Biochemistry Readiness Check II

Biochemistry Readiness Check II 5' UAC CGU 3' 3' UAC CGU 5' 3' TAC CGT 5' 5' TAC CGT 3' Correct! First, note that we are asked for a template/non-coding strand of DNA. DNA uses the base T where RNA uses the base U. Therefore, we can eliminate the two answers containing U because they must be RNA and we want DNA. Then, recall that any strands of nucleic acid that bind to each other (base pairing; A-T/U or C-G) must be each be running in opposite directions (antiparallel; a strand running 5'-->3 is bound to a strand running 3'-->5'). If any two strands of nucleic acid (for example 2 strands of DNA in a double helix) are complementary (A-T/U or C-G), the two strands must run IN OPPOSITE directions, 5'--->3' and 3'--->5'. 5' TTC GCC ATG CAT 3' 3' TTC GCC ATG CAT 5' Correct! All complementary base pairing must be antiparallel. The strand that is complementary to 5’ AAG CGG TAC GTA 3’ is 3' TTC GCC ATG CAT 5'. If we simply 'flip' the sequence, we get 5' TAC GTA CCG CTT 3'. Thus, both of these are the correct answers. 3' TTC GCC ATG CAT 5' 3' TTC GCC ATG CAT 5' 5’ AAG CGG TAC GTA 3’ 3' AAG CGG TAC GTA 5' is similar to the original sequence (5’ AAG CGG TAC GTA 3’), but its 5' and 3' ends are swapped. 5' TAC GTA CCG CTT 3' Correct! All complementary base pairing must be antiparallel. The strand that is complementary to 5’ AAG CGG TAC GTA 3’ is 3' TTC GCC ATG CAT 5'. If we simply 'flip' the sequence, we get 5' TAC GTA CCG CTT 3'. Thus, both of these are the correct answers. 3' TTC GCC ATG CAT 5' 3' TTC GCC ATG CAT 5' 5’ AAG CGG TAC GTA 3’ 3' AAG CGG TAC GTA 5' is similar to the original sequence (5’ AAG CGG TAC GTA 3’), but its 5' and 3' ends are swapped. 3' AAG CGG TAC GTA 5' 5’ ATG TAC GGC GAA 3' 3' ATG GCG TTC GAA 5' 5' AUG GCG UUC CUU 3' 5' AUG GCG UUC GAA 3' Correct! The coding strand and the mRNA both go in the same direction, but do not both contain Ts. 5' UTG GCG TTC GUU 3' Amino Acids RNA nucleotides DNA polymerase