Map Sapling Learning macmillar leaiming A female Drosophila fly is heterozygous for three
recessive pigmentation mutations called pl, wh, and tp pl is associated with purple eyes, wh is
associated with white body, and tp is associated with transparent wings. A geneticist crosses this
fly to a male purple, white, transparent fly and obtains 1000 progeny distributed as follows
Number Phenotype white wild type purple, transparent purple, white 50 204 52 201 transparent
white, transparent purple, white, transparent purple Number 203 43 202 45 Based on the data in
this table, which genes are linked? O pl and wh O wh and tp O pl and tp Calculate the distance
between the linked genes Number m.u
Solution
Hi,
Among the progeny , the wild type and homozygous mutant appear most of time. Among
recombinants the purple.white[201] and transparent[203] appeat most of the time. Hence the
genes purple and whte or pl and wh are linked.
The distance between them is calculated by knowing the recombination frequency.
RF = no .of pl,wh /total\\
= 201+
= 404/1000
= 0.404 = 40.4%
the distance= 40.4 mu
recessive pigmentation mutations called pl, wh, and tp pl is associated with purple eyes, wh is
associated with white body, and tp is associated with transparent wings. A geneticist crosses this
fly to a male purple, white, transparent fly and obtains 1000 progeny distributed as follows
Number Phenotype white wild type purple, transparent purple, white 50 204 52 201 transparent
white, transparent purple, white, transparent purple Number 203 43 202 45 Based on the data in
this table, which genes are linked? O pl and wh O wh and tp O pl and tp Calculate the distance
between the linked genes Number m.u
Solution
Hi,
Among the progeny , the wild type and homozygous mutant appear most of time. Among
recombinants the purple.white[201] and transparent[203] appeat most of the time. Hence the
genes purple and whte or pl and wh are linked.
The distance between them is calculated by knowing the recombination frequency.
RF = no .of pl,wh /total\\
= 201+
= 404/1000
= 0.404 = 40.4%
the distance= 40.4 mu
