value =
|! |! |! |! |! |! |! |!




int(input())

data_type = type(various_data_types[index_value]).__name__
|! |!