100% de satisfacción garantizada Inmediatamente disponible después del pago Tanto en línea como en PDF No estas atado a nada 4,6 TrustPilot
logo-home
Examen

Sta midterm ch4 Exam Questions And Answers 100% Pass

Puntuación
-
Vendido
-
Páginas
14
Grado
A+
Subido en
13-11-2024
Escrito en
2024/2025

Sta midterm ch4 Exam Questions And Answers 100% Pass If A denotes some event, what does A bar(complement) denote? If P(A)=0.005, what is the value of P(A bar)? If P(A)=0.005, is A bar(complement) unlikely? - answerEvent A bar(complement) denotes the complement of event A, meaning that A bar(complement) consists of all outcomes in which event A does not occur. P(A bar) = .995 It is not unlikely How do you get the probability of the complement of A or P(A bar(complement))? - answer1 - P(A) Assume that 900 births are randomly selected and exactly 446 of the births are girls. Use subjective judgment to determine whether the given outcome is unlikely, and also determine whether it is unusual in the sense that the result is far from what is typically expected. a) Determine whether exactly 446 girls out of 900 randomly selected births is unlikely. b) Determine whether exactly 446 girls out of 900 randomly selected births is unusual. - answera) It is unlikely because the probability of this particular outcome is very small, considering all of the other possible outcomes. b) It is not unusual because 446 is about the number of girls expected. explanation: the specific number "446" is unlikely, but 446 is not unusual because the probability of having a girl is 0.5, and half of 900 is 450. In a test of a gender-selection technique, results consisted of 274 baby girls and 5 baby boys. Based on this result, what is the probability of a girl born to a couple using this technique? Does it appear that the technique is effective in increasing the likelihood that a baby will be a girl? - answerThe probability of a girl born is 274/279. ©THEBRIGHT EXAM SOLUTIONS 11/06/2024 10:41 AM Yes it is effective In a genetics experiment on peas, one sample of offspring contained 355 green peas and 132 yellow peas. Based on those results, estimate the probability of getting an offspring pea that is green. Is the result reasonably close to the value of 3/4 that was expected? - answerThe probability of getting an offspring pea that is green is 355/487. explanation: 355 + 132 = 487, then 355/487 = .729 Yes, 0.729 is close to 3/4. To the right are the outcomes that are possible when a couple has three children. Refer to that list, and find the probability of each event. boy-boy-boy boy-boy-girl boy-girl-boy boy-girl-girl girl-boy-boy girl-boy-girl girl-girl-boy girl-girl-girl a. Among three children, there is exactly 1 boy. b. Among three children, there are exactly 0 boys. c. Among three children, there are exactly 2 boys. - answera) 3/8 b) 1/8 c) 3/8 If a couple were planning to have three children, the sample space summarizing the gender outcomes would be: bbb, bbg, bgb, bgg, gbb, gbg, ggb, ggg. a. Construct a similar sample space for the possible eye color outcomes (using b for blue-eyed and g for green-eyed) of two children. b. Assuming that the outcomes listed in part (a) were equally likely, find the probability of getting two blue-eyed children.

Mostrar más Leer menos
Institución
Sta
Grado
Sta

Vista previa del contenido

©THEBRIGHT EXAM SOLUTIONS

11/06/2024 10:41 AM


Sta midterm ch4 Exam Questions And
Answers 100% Pass


If A denotes some event, what does A bar(complement) denote? If P(A)=0.005, what is the
value of P(A bar)? If P(A)=0.005, is A bar(complement) unlikely? - answer✔Event A
bar(complement) denotes the complement of event A, meaning that A bar(complement)
consists of all outcomes in which event A does not occur.
P(A bar) = .995
It is not unlikely

