INSTRUCTOR’S
SOLUTIONS MANUAL
BEGINNING ALGEBRA
NINTH EDITION
John Tobey
North Shore Community College
Danvers, Massachusetts
Jeffrey Slater
North Shore Community College
Danvers, Massachusetts
Jamie Blair
Orange Coast College
Costa Mesa, California
Jennifer Crawford
Normandale Community College
Bloomington, Minnesota
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Contents
Chapter 0 1
Chapter 1 18
Chapter 2 37
Chapter 3 71
Chapter 4 92
Chapter 5 114
Chapter 6 135
Chapter 7 165
Chapter 8 198
Chapter 9 232
Chapter 10 256
Practice Final Examination 287
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Chapter 0
0.1 Exercises 8
25 1
26. = 3 25 = 8
13 3 24 3
2. : 17 is the denominator
17 1
3 17 11
4. 1: or 79 2
3 17 28. = 7 79 = 11
7 7 7
3 09
6. 3
4 7
2
20 5 × 4 5 15
8. = = 124 4 1
24 6 × 4 6 30. = 8 124 = 15 = 15
8 8 8 2
8 1× 8 1
10. = = 44
48 6 × 8 6 40
4
72 18 × 4
12. = =4
18 18 × 1
2 (4 × 5) + 2 20 + 2 22
32. 4 = = =
32 32 × 1 1 5 5 5 5
14. = =
64 32 × 2 2
1 (5 × 12) + 1 60 + 1 61
34. 5 = = =
33 11 × 3 3 12 12 12 12
16. = =
55 11 × 5 5 5 (1 × 6) + 5 6 + 5 11
36. 1 = = =
6 6 6 6
63 9 × 7 7
18. = =
81 9 × 9 9 2 (6 × 3) + 2 18 + 2 20
38. 6 = = =
3 3 3 3 3
19 4
20. = 5 19 = 3
5 5 1 (10 × 9) + 1 90 + 1 91
15 40. 10 = = =
4 9 9 9 9
78
54
7
5 42. = 78 ÷ 6
22. = 7 54 = 7 6
7 49 7 13
5 6 78
6
6 18
41 5
24. = 6 41 = 6 18
6 36 6 0
5 78
= 13
6
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Chapter 0: A Brief Review of Arithmetic Skills ISM: Beginning Algebra
5 ? 5 × 6 30 0.2 Exercises
44. = ⇒ =
9 54 9 × 6 54
2. You must change the fractions to equivalent
fractions with a common denominator.
5 ? 5 × 5 25
46. = ⇒ =
9 45 9 × 5 45 21 17
4. and
30 20
13 ? 13 × 3 39
48. = ⇒ = 30 = 2 ⋅ 3 ⋅ 5
17 51 17 × 3 51 20 = 2 ⋅ 2 ⋅ 5
LCD = 2 ⋅ 2 ⋅ 3 ⋅ 5 = 60
10 ? 10 × 4 40
50. = ⇒ =
15 60 15 × 4 60 5 1
6. and
18 24
7 ? 7 × 5 35 18 = 2 ⋅ 3 ⋅ 3
52. = ⇒ =
8 40 8 × 5 40 24 = 2 ⋅ 2 ⋅ 2 ⋅ 3
LCD = 2 ⋅ 2 ⋅ 2 ⋅ 3 ⋅ 3 = 72
45 ? 45 × 2 90
54. = ⇒ =
50 100 50 × 2 100 5 7
8. and
16 48
20 5× 4 5 16 = 2 ⋅ 2 ⋅ 2 ⋅ 2
56. = =
424 106 × 4 106 48 = 2 ⋅ 2 ⋅ 2 ⋅ 2 ⋅ 3
LCD = 2 ⋅ 2 ⋅ 2 ⋅ 2 ⋅ 3 = 48
1400 70 × 20 70
58. = =
2420 121× 20 121 11 7
10. and
12 20
3 3 12 = 2 ⋅ 2 ⋅ 3
60. = is raisins
1+ 3 +1 5 20 = 2 ⋅ 2 ⋅ 5
LCD = 2 ⋅ 2 ⋅ 3 ⋅ 5 = 60
1+ 3 4
62. = does not contain nuts 7 8
1+ 3 +1 5 12. and
30 45
6 6 3× 2 3 30 = 2 ⋅ 3 ⋅ 5
64. = = =
6 + 8 14 7 × 2 7 45 = 3 ⋅ 3 ⋅ 5
3 LCD = 2 ⋅ 3 ⋅ 3 ⋅ 5 = 90
of the students enrolled in 1994 were male.
7 1 3 9
14. , , and
Classroom Quiz 0.1 7 14 35
7=7
56 7 × 8 7 14 = 2 ⋅ 7
1. = = 35 = 5 ⋅ 7
88 11× 8 11
LCD = 2 ⋅ 5 ⋅ 7 = 70
11 (5 × 14) + 11 70 + 11 81
2. 5 ⇒ = = 3 5 11
14 14 14 14 16. , , and
8 12 42
109 1 8=2⋅2⋅2
3. =9 12 = 2 ⋅ 2 ⋅ 3
12 12
42 = 2 ⋅ 3 ⋅ 7
9
LCD = 2 ⋅ 2 ⋅ 2 ⋅ 3 ⋅ 7 = 168
12 109
108
1
2 Copyright © 2017 Pearson Education, Inc.
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