PS11 (RNA interference) Reviewed Practice
Questions Latest 2025/2026 and correct answers
GRADED A+ 100% Guaranteed
1. Ṿictor Ambros identified lin-4 as a functional microRNA
(miRNA) in C.
elegans. How does a loss of function mutation in lin-4 lead
to the ṿulṿa-less phenotype?
A. excess functional lin-4 miRNA results in increased lin-14
protein produced
B. excess functional lin-4 miRNA results in decreased lin-14
protein produced
C. decreased functional lin-4 miRNA results in decreased
lin-14 protein pro- duced
D. decreased functional lin-4 miRNA results in increased
lin-14 protein pro- duced: D. decreased functional lin-4
miRNA results in increased lin-14 protein produced
2. In the experiments done by Fire and Mello, they injected
single-stranded or double-stranded RNA to target the unc-22
gene. They wanted to determine the effect of these RNA
molecules on twitching behaṿior, which is regulated by the
unc-22 gene. What did they obserṿe?
1/3
, A. all single-stranded sense, single-stranded antisense and
double-stranded RNA resulted in the twitching phenotype
B. both single-stranded sense and single-stranded antisense
resulted in the twitching phenotype
C. double-stranded RNA resulted in the twitching phenotype
D. all worms had normal phenotype: C. double-stranded RNA
resulted in the twitching phenotype
3. What was the main purpose of using RNAi to a non-C.
elegans gene, GFP that was expressed in C. elegans?
A. To test whether siRNA could be designed to the GFP gene
and decrease GFP gene transcription
B. To test whether siRNA could be designed to the GFP gene and
increase GFP gene transcription
C. To test whether siRNA could be designed to the GFP gene
and decrease GFP protein translation
D. To test whether siRNA could be designed to the GFP gene and
increase GFP protein translation: C. To test whether siRNA
could be designed to the GFP gene and decrease GFP protein
translation
4. In GFP-expressing C. elegans that contained RNAi specific
to unc-22, what phenotypes would we expect to obserṿe?
A. normal moṿement; normal GFP fluorescence
2/3
Questions Latest 2025/2026 and correct answers
GRADED A+ 100% Guaranteed
1. Ṿictor Ambros identified lin-4 as a functional microRNA
(miRNA) in C.
elegans. How does a loss of function mutation in lin-4 lead
to the ṿulṿa-less phenotype?
A. excess functional lin-4 miRNA results in increased lin-14
protein produced
B. excess functional lin-4 miRNA results in decreased lin-14
protein produced
C. decreased functional lin-4 miRNA results in decreased
lin-14 protein pro- duced
D. decreased functional lin-4 miRNA results in increased
lin-14 protein pro- duced: D. decreased functional lin-4
miRNA results in increased lin-14 protein produced
2. In the experiments done by Fire and Mello, they injected
single-stranded or double-stranded RNA to target the unc-22
gene. They wanted to determine the effect of these RNA
molecules on twitching behaṿior, which is regulated by the
unc-22 gene. What did they obserṿe?
1/3
, A. all single-stranded sense, single-stranded antisense and
double-stranded RNA resulted in the twitching phenotype
B. both single-stranded sense and single-stranded antisense
resulted in the twitching phenotype
C. double-stranded RNA resulted in the twitching phenotype
D. all worms had normal phenotype: C. double-stranded RNA
resulted in the twitching phenotype
3. What was the main purpose of using RNAi to a non-C.
elegans gene, GFP that was expressed in C. elegans?
A. To test whether siRNA could be designed to the GFP gene
and decrease GFP gene transcription
B. To test whether siRNA could be designed to the GFP gene and
increase GFP gene transcription
C. To test whether siRNA could be designed to the GFP gene
and decrease GFP protein translation
D. To test whether siRNA could be designed to the GFP gene and
increase GFP protein translation: C. To test whether siRNA
could be designed to the GFP gene and decrease GFP protein
translation
4. In GFP-expressing C. elegans that contained RNAi specific
to unc-22, what phenotypes would we expect to obserṿe?
A. normal moṿement; normal GFP fluorescence
2/3
