Stat st cs - Portage Online Summer
MATH 110 Module 3 Exam Questions and Answers- Portage
Learning
Module 3 Exam
Exam Page 1
Suppose A and B are two events with probabilities:
P(Ac )
=.40,P(B)=.45,P(A∪B)=.60.
Find the following:
a) P(A∩B).
p(anb) = p(a) + p(b) -
p(aub) p(a) = 1 - p(a^c)
p(a^c) = 0.40
1 - 0.40 = 0.60
p(a) = 0.60
0.60 + 0.45 - 0.60 = 0.45
P(AnB) = 0.45
b) P(A).
p(a) = 1 -
p(a^c) p(a^c)
= 0.40
1 - 0.40 = 0.60
P(A) = 0.60
c) P(Bc).
p(b) = 1 - p(b^c)
/
, Stat st cs - Portage Online Summer
rearranged to find p(b^c) = 1 - p(b)
1 - 0.45 = 0.55
/
MATH 110 Module 3 Exam Questions and Answers- Portage
Learning
Module 3 Exam
Exam Page 1
Suppose A and B are two events with probabilities:
P(Ac )
=.40,P(B)=.45,P(A∪B)=.60.
Find the following:
a) P(A∩B).
p(anb) = p(a) + p(b) -
p(aub) p(a) = 1 - p(a^c)
p(a^c) = 0.40
1 - 0.40 = 0.60
p(a) = 0.60
0.60 + 0.45 - 0.60 = 0.45
P(AnB) = 0.45
b) P(A).
p(a) = 1 -
p(a^c) p(a^c)
= 0.40
1 - 0.40 = 0.60
P(A) = 0.60
c) P(Bc).
p(b) = 1 - p(b^c)
/
, Stat st cs - Portage Online Summer
rearranged to find p(b^c) = 1 - p(b)
1 - 0.45 = 0.55
/
