ELECTRICAL LOAD ANALYSIS
EXAMINATION WITH ACTUAL QUESTIONS
AND VERIFIED ANSWERS, PLUS
EXPLAINED RATIONALES/EXPERT
VERIFIED FOR GUARANTEED 100% PASS
2026/LATEST UPDATE/INSTANT
DOWNLOAD PDF
Questions 1–10
1. A 120/240-volt, single-phase dwelling has the following calculated
connected loads: general lighting and receptacles = 4,500 VA,
small-appliance circuits = 3,000 VA, laundry circuit = 1,500 VA,
range = 12,000 VA, and electric dryer = 5,000 VA. Before
applying any applicable demand factors, what is the total
connected load?
A. 21,000 VA
B. 24,500 VA
C. 26,000 VA
D. 28,500 VA
Answer: C. 26,000 VA
Rationale: The connected load is the arithmetic sum of all listed loads:
4,500 + 3,000 + 1,500 + 12,000 + 5,000 = 26,000 VA. Demand factors
are applied afterward where permitted; they do not change the initial
connected-load total.
2. A 120-volt single-phase circuit supplies a continuous load of 1,800
VA. If the continuous-load portion must be included at 125% for
sizing purposes, what minimum circuit ampacity is required before
considering conductor derating or other adjustments?
1
,A. 15 A
B. 18.75 A
C. 20 A
D. 22.5 A
Answer: C. 20 A
Rationale: The adjusted load is 1,800 × 1.25 = 2,250 VA. At 120 V,
current is 2,250 ÷ 120 = 18.75 A. The next standard circuit rating
capable of carrying the calculated load is 20 A, assuming the
applicable rules permit the selected conductor and overcurrent device.
3. A three-phase, 480-volt motor has a calculated electrical input load
of 60 kW at a power factor of 0.80. Approximately what line
current does the load draw?
A. 72.2 A
B. 90.2 A
C. 108.3 A
D. 125.0 A
Answer: B. 90.2 A
Rationale: For a balanced three-phase load, I = P ÷ (√3 × V × PF).
Therefore, I = 60,000 ÷ (1.732 × 480 × 0.80) ≈ 90.2 A. The power
factor is critical because lower power factor increases current for the
same real power.
4. An electrical engineer is analyzing a facility with 400 kW of real
power and a measured power factor of 0.75. What is the
approximate apparent power?
A. 300 kVA
B. 400 kVA
2
,C. 533 kVA
D. 600 kVA
Answer: C. 533 kVA
Rationale: Apparent power is S = P ÷ PF. Thus, 400 kW ÷ 0.75 =
533.3 kVA. This illustrates why transformer, feeder, and generator
sizing cannot be based solely on real power when the power factor is
below unity.
5. A facility has a 1,000 kVA transformer operating at 70% of its
rated apparent power. Approximately how much apparent load is
presently being supplied?
A. 570 kVA
B. 650 kVA
C. 700 kVA
D. 770 kVA
Answer: C. 700 kVA
Rationale: Transformer loading is expressed as the percentage of its
kVA capacity being used. Therefore, 1,000 kVA × 0.70 = 700 kVA.
This represents apparent load, not necessarily real power, because the
actual kW depends on the facility's power factor.
6. A 208-volt, three-phase panel supplies a balanced load of 36 kVA.
What is the approximate line current?
A. 50 A
B. 75 A
C. 100 A
D. 125 A
Answer: C. 100 A
3
, Rationale: I = S ÷ (√3 × V). Therefore, I = 36,000 ÷ (1.732 × 208) ≈
99.9 A. The calculated current is approximately 100 A.
7. A commercial building has a connected lighting load of 40 kVA.
After an applicable demand factor reduces the calculated lighting
load to 80% of connected load, what is the resulting demand load?
A. 24 kVA
B. 30 kVA
C. 32 kVA
D. 38 kVA
Answer: C. 32 kVA
Rationale: The demand load is 40 kVA × 0.80 = 32 kVA. A demand
factor recognizes that connected loads are not necessarily operating
simultaneously at full rated capacity.
8. A feeder supplies 10 kW of resistance heating and 20 kW of motor
load. Assuming both loads operate simultaneously at unity power
factor, what is the combined real power?
A. 20 kW
B. 25 kW
C. 30 kW
D. 35 kW
Answer: C. 30 kW
Rationale: Real powers operating simultaneously are additive.
Therefore, 10 kW + 20 kW = 30 kW. If the motor had a power factor
below unity, the apparent-power calculation would need additional
consideration.
