IICRC S500 Water Mitigation
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1. The homeowner is responsible to take the necessary steps to preserve
and protect their property from further damage
2. Four principles of water damage Provide for health and safety of workers and occu-
restoration: pants; Document everything; Mitigate, and Dry
3. Four principles of drying Extract, Evaporate, dehumidify, control temp
4. Extraction is removing excess water and is the first step in mit-
igation
5. Evaporation is achieved by using energy (heat) to transform water
trapped in porous materials into a vapor, thereby
releasing the moisture from the materials.
6. Dehumidification the process of removing water vapor from the air.
7. Rate of Dehumidification must be at least equal to the rate of evaporation.
8. True or False Elevated vapor pressure in a room Can cause sec-
ondary damage to hygroscopic materials
9. True or False The control of temperature is important to enhance
both evaporation and dehumidification for effective
drying
10. True or False When temperature increases evaporation of ab-
sorbed water increases and water vapor suspended
in air also increases.
11. Classification of Water Intrusion described as Class 1, 2, 3, or 4. Must be determined
to calculate the amount of dehumidification required
in drying process, based on the amount of wet sur-
, IICRC S500 Water Mitigation
Study online at https://quizlet.com/_9l8q1w
face area, permeance/porosity of materials in drying
area.
12. Class 1 is the least amount of water absorption and evapora-
tion load, affecting less 5% of porous materials with
minimal absorption into low evaporation materials.
13. Class 2 has a significant amount of water absorption and
evaporation load, affection 5-40% porous materials,
with minimal absorption into low evaporated mate-
rials
14. Class 3 has the greatest amount of water absorption and
evaporation load, affecting more than 40% porous
materials and minimal absorption into low evaporat-
ed materials
15. Class 4 has deeply held or bound water, and significant ab-
sorption into low evaporation materials.
16. Determine the Class of water for a Affected area/Total SF = % affected
20' x 20' x 8 ' room, with an entirely 400/1440 = .27777 x 100 = 28%
wet floor.. 28% = Class 2
17. Determine the Class of Water for a Affected area/total sf = % affected
20' x 20' x 8' room, with only half the 200/1440 = .13888 x 100 = 14%
floor affected and arriving within 24 14% = Class 2
hours of loss.
18. Determine Class of water for a 20' affected area/total sf = % affected
x 20' x 8' room, with entirely wet Class 4 due to deeply bound water sitting for long
plywood subfloor arriving 48 hours time
after loss
Study online at https://quizlet.com/_9l8q1w
1. The homeowner is responsible to take the necessary steps to preserve
and protect their property from further damage
2. Four principles of water damage Provide for health and safety of workers and occu-
restoration: pants; Document everything; Mitigate, and Dry
3. Four principles of drying Extract, Evaporate, dehumidify, control temp
4. Extraction is removing excess water and is the first step in mit-
igation
5. Evaporation is achieved by using energy (heat) to transform water
trapped in porous materials into a vapor, thereby
releasing the moisture from the materials.
6. Dehumidification the process of removing water vapor from the air.
7. Rate of Dehumidification must be at least equal to the rate of evaporation.
8. True or False Elevated vapor pressure in a room Can cause sec-
ondary damage to hygroscopic materials
9. True or False The control of temperature is important to enhance
both evaporation and dehumidification for effective
drying
10. True or False When temperature increases evaporation of ab-
sorbed water increases and water vapor suspended
in air also increases.
11. Classification of Water Intrusion described as Class 1, 2, 3, or 4. Must be determined
to calculate the amount of dehumidification required
in drying process, based on the amount of wet sur-
, IICRC S500 Water Mitigation
Study online at https://quizlet.com/_9l8q1w
face area, permeance/porosity of materials in drying
area.
12. Class 1 is the least amount of water absorption and evapora-
tion load, affecting less 5% of porous materials with
minimal absorption into low evaporation materials.
13. Class 2 has a significant amount of water absorption and
evaporation load, affection 5-40% porous materials,
with minimal absorption into low evaporated mate-
rials
14. Class 3 has the greatest amount of water absorption and
evaporation load, affecting more than 40% porous
materials and minimal absorption into low evaporat-
ed materials
15. Class 4 has deeply held or bound water, and significant ab-
sorption into low evaporation materials.
16. Determine the Class of water for a Affected area/Total SF = % affected
20' x 20' x 8 ' room, with an entirely 400/1440 = .27777 x 100 = 28%
wet floor.. 28% = Class 2
17. Determine the Class of Water for a Affected area/total sf = % affected
20' x 20' x 8' room, with only half the 200/1440 = .13888 x 100 = 14%
floor affected and arriving within 24 14% = Class 2
hours of loss.
18. Determine Class of water for a 20' affected area/total sf = % affected
x 20' x 8' room, with entirely wet Class 4 due to deeply bound water sitting for long
plywood subfloor arriving 48 hours time
after loss
