EKG STUDY MATERIAL FOR ADVENTHEALTH Exam Questions With Verified Answers

EKG STUDY MATERIAL FOR ADVENTHEALTH Exam Questions With Verified Answers 3 pacemakers of the heart - answer1. SA node 2. AV node 3. bundle branch intrinsic rate of SA node - answer60-100 bpm intrinsic rate of AV node - answer40-60 bpm intrinsic rate of bundle branches - answer20-40 bpm electrical pathway through the heart - answer1. normal conduction impulse originates in the *SA Node* 2. impulse travels to *AV Node* causing atrial depolarization (contraction) 3. AV Node slightly delays impulse then sends impulse to *Bundle of HIS* 4. then travels to *Bundle Branches* 5. impulse continues down to the *Purkinje Fibers* causing ventricular depolarization (contraction) P wave - answeratrial depolarization (contraction) PR interval - answerdelay of AV node to allow filling of ventricles QRS complex - answerventricular depolarization (contraction) ST interval - answerventricular repolarization (resting phase) QT interval - answerventricular depolarization and repolarization inversely related to the heart rate normally less than half of the length of the R-R interval T wave - answerventricular repolarization (resting phase) isoelectric line - answerThe baseline of the ECG / absence of electrical activity positive deflection - answera wave that exists above the isoelectric line negative deflection - answera wave that exists below the isoelectric line absolute refractory period - answercardiac cells will not respond to further stimulation myocardial cells will not contract electrical cells will not conduct relative refractory period - answervulnerable period cardiac cells can be stimulated to contract notched P wave - answer peaked P wave - answer inverted P wave - answer depressed ST segment - answerindicates myocardial ischemia elevated ST segment - answeracute myocardial infarction tall T wave - answerhyperkalemia inverted T wave - answermyocardial ischemia hyperacute T wave - answerSometimes the earliest presentation of MI 1 small box on EKG = - answer0.04 seconds