CHM142 Exam 4 Review 2024/2025 with Correct Answers
Which of the following titrations will result in a noticeably basic solution at the equivalence point? KOH(aq) + HI(aq) HCl(aq) + NaOH(aq) CH3COOH(aq) + NaOH(aq) NH3(aq) + HClO4(aq) NaHCO3(aq) + HCl(aq) - Ans: CH3COOH(aq) + NaOH(aq) Which of the following indicators is suitable for the titration of 0.10 M CH3COOH (Ka = 1.8 x 10-5) with 0.15 M NaOH? methyl orange (Ka = 2.0 x 10-4) phenolphthalein (Ka = 4.0 x 10-10) bromocresol green (Ka = 2.0 x 10-5) bromothymol blue (Ka = 1.0 x 10-7) methyl red (Ka = 7.9 x 10-6) - Ans: phenolphthalein (Ka = 4.0 x 10-10) Calculate the concentration of fluoride ions in a saturated solution of chromium fluoride (CrF3). Ksp(CrF3) = 6.6 x 10-11 - Ans: 3.9 x 10-3 M What is the molar solubility of PbBr2 in a 0.15 M solution of KBr? Ksp(PbBr2) = 6.6 x 10-6. - Ans: 2.9 x 10-4 M Which of the following salts will not be significantly more soluble in acidic solution than in pure water? Which of the following titrations will result in a noticeably acidic solution at the equivalence point? (CH3)3N(aq) + HClO4(aq) HBr(aq) + KOH(aq) HCNO(aq) + NaOH(aq) CH3COOH(aq) + LiOH(aq) Ca(OH)2(aq) + HI(aq) - Ans: (CH3)3N(aq) + HClO4(aq) What should be the approximate value of pKa of an indicator that can be used to titrate a solution of a weak acid with a solution of a strong base? pKa = 4 pKa = 5 pKa = 13 pKa = 9 pKa = 7 - Ans: pKa = 9 The expression for the solubility-product constant for zirconium fluoride, ZrF4, is - Ans: Ksp = [Zr4+] [F-]4 The concentration of PO43- ions in a saturated solution of cadmium phosphate, Cd3(PO4)2, was found to be 2.4 x 10-7 M. What is the Ksp for Cd3(PO4)2?
Escuela, estudio y materia
- Institución
- University Of Miami
- Grado
- CHM142 (CHM142)
Información del documento
- Subido en
- 15 de octubre de 2024
- Número de páginas
- 14
- Escrito en
- 2024/2025
- Tipo
- Examen
- Contiene
- Preguntas y respuestas
Temas
-
chm142
-
miami university
-
chm142 exam
