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Exam (elaborations) TEST BANK FOR Control Systems Engineering 7th Edition By Norman S. Nice (Solutions Manual to ISBN 9781118170519)

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Exam (elaborations) TEST BANK FOR Control Systems Engineering 7th Edition By Norman S. Nice (Solutions Manual to ISBN 0519) O N E Introduction ANSWERS TO REVIEW QUESTIONS 1. Guided missiles, automatic gain control in radio receivers, satellite tracking antenna 2. Yes - power gain, remote control, parameter conversion; No - Expense, complexity 3. Motor, low pass filter, inertia supported between two bearings 4. Closed-loop systems compensate for disturbances by measuring the response, comparing it to the input response (the desired output), and then correcting the output response. 5. Under the condition that the feedback element is other than unity 6. Actuating signal 7. Multiple subsystems can time share the controller. Any adjustments to the controller can be implemented with simply software changes. 8. Stability, transient response, and steady-state error 9. Steady-state, transient 10. It follows a growing transient response until the steady-state response is no longer visible. The system will either destroy itself, reach an equilibrium state because of saturation in driving amplifiers, or hit limit stops. 11. Transient response 12. True 13. Transfer function, state-space, differential equations 14. Transfer function - the Laplace transform of the differential equation State-space - representation of an nth order differential equation as n simultaneous first-order differential equations Differential equation - Modeling a system with its differential equation SOLUTIONS TO PROBLEMS 1. Five turns yields 50 v. Therefore K = 50 volts 5 x 2π rad = 1.59 2 Chapter 1: Introduction 2. Thermostat Amplifier and valves Heater Temperature difference Voltage difference Fuel flow Actual temperature Desired temperature + - 3. Desired roll angle Input voltage + - Pilot controls Aileron position control Error voltage Aileron position Aircraft dynamics Roll rate Integrate Roll angle Gyro Gyro voltage 4. Speed Error voltage Desired speed Input voltage + - transducer Amplifier Motor and drive system Actual speed Voltage proportional to actual speed Dancer position sensor Dancer dynamics 5. Desired power Power Error voltage Input voltage + - Transducer Amplifier Motor and drive system Voltage proportional to actual power Rod position Reactor Actual power Sensor & transducer Solutions to Problems 3 6. Desired student population + - Administration Population error Desired student rate Admissions Actual student rate + - Graduating and drop-out rate Net rate of influx Integrate Actual student population 7. Desired volume + - Transducer Volume control circuit Voltage proportional to desired volume Volume error Radio Voltage representing actual volume Actual volume - + Transducer - Speed Voltage proportional to speed Effective volume 4 Chapter 1: Introduction 8. a. R +V -V Differential amplifier Desired level - + Power amplifier Actuator Valve Float Fluid input Drain Tank R +V -V b. Desired level Amplifiers Actuator and valve Flow rate in Integrate Actual level Flow rate out Potentiometer + - + Drain Potentiometer Float - voltage in voltage out Displacement Solutions to Problems 5 9. Desired force Transducer Amplifier Valve Actuator and load Tire Load cell Actual + force - Current Displacement Displacement 10. Commanded blood pressure Vaporizer Patient Actual blood + pressure - Isoflurane concentration 11. + - Controller & motor Grinder Force Feed rate Integrator Desired depth Depth 12. + - Coil circuit Solenoid coil & actuator Coil current Force Armature & spool dynamics Desired position Depth Transducer Coil voltage LVDT 13. a. L di dt + Ri = u(t) 6 Chapter 1: Introduction b. Assume a steady-state solution iss = B. Substituting this into the differential equation yields RB = 1, from which B = 1 R . The characteristic equation is LM + R = 0, from which M = - R L . Thus, the total solution is i(t) = Ae-(R/L)t + 1 R . Solving for the arbitrary constants, i(0) = A + 1 R = 0. Thus, A = - 1 R . The final solution is i(t) = 1 R -- 1 R e-(R/L)t = 1 R (1 − e−( R/ L)t ). c. 14. a. Writing the loop equation, Ri + L di dt + 1 C ∫ idt + vC (0) = v(t) b. Differentiating and substituting values, d2i dt 2 + 2 di dt + 30i = 0 Writing the characteristic equation and factoring, M2 + 2 M+ 30 = M+ 1 + 29 i M +1 - 29 i . The general form of the solution and its derivative is i = e-t cos 29 t A + B sin 29 t e- t di = - A + 29 B e-t cos 29 t - 29 A + B e- t sin 29 t dt Using i(0) = 0; di dt (0) = vL(0) L = 1 L = 2 i 0 = A =0 di dt (0) = −A + 29B=2 Thus, A = 0 and B = 2 29 . The solution

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Subido en
7 de noviembre de 2021
Número de páginas
650
Escrito en
2021/2022
Tipo
Examen
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, O N E

Introduction
ANSWERS TO REVIEW QUESTIONS
1. Guided missiles, automatic gain control in radio receivers, satellite tracking antenna
2. Yes - power gain, remote control, parameter conversion; No - Expense, complexity
3. Motor, low pass filter, inertia supported between two bearings
4. Closed-loop systems compensate for disturbances by measuring the response, comparing it to
the input response (the desired output), and then correcting the output response.
5. Under the condition that the feedback element is other than unity
6. Actuating signal
7. Multiple subsystems can time share the controller. Any adjustments to the controller can be
implemented with simply software changes.
8. Stability, transient response, and steady-state error
9. Steady-state, transient
10. It follows a growing transient response until the steady-state response is no longer visible. The
system will either destroy itself, reach an equilibrium state because of saturation in driving
amplifiers, or hit limit stops.
11. Transient response
12. True
13. Transfer function, state-space, differential equations
14. Transfer function - the Laplace transform of the differential equation
State-space - representation of an nth order differential equation as n simultaneous first-order
differential equations
Differential equation - Modeling a system with its differential equation



SOLUTIONS TO PROBLEMS
50 volts
1. Five turns yields 50 v. Therefore K = = 1.59
5 x 2π rad

,2 Chapter 1: Introduction




2.


Desired Temperature Voltage Actual
Fuel
temperature difference difference temperature
flow

+ Amplifier and
Thermostat Heater
valves
-



3.


Desired Input Error Aileron Roll Roll
roll voltage voltage position rate angle
angle
+ Aileron Aircraft
Pilot Integrate
position dynamics
controls
control
-

Gyro
Gyro voltage


4.
Input
Speed
Desired voltage Actual
Error Motor
speed speed
transducer
+ voltage and
Amplifier drive
system
-
Dancer
Dancer
position
Voltage dynamics
sensor
proportional
to actual speed

5.

Input Power Rod
voltage Error position
Desired voltage Motor Actual
power and power
Transducer
+ Amplifier drive Reactor
system
-

Sensor &
Voltage transducer
proportional
to actual power

, Solutions to Problems 3




6.
Graduating
and
drop-out
rate
Desired Actual
Desired Population student Actual
Net rate student
student error rate student - of influx population
population + rate +
Administration Admissions Integrate

-



7.
Voltage Voltage
proportional representing
to desired Volume actual volume Actual
Desired volume error volume
volume + Volume
Transducer Radio
control circuit
-
Effective
volume
+
Voltage
- proportional
to speed

Transducer
-

Speed
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