4
EXAMINATION WITH ACTUAL QUESTIONS
AND VERIFIED ANSWERS, PLUS
EXPLAINED RATIONALES/EXPERT
VERIFIED FOR GUARANTEED 100% PASS
2026/LATEST UPDATE/INSTANT
DOWNLOAD PDF
Questions 1–10
1. A 120/240-volt, single-phase dwelling has the following calculated
connected loads: general lighting and receptacles = 4,500 VA,
small-appliance circuits = 3,000 VA, laundry circuit = 1,500 VA,
range = 12,000 VA, and electric dryer = 5,000 VA. Before
applying any applicable demand factors, what is the total
connected load?
A. 21,000 VA
B. 24,500 VA
C. 26,000 VA
D. 28,500 VA
Answer: C. 26,000 VA
Rationale: The connected load is the arithmetic sum of all listed loads:
4,500 + 3,000 + 1,500 + 12,000 + 5,000 = 26,000 VA. Demand factors
are applied afterward where permitted; they do not change the initial
connected-load total.
2. A 120-volt single-phase circuit supplies a continuous load of 1,800
VA. If the continuous-load portion must be included at 125% for
sizing purposes, what minimum circuit ampacity is required before
considering conductor derating or other adjustments?
1
,A. 15 A
B. 18.75 A
C. 20 A
D. 22.5 A
Answer: C. 20 A
Rationale: The adjusted load is 1,800 × 1.25 = 2,250 VA. At 120 V,
current is 2,250 ÷ 120 = 18.75 A. The next standard circuit rating
capable of carrying the calculated load is 20 A, assuming the
applicable rules permit the selected conductor and overcurrent device.
3. A three-phase, 480-volt motor has a calculated electrical input load
of 60 kW at a power factor of 0.80. Approximately what line
current does the load draw?
A. 72.2 A
B. 90.2 A
C. 108.3 A
D. 125.0 A
Answer: B. 90.2 A
Rationale: For a balanced three-phase load, I = P ÷ (√3 × V × PF).
Therefore, I = 60,000 ÷ (1.732 × 480 × 0.80) ≈ 90.2 A. The power
factor is critical because lower power factor increases current for the
same real power.
4. An electrical engineer is analyzing a facility with 400 kW of real
power and a measured power factor of 0.75. What is the
approximate apparent power?
A. 300 kVA
B. 400 kVA
2
,C. 533 kVA
D. 600 kVA
Answer: C. 533 kVA
Rationale: Apparent power is S = P ÷ PF. Thus, 400 kW ÷ 0.75 =
533.3 kVA. This illustrates why transformer, feeder, and generator
sizing cannot be based solely on real power when the power factor is
below unity.
5. A facility has a 1,000 kVA transformer operating at 70% of its
rated apparent power. Approximately how much apparent load is
presently being supplied?
A. 570 kVA
B. 650 kVA
C. 700 kVA
D. 770 kVA
Answer: C. 700 kVA
Rationale: Transformer loading is expressed as the percentage of its
kVA capacity being used. Therefore, 1,000 kVA × 0.70 = 700 kVA.
This represents apparent load, not necessarily real power, because the
actual kW depends on the facility's power factor.
6. A 208-volt, three-phase panel supplies a balanced load of 36 kVA.
What is the approximate line current?
A. 50 A
B. 75 A
C. 100 A
D. 125 A
Answer: C. 100 A
3
, Rationale: I = S ÷ (√3 × V). Therefore, I = 36,000 ÷ (1.732 × 208) ≈
99.9 A. The calculated current is approximately 100 A.
7. A commercial building has a connected lighting load of 40 kVA.
After an applicable demand factor reduces the calculated lighting
load to 80% of connected load, what is the resulting demand load?
A. 24 kVA
B. 30 kVA
C. 32 kVA
D. 38 kVA
Answer: C. 32 kVA
Rationale: The demand load is 40 kVA × 0.80 = 32 kVA. A demand
factor recognizes that connected loads are not necessarily operating
simultaneously at full rated capacity.
8. A feeder supplies 10 kW of resistance heating and 20 kW of motor
load. Assuming both loads operate simultaneously at unity power
factor, what is the combined real power?
A. 20 kW
B. 25 kW
C. 30 kW
D. 35 kW
Answer: C. 30 kW
Rationale: Real powers operating simultaneously are additive.
Therefore, 10 kW + 20 kW = 30 kW. If the motor had a power factor
below unity, the apparent-power calculation would need additional
consideration.
4
