Chapter 15 Test Questions with Verified Answers,100% CORRECT

Chapter 15 Test Questions with Verified Answers F - CORRECT ANSWER Potential energy is the energy of motion. T - CORRECT ANSWER Potential energy is due to the composition or position of an object. T - CORRECT ANSWER Energy exists in two basic forms, potential and kinetic energy. T - CORRECT ANSWER The law of conservation of energy states that energy is neither created nor destroyed. F - CORRECT ANSWER The symbol "h" is used to represent heat. T - CORRECT ANSWER Chemical potential energy is stored in the chemical bonds of a substance. T - CORRECT ANSWER Thermochemistry is the study of heat changes that accompany chemical reactions and phase changes. T - CORRECT ANSWER The heat required to vaporize one mole of a liquid is called its molar enthalpy of vaporization. F - CORRECT ANSWER The heat required to melt one mole of solid substance is called its molar enthalpy of melting. T - CORRECT ANSWER A spontaneous process is a physical or chemical change that occurs with no outside intervention. A - CORRECT ANSWER Calculate the energy in joules of a baked potato of 245 calories. (1 cal = 4.184 J) A. 1.03 x 10⁶ J B. 2.45 x 10⁵ J C. 1.03 x 10³ J D. 5.86 x 10⁴ J A - CORRECT ANSWER The __________ law of thermodynamics states that energy is neither created nor destroyed. A. first B. second C. third D. fourth A - CORRECT ANSWER The amount of energy required to raise the temperature of one gram of pure water by one degree Celsius is defined as: A. a calorie B. heat C. a joule D. a watt C - CORRECT ANSWER The SI unit of heat and energy is the __________. A. calorie B. heat C. joule D. watt C - CORRECT ANSWER What is the equation for calculating heat? A. c = mq∆T B. m = cq∆T C. q = cm∆T D. ∆T = cmq D - CORRECT ANSWER How much heat is evolved from 54.0 g glucose (C₆H₁₂O₆), according to the equation for calculating heat? C₆H₁₂O₆ + 6O₂ → 6H₂O + 6CO₂ + 2808kJ A. 0.842 kJ B. 8.42 kJ C. 84.2 kJ D. 842 kJ B - CORRECT ANSWER For a process, the enthalpy change of a system is 1.25 x 10⁵ J and the entropy change is 300.0 J/K. Calculate the free energy change of the system at 290 K. A. 8.7 x 10⁴ J B. 3.8 x 10⁴ J C. 1.2 x 10⁵ J D. 1.2 x 10⁴ J