Student Number : 62039415
Module : OPM 1501
Assignment : 3
Unique Number : 8497751
Due Date : 1 July 2019
, PART A
1.
0 0
1 ×3 -4 1
2 2
k 3
K = 3
Therefore 3×3 = 9
9-4 = 5
2.
Input value 0 1 2 k
Output value 0 -1 2 5
3.
0, 3 , 8 , 15 , 24 , 35 , 48 , 63 , 80 , 99, 120
3 5 7 9 11 13 15 17 19 20
2 2 2 2 2 2 2 2 2
Therefore, the eleventh for this sequence is 12