, MOMENTUM AND IMPULSE
• NB STUDY ALL DEFINITONS
• ALL FORMULAE
P=mv
P= mvf – mvi
P= m(vf-vi)
M1Vi + M2Vi = M1Vf + M2Vf
M1Vi + M2Vi = (M1 + M2) Vf
Fnet t= p
Ek before = Ek after
[Ep + Ek] top = [Ep + Ek] bottom
, MOMENTUM (Kg.m.s^-1)
1. A motorcycle with a mass of 200kg moves at 12m.s-1 in a direction NW. Calcula
momentum of the motorcycle.
P=mv
P= 200 x 2
P= 200 x 12
p= 2400 kg.m.s6-1 NW
2. The momentum of an object is 350kg.m.s-1 in the direction 90 degrees. If the o
has a mass of 30 kg. Calculate the velocity of the object.
P=mv
350= 30v
V= 11,67 m.s^-1 in the direction 90 degrees
, MOMENTUM AND IMPULSE
3. A rubber ball with a mass of 0.8kg is dropped and hits the floor with an initial
downward velocity of 6m.s^-1. The ball bounces with a final upward velocity of 4
1. Calculate:
a) initial momentum
b) final momentum
c) change in momentum of the rubber ball
• NB STUDY ALL DEFINITONS
• ALL FORMULAE
P=mv
P= mvf – mvi
P= m(vf-vi)
M1Vi + M2Vi = M1Vf + M2Vf
M1Vi + M2Vi = (M1 + M2) Vf
Fnet t= p
Ek before = Ek after
[Ep + Ek] top = [Ep + Ek] bottom
, MOMENTUM (Kg.m.s^-1)
1. A motorcycle with a mass of 200kg moves at 12m.s-1 in a direction NW. Calcula
momentum of the motorcycle.
P=mv
P= 200 x 2
P= 200 x 12
p= 2400 kg.m.s6-1 NW
2. The momentum of an object is 350kg.m.s-1 in the direction 90 degrees. If the o
has a mass of 30 kg. Calculate the velocity of the object.
P=mv
350= 30v
V= 11,67 m.s^-1 in the direction 90 degrees
, MOMENTUM AND IMPULSE
3. A rubber ball with a mass of 0.8kg is dropped and hits the floor with an initial
downward velocity of 6m.s^-1. The ball bounces with a final upward velocity of 4
1. Calculate:
a) initial momentum
b) final momentum
c) change in momentum of the rubber ball
