WORKSHEET 5-2 QUESTIONS AND ANSWERS WITH SOLUTIONS 2024/25

one coulomb per second is equivalent to 1 A and 1 C is equal to 6.3 x 10^18 electrons. therefore, operation at 100 mA would result in a current of: - ANSWER 6.3 x 10^17 electrons/s the filament transformer: - ANSWER increases current located with the high-voltage generator, a step-down transformer - ANSWER the filament transformer a PA chest requires a technique of 125 kVp @ 4 mAs. the total number of electrons used to make the exposure is: - ANSWER 2.5 X 10^16 begins at the autotransformer and ends at the filament - ANSWER the filament transformer could be expressed in coulombs - ANSWER mAs *an exposure technique of 100 mA at 100 ms compared with 50 mA at 50 ms results in: - ANSWER four times the total number of electrons the cont