How do you get the probability of the complement of A or P(A bar(complement))? - answer✔1 -
P(A)
Assume that 900 births are randomly selected and exactly 446 of the births are girls. Use
subjective judgment to determine whether the given outcome is unlikely, and also determine
whether it is unusual in the sense that the result is far from what is typically expected.
a) Determine whether exactly 446 girls out of 900 randomly selected births is unlikely.
b) Determine whether exactly 446 girls out of 900 randomly selected births is unusual. -
answer✔a) It is unlikely because the probability of this particular outcome is very small,
considering all of the other possible outcomes.
b) It is not unusual because 446 is about the number of girls expected.


explanation: the specific number "446" is unlikely, but 446 is not unusual because the
probability of having a girl is 0.5, and half of 900 is 450.
In a test of a gender-selection technique, results consisted of 274 baby girls and 5 baby boys.
Based on this result, what is the probability of a girl born to a couple using this technique? Does
it appear that the technique is effective in increasing the likelihood that a baby will be a girl? -
answer✔The probability of a girl born is 274/279.

, ©THEBRIGHT EXAM SOLUTIONS

11/06/2024 10:41 AM

Yes it is effective
In a genetics experiment on peas, one sample of offspring contained 355 green peas and 132
yellow peas. Based on those results, estimate the probability of getting an offspring pea that is
green. Is the result reasonably close to the value of 3/4 that was expected? - answer✔The
probability of getting an offspring pea that is green is 355/487. explanation: 355 + 132 = 487,
then 355/487 = .729
Yes, 0.729 is close to 3/4.
To the right are the outcomes that are possible when a couple has three children. Refer to that
list, and find the probability of each event.
boy-boy-boy
boy-boy-girl
boy-girl-boy
boy-girl-girl
girl-boy-boy
girl-boy-girl
girl-girl-boy
girl-girl-girl
a. Among three children, there is exactly 1 boy.
b. Among three children, there are exactly 0 boys.

c. Among three children, there are exactly 2 boys. - answer✔a) 3/8
b) 1/8
c) 3/8
If a couple were planning to have three children, the sample space summarizing the gender
outcomes would be: bbb, bbg, bgb, bgg, gbb, gbg, ggb, ggg.
a. Construct a similar sample space for the possible eye color outcomes (using b for blue-eyed
and g for green-eyed) of two children.
b. Assuming that the outcomes listed in part (a) were equally likely, find the probability of
getting two blue-eyed children.

Escuela, estudio y materia

Institución
Sta
Grado
Sta

Información del documento

Subido en
13 de noviembre de 2024
Número de páginas
14
Escrito en
2024/2025
Tipo
Examen
Contiene
Preguntas y respuestas

Temas

$11.99
Accede al documento completo:

100% de satisfacción garantizada
Inmediatamente disponible después del pago
Tanto en línea como en PDF
No estas atado a nada

Conoce al vendedor

Seller avatar
Los indicadores de reputación están sujetos a la cantidad de artículos vendidos por una tarifa y las reseñas que ha recibido por esos documentos. Hay tres niveles: Bronce, Plata y Oro. Cuanto mayor reputación, más podrás confiar en la calidad del trabajo del vendedor.
Thebright Florida State University
Seguir Necesitas iniciar sesión para seguir a otros usuarios o asignaturas
Vendido
185
Miembro desde
1 año
Número de seguidores
6
Documentos
12718
Última venta
17 horas hace
Topscore Emporium.

On this page, you find verified, updated and accurate documents and package deals.

3.8

36 reseñas

5
14
4
10
3
7
2
1
1
4

Recientemente visto por ti

Por qué los estudiantes eligen Stuvia

Creado por compañeros estudiantes, verificado por reseñas

Calidad en la que puedes confiar: escrito por estudiantes que aprobaron y evaluado por otros que han usado estos resúmenes.

¿No estás satisfecho? Elige otro documento

¡No te preocupes! Puedes elegir directamente otro documento que se ajuste mejor a lo que buscas.

Paga como quieras, empieza a estudiar al instante

Sin suscripción, sin compromisos. Paga como estés acostumbrado con tarjeta de crédito y descarga tu documento PDF inmediatamente.

Student with book image

“Comprado, descargado y aprobado. Así de fácil puede ser.”

Alisha Student

Preguntas frecuentes