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Solutions Manual – Principles of Geotechnical Engineering, 10th Edition by Braja Das | All 18 Chapters Covered

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Solutions Manual – Principles of Geotechnical Engineering, 10th Edition by Braja M. Das | Complete Problem Solutions for Soil Mechanics and Foundation Engineering This expertly prepared solutions manual for Principles of Geotechnical Engineering, 10th Edition by Braja M. Das provides detailed, step-by-step answers to all end-of-chapter problems. It covers essential topics in soil mechanics such as particle-size distribution, consistency limits, compaction, permeability, stress distribution, consolidation, shear strength, slope stability, and more. Ideal for civil engineering students and instructors, this manual supports comprehensive learning, exam preparation, and homework assistance. geotechnical engineering solutions, Braja Das 10th edition answers, soil mechanics problem solving, consolidation calculations, slope stability practice, permeability examples, shear strength solutions, foundation engineering manual, geotechnical textbook solutions, civil engineering exam prep #GeotechnicalEngineering #BrajaDas #SoilMechanics #EngineeringSolutions #CivilEngineering #SlopeStability #FoundationDesign #SoilProperties #ExamPrep #HomeworkHelp

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,
, Chapter 2

D60 0.42 D302 0.212
2.1 Cu = = = 2.625 ≈ 2.63 ; Cc = = = 0.656 ≈ 0.66
D10 0.16 ( D60 )( D10 ) (0.42)(0.16)


D60 0.81 D302 0.412
2.2 Cu = = = 3.0 ; Cc = = = 0.768 ≈ 0.77
D10 0.27 ( D60 )( D10 ) (0.81)(0.27)


2.3 a.
Sieve Mass of soil retained Percent retained Percent
no. on each sieve (g) on each sieve finer
4 28 4.54 95.46
10 42 6.81 88.65
20 48 7.78 80.88
40 128 20.75 60.13
60 221 35.82 24.31
100 86 13.94 10.37
200 40 6.48 3.89
Pan 24 3.89 0.00
∑ 617 g




1
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, b. D10 = 0.16 mm; D30 = 0.29 mm; D60 = 0.45 mm

D60 0.45
c. Cu = = = 2.812 ≈ 2.81
D10 0.16

D302 0.292
d. Cc = = = 1.168 ≈ 1.17
( D60 )( D10 ) (0.45)(0.16)



2.4 a.
Sieve Mass of soil retained Percent retained Percent
no. on each sieve (g) on each sieve Finer
4 0 0.0 100.00
6 30 6.0 94.0
10 48.7 9.74 84.26
20 127.3 25.46 58.80
40 96.8 19.36 39.44
60 76.6 15.32 24.12
100 55.2 11.04 13.08
200 43.4 8.68 4.40
Pan 22 4.40 0.00
∑ 500 g




b. D10 = 0.13 mm; D30 = 0.3 mm; D60 = 0.9 mm

2
© 2014 Cengage Learning. All Rights Reserved. May not be scanned, copied or duplicated, or posted to a publicly accessible website, in whole or in part.

, D60 0 .9
c. Cu = = = 6.923 ≈ 6.92
D10 0.13

D302 0.32
d. Cc = = = 0.769 ≈ 0.77
( D60 )( D10 ) (0.9)(0.13)


2.5 a.
Sieve Mass of soil retained Percent retained Percent
no. on each sieve (g) on each sieve finer
4 0 0.0 100.00
10 40 5.49 94.51
20 60 8.23 86.28
40 89 12.21 74.07
60 140 19.20 54.87
80 122 16.74 38.13
100 210 28.81 9.33
200 56 7.68 1.65
Pan 12 1.65 0.00
∑ 729 g




b. D10 = 0.17 mm; D30 = 0.18 mm; D60 = 0.28 mm

D60 0.28
c. Cu = = = 1.647 ≈ 1.65
D10 0.17
3
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, D302 0.18 2
d. Cc = = = 0.68
( D60 )( D10 ) (0.28)(0.17)


