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Bontrager- Chapter 5 Test Questions With 100% Verified Solutions

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Bontrager- Chapter 5 Test Questions With 100% Verified Solutions lateral angle of scapula - ANSWER- called head of the scapula, the thickest part ends laterally in glenoid fossa Scapulohumeral joint - ANSWER- shoulder joint neck of scapula - ANSWER- constricted region around the glenoid cavity costal surface of scapula - ANSWER- anterior surface spine of scapula - ANSWER- joints of the shoulder griddle - ANSWER- sternoclaviculkar (ball & socket) acromioclavicular (plane) scapulohumeral (plane) ALL synovial/diarthrodial AP Humerus Projection - ANSWER- -Shoulder placed in external rotation -Epicondyles will be parallel to the IR -Hands supinated -Center to mid-humerus Lateromedial Humerus Projection - ANSWER- -Back to IR -internal rotation -epicondyles perpendicular to IR -Center to mid-humerus Mediolateral Humerus Projection - ANSWER- -Patient facing IR -oblique as needed (20-30 from PA) -flex elbow 90 degrees -Center to mid-humerus what projection is done for fractures of the diaphysis of the humerus? - ANSWER- transthoracic lateral projection: Humerus (trauma) Lawrence Method (nontrauma) - ANSWER- inferosuperior axial projection-shoulder -Patient supine -Arm abducted 90 degrees, external rotation -CR 25-30 medially into axilla (humeral head -done to see head of humerus and scapulohumeral cavity Hill-Sachs defect - ANSWER- Compression fracture of the articular surface of the humeral head what position is done to see the the scapulohumeral joint space? - ANSWER- Grashey Method -checking for bankart lesions, erosion of the glenoid rim, integerity of joint. How should you angle the CR for an AP axial of the clavicle? - ANSWER- 15-30 cephalic what angle will asthenic patients need for an AP axial of the clavicle? - ANSWER- 25-30 cephalic what angle will hypersthenic patients need for an AP axial of the clavicle? - ANSWER- 15-20 cephalic why is the Pearson method done? - ANSWER- possible AC joint separation -Center midpoint to AC joints AC joint rules - ANSWER- always 72 inches always bilateral always w and w/o weights minimum weight to be used for Pearson method? - ANSWER- 8-10 lbs why cant the patient hold the weights for AP AC joint projection? - ANSWER- patients tend to pull on the weights which results in contraction instead of relaxation of the shoulder muscle. False-negative radiograph AP Scapula - ANSWER- -Arm abducted 90 degrees -Hand supinated (Abduction moves scapula laterally to clear more thoracic structures) -Center 2 inches inferior to coracoid (level of axilla) what lateral position best demonstrates the scapula body? - ANSWER- 45 degrees LAO/RAO scapula what lateral position best demonstrates coracoid and acromion process? - ANSWER- 60 degrees LAO/RAO scapula 3 parts of the clavicle - ANSWER- sternal extremity, acromial extremity, body When is the greater tubercle seen laterally? - ANSWER- external rotation of humerus when is the lesser tubercle seen medially? - ANSWER- internal rotation of the humerus when are the epicondyles 45 degrees to the IR? - ANSWER- neutral rotation of the humerus where is the CR placed for AP projection of the shoulder? - ANSWER- 1 inch inferior to coracoid process which lateral position can be done to demonstrate entire humerus? - ANSWER- transthoracic lateral projection what projection best demonstrates a dislocation of the proximal humerus? - ANSWER- Scap Y (posterior oblique) what landmarks are placed perpendicular for a Scap Y? - ANSWER- superior angle of scapula and AC joint what must be ruled out before preforming the weight-bearing study for AC joints? - ANSWER- fracture of scapula largest, longest bone of upper limb - ANSWER- humerus the proximal humerus articulates with - ANSWER- scapula most proximal part of the humerus - ANSWER- head anatomic neck - ANSWER- narrow constriction superior to the tubercles lesser tubercle - ANSWER- anterior surface

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Bontrager- Chapter 5
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Bontrager- Chapter 5
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Bontrager- Chapter 5

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Subido en
16 de mayo de 2025
Número de páginas
5
Escrito en
2024/2025
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Examen
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Bontrager- Chapter 5 Test Questions With 100%
Verified Solutions

lateral angle of scapula - ANSWER- called head of the scapula, the thickest part ends
laterally in glenoid fossa

Scapulohumeral joint - ANSWER- shoulder joint

neck of scapula - ANSWER- constricted region around the glenoid cavity

costal surface of scapula - ANSWER- anterior surface

spine of scapula - ANSWER-

joints of the shoulder griddle - ANSWER- sternoclaviculkar (ball & socket)
acromioclavicular (plane)
scapulohumeral (plane)

ALL synovial/diarthrodial

AP Humerus Projection - ANSWER- -Shoulder placed in external rotation
-Epicondyles will be parallel to the IR
-Hands supinated
-Center to mid-humerus

Lateromedial Humerus Projection - ANSWER- -Back to IR
-internal rotation
-epicondyles perpendicular to IR
-Center to mid-humerus

Mediolateral Humerus Projection - ANSWER- -Patient facing IR
-oblique as needed (20-30 from PA)
-flex elbow 90 degrees
-Center to mid-humerus

what projection is done for fractures of the diaphysis of the humerus? - ANSWER-
transthoracic lateral projection: Humerus (trauma)

, Lawrence Method (nontrauma) - ANSWER- inferosuperior axial projection-shoulder
-Patient supine
-Arm abducted 90 degrees, external rotation
-CR 25-30 medially into axilla (humeral head
-done to see head of humerus and scapulohumeral cavity

Hill-Sachs defect - ANSWER- Compression fracture of the articular surface of the
humeral head

what position is done to see the the scapulohumeral joint space? - ANSWER- Grashey
Method
-checking for bankart lesions, erosion of the glenoid rim, integerity of joint.

How should you angle the CR for an AP axial of the clavicle? - ANSWER- 15-30
cephalic

what angle will asthenic patients need for an AP axial of the clavicle? - ANSWER- 25-30
cephalic

what angle will hypersthenic patients need for an AP axial of the clavicle? - ANSWER-
15-20 cephalic

why is the Pearson method done? - ANSWER- possible AC joint separation
-Center midpoint to AC joints

AC joint rules - ANSWER- always 72 inches
always bilateral
always w and w/o weights

minimum weight to be used for Pearson method? - ANSWER- 8-10 lbs

why cant the patient hold the weights for AP AC joint projection? - ANSWER- patients
tend to pull on the weights which results in contraction instead of relaxation of the
shoulder muscle. False-negative radiograph

AP Scapula - ANSWER- -Arm abducted 90 degrees
-Hand supinated
(Abduction moves scapula laterally to clear more thoracic structures)
-Center 2 inches inferior to coracoid (level of axilla)
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