2024
ENGR 391 Final exam 2024 Questions
and answers Graded A+; Concordia
, Question 1 By checking the "yes" answer below I confirm
Complete that I have neither given nor received unauthorized aid to answer the questions of this assignment.
Not graded I agree to follow the rules in regard of online assignments as they are posted in the announcement forum of
this class and sent to me by email via moodle
Select one:
Yes I agree
No I do not agree
Question 2
Consider a continuous function f(x) such that f(a) < 0 and f(b) > 0. Choose the correct
Complete
statement
Marked out of 1.00
Select one:
There is no root in the interval [a, b]
There is exactly one root in the interval [a, b]
There is at least one root in the interval [a, b]
Not enough information provided in the question to make a conclusion
Question 3
You are approximating the solution of an initial value problem using a RK5 method.
Complete
If the global truncation error of the approximation produced by the IVP solver in t = 5 is 0.8
Marked out of 1.00
when using a step size h = 0.01, how much will be the global truncation error
when using a smaller step size of h = 0.001?
Answer: 0.08
/
ENGR 391 Final exam 2024 Questions
and answers Graded A+; Concordia
, Question 1 By checking the "yes" answer below I confirm
Complete that I have neither given nor received unauthorized aid to answer the questions of this assignment.
Not graded I agree to follow the rules in regard of online assignments as they are posted in the announcement forum of
this class and sent to me by email via moodle
Select one:
Yes I agree
No I do not agree
Question 2
Consider a continuous function f(x) such that f(a) < 0 and f(b) > 0. Choose the correct
Complete
statement
Marked out of 1.00
Select one:
There is no root in the interval [a, b]
There is exactly one root in the interval [a, b]
There is at least one root in the interval [a, b]
Not enough information provided in the question to make a conclusion
Question 3
You are approximating the solution of an initial value problem using a RK5 method.
Complete
If the global truncation error of the approximation produced by the IVP solver in t = 5 is 0.8
Marked out of 1.00
when using a step size h = 0.01, how much will be the global truncation error
when using a smaller step size of h = 0.001?
Answer: 0.08
/
