A 23-year-old woman has 10 Escherichia coli inoculated into her bladder while having
sex. This organism has a generation time of 20 minutes. After a lag of 20 minutes, the E
coli enter the logarithmic phase of growth. After 3 hours of logarithmic growth, the total
number of cells is
(A) 2560
(B) 5012
(C) 90
(D) 1028
(E) 1,000,000 - A
A 73-year-old woman is admitted to the hospital for intravenous treatment of an abscess
caused by Staphylococcus aureus. Subse- quent to her treatment and discharge from
the hospital, it is neces- sary to disinfect the hospital room. One thousand of the S
aureus cells are exposed to a disinfectant. After 10 minutes, 90% of the
cells are killed. How many cells remain viable after 20 minutes?
(A) 500
(B) 100
(C) 10
(D) 1
(E) 0 - C
The action of which of the following agents or processes on non-spore forming bacteria
can be reversed?
(A) A disinfectant
(B) A bactericidal agent
(C) A bacteriostatic agent
(D) Autoclaving at 121°C for 15 minutes
(E) Dry heat at 160-170°C for 1 hour - C
The growth rate of bacteria during the exponential phase of growth is
(A) Zero
(B) Increasing (C) Constant (D) Decreasing (E) Negative - C
A physician obtains a sputum specimen from a patient suffer- ing from tuberculosis.
This sputum sample contains one viable Mycobacterium tuberculosis, an organism with
a slow doubling time in vitro of 48 hours, which corresponds to a growth rate constant in
vitro of (κ) of 0.04 h-1. Estimating that the bio- mass of this single mycobacterial
organism is 2.3 × 10−13 g and assuming that this organism is immediately going to
enter log phase growth, how many hours will it take to produce 10−6 g of biomass?
(A) 4hours
(B) 40 hours
(C) 400 hours