2.6 a.
Sieve Mass of soil retained Percent retained Percent
no. on each sieve (g) on each sieve finer
4 0 0.0 100.00
6 0 0.0 100.00
10 0 0.0 100.00
20 9.1 1.82 98.18
40 249.4 49.88 48.3
60 179.8 35.96 12.34
100 22.7 4.54 7.8
200 15.5 3.1 4.7
Pan 23.5 4.7 0.00
∑ 500 g




b. D10 = 0.21 mm; D30 = 0.39 mm; D60 = 0.45 mm

D60 0.45
c. Cu = = = 2.142 ≈ 2.14
D10 0.21
D302 0.39 2
d. Cc = = = 1.609 ≈ 1.61
( D60 )( D10 ) (0.45)(0.21)

4
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,2.7 a.




b. Percent passing 2 mm = 100 GRAVEL: 100 – 100 = 0%
Percent passing 0.06 mm = 73 SAND: 100 – 73 = 27%
Percent passing 0.002 mm = 9 SILT: 73 – 9 = 64%
CLAY: 9 – 0 = 9%

c. Percent passing 2 mm = 100 GRAVEL: 100 – 100 = 0%
Percent passing 0.05 mm = 68 SAND: 100 – 68 = 32%
Percent passing 0.002 mm = 9 SILT: 68 – 9 = 59%
CLAY: 9 – 0 = 9%

d. Percent passing 2 mm = 100 GRAVEL: 100 – 100 = 0%
Percent passing 0.075 mm = 80 SAND: 100 – 80 = 20%
Percent passing 0.002 mm = 9 SILT: 80 – 9 = 71%
CLAY: 9 – 0 = 9%




5
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,2.8 a.




b. Percent passing 2 mm = 100 GRAVEL: 100 – 100 = 0%
Percent passing 0.06 mm = 30 SAND: 100 – 30 = 70%
Percent passing 0.002 mm = 5 SILT: 70 – 5 = 65%
CLAY: 5 – 0 = 5%

c. Percent passing 2 mm = 100 GRAVEL: 100 – 100 = 0%
Percent passing 0.05 mm = 28 SAND: 100 – 28 = 72%
Percent passing 0.002 mm = 5 SILT: 72 – 5 = 67%
CLAY: 5 – 0 = 5%

d. Percent passing 2 mm = 100 GRAVEL: 100 – 100 = 0%
Percent passing 0.075 mm = 34 SAND: 100 – 34 = 66%
Percent passing 0.002 mm = 5 SILT: 66 – 5 = 61%
CLAY: 5 – 0 = 5%




6
© 2014 Cengage Learning. All Rights Reserved. May not be scanned, copied or duplicated, or posted to a publicly accessible website, in whole or in part.

,2.9 a.




b. Percent passing 2 mm = 100 GRAVEL: 100 – 100 = 0%
Percent passing 0.06 mm = 84 SAND: 100 – 84 = 16%
Percent passing 0.002 mm = 28 SILT: 84 – 28 = 56%
CLAY: 28 – 0 = 28%

c. Percent passing 2 mm = 100 GRAVEL: 100 – 100 = 0%
Percent passing 0.05 mm = 83 SAND: 100 – 83 = 17%
Percent passing 0.002 mm = 28 SILT: 83 – 28 = 55%
CLAY: 28 – 0 = 28%

d. Percent passing 2 mm = 100 GRAVEL: 100 – 100 = 0%
Percent passing 0.075 mm = 90 SAND: 100 – 90 = 10%
Percent passing 0.002 mm = 28 SILT: 90 – 28 = 62%
CLAY: 28 – 0 = 28%




7
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, 2.10 a.




b. Percent passing 2 mm = 100 GRAVEL: 100 – 100 = 0%
Percent passing 0.06 mm = 65 SAND: 100 – 65 = 35%
Percent passing 0.002 mm = 35 SILT: 65 – 35 = 30%
CLAY: 35 – 0 = 35%

c. Percent passing 2 mm = 100 GRAVEL: 100 – 100 = 0%
Percent passing 0.05 mm = 62 SAND: 100 – 62 = 38%
Percent passing 0.002 mm = 35 SILT: 62 – 35 = 27%
CLAY: 35 – 0 = 35%

d. Percent passing 2 mm = 100 GRAVEL: 100 – 100 = 0%
Percent passing 0.075 mm = 70 SAND: 100 – 70 = 30%
Percent passing 0.002 mm = 35 SILT: 70 – 35 = 35%
CLAY: 35 – 0 = 35%




2.11 Gs = 2.7; temperature = 24°; time = 60 min; L = 9.2 cm

L (cm)
Eq. (2.5): D (mm) = K
t (min)


8
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