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Biochemistry Readiness Check 1B | Biochemistry Readiness Check 2020

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Biochemistry Readiness Check 1B The 2nd OA Readiness Check is designed to give you additional practice with new assessment- style questions to help prepare for success on the OA. Thus, please try to mimic exam-like conditions by taking the test in one <2 hr sitting without any study aids apart from your whiteboard/scrap paper. Note: Responses cannot be edited. You will be able to see the results and feedback after submitting the test. A score of 70% is required for OA approval. If you score below 70%, please speak with a Course Instructor via appointment to discuss next steps prior to retaking this test. Points: 53/67 1 What is the complementary sequence to 3’ CAG TAA CAA 5’? * (0/1 Point) 5' TTG TTA CTG 3 The correct answer is 3' TTG TTA CTG 5'. Remember complementary means “Matching or Pairing” You have to remember to pay attention to your numbers as well as your letters (A-T, G-C, 5'-3'). The correct answer is 3’ CAG TAA CAA 5’ (original sequence) 5’ GTC ATT GTT 3’ (complementary sequence) But we asked for it in the 3’ direction, so mirror answer to give correct answer: 3’ TTG TTA CTG 5’ If you chose 5' GTC ATT GTT 3', this sequence is just the mirror of the original 12/12/2020 Biochemistry Readiness Check 1B sequence provided, and is not its complementary sequence. No "pairing" was done to get this sequence. 3’ GTC ATT GTT 5’ 3’ GTT ATT GTC 5’ 3' TTG TTA CTG 5 2 Which amino acid sequence would result from this Coding DNA strand? 3’ TAC GTT AAC 5’? * (0/1 Point) Gln Leu His 12/12/2020 Biochemistry Readiness Check 1B Met Gln Leu The correct answer is Gln Leu His. We are starting at the coding strand, and have to remember the relationship between coding DNA and mRNA. These two strands are non-complementary and parallel. So we copy the coding strand , change T ---> U, and then write the mRNA sequence: 3’ TAC GTT AAC 5’ coding 3’ UAC GUU AAC 5’ mRNA Mirror by changing orientation: 5’ CAA UUG CAU 3’ Read chart Gln Leu His (chart is in direction of 5' ---> 3') If you chose Met Gln Leu, this answer is incorrect because this is the amino acid sequence that results from the mRNA 5' AUG CAA UUG 3' which would have been complementary to the given coding strand. Coding DNA is non- complementary and parallel to mRNA. Ile Asp Val Gln Ile Met 3 Which amino acid sequence would be made from this template DNA strand? 5’ AGT TAT AAC 3’? * (0/1 Point) 12/12/2020 Biochemistry Readiness Check 1B Met Leu Thr Val Ile Thr Ser Tyr Asn The correct answer is Val Ile Thr because 5’ AGT TAT AAC 3’ template is complementary and antiparallel so 3’ UCA AUA UUG 5’ but it is in the wrong orientation, so mirror 5’ GUU AUA ACU 3’ and read the chart Val Ile Thr Gln Tyr 12/12/2020 Biochemistry Readiness Check 1B 5 Which ingredients/molecules are required to set up a polymerase chain reaction? Select all that apply. * (0/1 Point) Amino Acids RNA nucleotides DNA polymerase Correct! In PCR, a DNA sample is separated into single strands and incubated with DNA polymerase, deoxynucleotides (dNTPs), and two short DNA primers whose sequences flank the DNA segment of interest and thus define the region to be amplified. Recall from the section on DNA replication that DNA polymerase needs a primer to begin DNA synthesis. This requirement means the primers will direct the DNA polymerase to only synthesize complementary strands of the target DNA. DNA nucleotides Correct! In PCR, a DNA sample is separated into single strands and incubated with DNA polymerase, deoxynucleotides (dNTPs), and two short DNA primers whose sequences flank the DNA segment of interest and thus define the region to be amplified. Recall from the section on DNA replication that DNA polymerase needs a primer to begin DNA synthesis. This requirement means the primers will direct the DNA polymerase to only synthesize complementary strands of the target DNA. Template DNA DNA Primers Correct! In PCR, a DNA sample is separated into single strands and incubated with DNA polymerase, deoxynucleotides (dNTPs), and two short DNA primers whose sequences flank the DNA segment of interest and thus define the region to be amplified. Recall from the section on DNA replication that DNA polymerase needs a primer to begin DNA synthesis. This requirement means the primers will direct the DNA polymerase to only synthesize complementary strands of the target DNA. Ribosomes RNA Primers 12/12/2020 Biochemistry Readiness Check 1B 5 Assuming 100%

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Western Governor\'S University
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Institución
Western Governor\'S University
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BIOCHEMISTRY

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Subido en
4 de septiembre de 2021
Número de páginas
48
Escrito en
2020/2021
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