M5: Exam - Requires Respondus LockDown
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• Due No due date
• Points 100
• Questions 10
• Time Limit 120 Minutes
• Requires Respondus LockDown Browser
Attempt History
Attempt Time Score
LATEST Attempt 1 119 minutes 69.5 out of 100
Score for this quiz: 69.5 out of 100
Submitted Feb 4 at 11:17pm
This attempt took 119 minutes.
Question 1
pts
You may find the following resources helpful:
Scientific Calculator (Links to an external site.)
Periodic Table
Equation Table
, In the reaction of gaseous N2O5 to yield NO2 gas and O2gas as shown below the
following data table is obtained:
2 N2O5 (g) → 4 NO2 (g) + O2 (g)
Data Table #1
Time (sec) [N2O5] [O2]
0 0.200 M 0
300 0.182 M 0.009 M
600 0.166 M 0.017 M
900 0.152 M 0.024 M
1200 0.140 M 0.030 M
1800 0.122 M 0.039 M
2400 0.112 M 0.044 M
3000 0.108 M 0.046 M
Complete the following three problems:
1. Using the [O2] data from the table show the calculation of the instantaneous rate early
in the reaction (0 secs to 300 sec).
2. Using the [O2] data from the table show the calculation of the instantaneous rate late
in the reaction (2400 secs to 3000 secs).
3. Explain the relative values of the early instantaneous rate and the late instantaneous
rate.
Your Answer:
1.
.009-0/300-0 = .009/300 = .00003 = 3.0 x 10-5
Browser + Webcam
• Due No due date
• Points 100
• Questions 10
• Time Limit 120 Minutes
• Requires Respondus LockDown Browser
Attempt History
Attempt Time Score
LATEST Attempt 1 119 minutes 69.5 out of 100
Score for this quiz: 69.5 out of 100
Submitted Feb 4 at 11:17pm
This attempt took 119 minutes.
Question 1
pts
You may find the following resources helpful:
Scientific Calculator (Links to an external site.)
Periodic Table
Equation Table
, In the reaction of gaseous N2O5 to yield NO2 gas and O2gas as shown below the
following data table is obtained:
2 N2O5 (g) → 4 NO2 (g) + O2 (g)
Data Table #1
Time (sec) [N2O5] [O2]
0 0.200 M 0
300 0.182 M 0.009 M
600 0.166 M 0.017 M
900 0.152 M 0.024 M
1200 0.140 M 0.030 M
1800 0.122 M 0.039 M
2400 0.112 M 0.044 M
3000 0.108 M 0.046 M
Complete the following three problems:
1. Using the [O2] data from the table show the calculation of the instantaneous rate early
in the reaction (0 secs to 300 sec).
2. Using the [O2] data from the table show the calculation of the instantaneous rate late
in the reaction (2400 secs to 3000 secs).
3. Explain the relative values of the early instantaneous rate and the late instantaneous
rate.
Your Answer:
1.
.009-0/300-0 = .009/300 = .00003 = 3.0 x 10-5
