physics lab quiz 6 100% Correct!

In an isolated system two equal masses of the same geometry approach one another along the same line of action with equal but opposite velocity. The collision between them is perfectly INELASTIC. The linear momentum of the system BEFORE the collision equals - ANSWERzero True/ False Let us consider the floor to be zero level of gravitational potential energy. When the ball is fired, it has a non-zero potential energy with respect to the floor. -- Because the ball is above the floor, it DOES have a non-zero potential energy with respect to the floor. PE = m*g*h - ANSWERTrue A 248 gm steel ball is projected with a horizontal velocity of 4.0 m/s from a height of 1.50 m. What is the range of the ball? -- Since horizontal velocity is constant, horizontal distance = velocity*time. Time is 0.553 from the previous problem, then range = 4.0 m/s * .553 s = - ANSWER2.2m When you cock the gun and the ball is in the firing position, its velocity is zero. Thus, the initial energy of the ball is zero. Yet, after you pull the trigger, it has kinetic energy because it is moving. Where does this energy come from? -- The potential energy of the _____________ is converted to the _____________ kinetic energy - ANSWERspring, balls A 248 gm steel ball is projected with a horizontal velocity of 4.0 m/s. It has a vertical speed of 6.3 m/s the instant before it hits the ground. What is the kinetic energy the instant before it hits the ground? Hint: 1 g=1x10^-3 kg (exact) -- Kinetic energy has horizontal and vertical components Total KE =Vertical KE+Horizontal KE = 0.5*0.248*6.3^2 + 0.5*0.248*4.0^2= - ANSWER6.9J A 248 gm steel ball is projected with a horizontal velocity of 4.0 m/s from a height of 1.50 m. What is the vertical speed of the ball the instant before it hits the ground? (Use g = 9.80 m/s^2) -- Since V^2 = Vo^2 + 2a(X - Xo), then V = the square root of ( Vo^2 + 2a(X - Xo) = the square root of (0^2 + 2(9.80)(1.50) = - ANSWER5.42m/s