100% de satisfacción garantizada Inmediatamente disponible después del pago Tanto en línea como en PDF No estas atado a nada
Buscado previamente por ti
CHEM 120 Final Exam (Version 3), CHEM 120: Introduction to General, Organic & Biological Chemistry with Lab, Verified and Correct Answers, Chamberlain College of Nursing.$15.49
Añadir al carrito
CHEM 120 Final Exam (Version 3), CHEM 120: Introduction to General, Organic & Biological Chemistry with Lab, Verified and Correct Answers, Chamberlain College of Nursing.
73 vistas 3 purchases
Grado
CHEM 120, Chamberlain college of Nursing
Institución
CHEM 120, Chamberlain College Of Nursing
CHEM 120 Final Exam (Version 3), CHEM 120: Introduction to General,
Organic & Biological Chemistry with Lab, Verified and Correct Answers, Chamberlain College of Nursing.
CHEM 120 Week 8 Final Exam
Course Number: CHEM120
Course Title: Introduction to General,Organic & Biological Chemistry with Lab
Correct Question & Answers
Secure high grade
Best feedback (rated) document by students
,CHEM 120: Final Exam
Multiple Choice
1. What is the molarity of a solution containing 55.8 g of MgCl2 dissolved in
1.00 L of solution?
M= moles of solute
liters of solution.
We are given the mass of our solute so we just need to convert
it to moles of MgCl2 via the MM.
55.9 g MgCl2 x 1 mol MgCl2 =0.586111 mols MgCl2
95.2119 g MgCl2
Now we can plug this into our equation for molarity
M = 0.587111 mols MgCl2 = 0.586 M MgCl2
`1.00 L
a) 55.8 M
b) 1.71 M
c) 0.586 M
d) 0.558 M
2. What is the mass in grams of Mg(NO3)2 present in 145 mL of a 0.150 M
solution of Mg(NO3)2?
We know the molarity and the volume, but we need to find the moles.
M= moles of solute
liters of solution. (volume)
First convert mLL.
145 mL 0.145 L (divide by 1000)
so we can solve this equation for moles.
Moles= (M) x (Volume)
moles Mg(NO3)2 = (0.150 moles) x (0.145 liters) = 0.02175 moles
Mg(NO3)2
liter
Now we can convert the number of moles to grams via the molar
mass of Mg(NO3)2.
3. When aqueous solutions of __________ are mixed, a precipitate forms.
To work out this problem, write molecular equations for each
reaction and, using your solubility chart, look at the products to
see if a precipitate is formed.
a) NiBr2 and AgNO3 : NiBr2(aq) + AgNO3(aq) NiNO3(aq) + 2
AgBr (s)
Nitrates are always soluble. Br- is usually soluble but when
paired with Ag, it forms a precipitate.
b) NaI and KBr- NaI (aq) + KBr(aq) NaBr (aq) + KI (aq)
Both of the products for this reaction are aqueous so no
reaction will occur.
c) K2SO4 and CrCl3 – 3 K2SO4 (aq) + 2 CrCl3(aq) 6 KCl (aq) +
Cr2(SO4)3 (aq)
Chlorides and sulfates are generally soluble and they both
form aqueous products so there is no reaction.
d) KOH and Sr(NO3)2 – KOH (aq) + Sr(NO3)2 (aq) KNO3(aq) +
Sr(OH)2 (aq)
Even though OH- groups are usually insoluble, Sr2+ is one of
the exceptions.
) Li2CO3 and CsI - Li2CO3 (aq) + CsI (aq) LiI(aq) + Cs2CO3 (aq)
Iodides
Carbonates are soluble when paired with alkali metals and so
are iodides. No reaction.
4. The net ionic equation for the formation of aqueous copper (II)
perchlorate which occurs when an aqueous solution of perchloric acid is
mixed with solid copper hydroxide is given by:
Perchloric acid: HClO4
Copper hydroxide: Cu(OH)2
Copper (II) perchlorate has the formula: Cu(ClO4)2
First write the balanced molecular equation:
2 HClO4 (aq) + Cu(OH)2 (s) Cu(ClO4)2 (aq) + 2 H2O (l)
Then write the ionic equation (breaking up the aqueous
reactants/products)
Los beneficios de comprar resúmenes en Stuvia estan en línea:
Garantiza la calidad de los comentarios
Compradores de Stuvia evaluaron más de 700.000 resúmenes. Así estas seguro que compras los mejores documentos!
Compra fácil y rápido
Puedes pagar rápidamente y en una vez con iDeal, tarjeta de crédito o con tu crédito de Stuvia. Sin tener que hacerte miembro.
Enfócate en lo más importante
Tus compañeros escriben los resúmenes. Por eso tienes la seguridad que tienes un resumen actual y confiable.
Así llegas a la conclusión rapidamente!
Preguntas frecuentes
What do I get when I buy this document?
You get a PDF, available immediately after your purchase. The purchased document is accessible anytime, anywhere and indefinitely through your profile.
100% de satisfacción garantizada: ¿Cómo funciona?
Nuestra garantía de satisfacción le asegura que siempre encontrará un documento de estudio a tu medida. Tu rellenas un formulario y nuestro equipo de atención al cliente se encarga del resto.
Who am I buying this summary from?
Stuvia is a marketplace, so you are not buying this document from us, but from seller HIGHSCORE. Stuvia facilitates payment to the seller.
Will I be stuck with a subscription?
No, you only buy this summary for $15.49. You're not tied to anything after your purchase.