Escrito por estudiantes que aprobaron Inmediatamente disponible después del pago Leer en línea o como PDF ¿Documento equivocado? Cámbialo gratis 4,6 TrustPilot
logo-home
Document preview thumbnail
Vista previa 3 fuera de 28 páginas
Examen

Portage Learning CHEM 103 General Chemistry I Module 6 Exam (PDF) | 2026 Exam Questions and Answers + Rationales | Study Guide | 100% Correct

Document preview thumbnail
Vista previa 3 fuera de 28 páginas

INSTANT PDF DOWNLOAD – Comprehensive Portage Learning CHEM 103 General Chemistry I Module 6 Exam study guide featuring practice questions, verified answers, and detailed answer rationales. Covers liquids and solids, phase changes, phase diagrams, solutions and solubility, homogeneous and heterogeneous mixtures, concentration units (mass percent, molarity, and molality), colligative properties, electrolyte solutions, ionization, conductivity, molar mass calculations, and solution chemistry designed to help students prepare confidently for the CHEM 103 Module 6 examination. Module 6 emphasizes solution chemistry, phase behavior, and colligative properties.

Vista previa del contenido

PORTAGE LEARNING CHEM 103 GENERAL CHEMISTRY I
MODULE 6 EXAM (PDF) | 2026 EXAM QUESTIONS AND
ANSWERS + RATIONALES | STUDY GUIDE | 100% CORRECT
1. Which of the following is NOT a fundamental unit of measurement in the metric system?
A) Meter
B) Gram
C) Fahrenheit
D) Liter
Correct Answer: C) Fahrenheit
Rationale: The fundamental metric units for length, mass, and volume are the meter, gram, and
liter. Fahrenheit is a unit of temperature in the imperial system, while Celsius and Kelvin are the
metric units .
2. A 5.00 g sample of an unknown metal has a volume of 2.50 mL. What is its density?
A) 0.500 g/mL
B) 2.00 g/mL
C) 7.50 g/mL
D) 12.5 g/mL
Correct Answer: B) 2.00 g/mL
Rationale: Density is mass divided by volume (D = m/v). Therefore, 5.00 g / 2.50 mL = 2.00
g/mL . This value can be used to help identify the metal.
3. Which of the following is an example of a chemical change?
A) Dissolving sugar in water
B) Boiling water to steam
C) Rusting of an iron nail
D) Breaking a glass beaker
Correct Answer: C) Rusting of an iron nail
Rationale: Rusting is a chemical change because it creates a new substance (iron oxide).
Dissolving sugar, boiling water, and breaking glass are physical changes that do not alter the
chemical composition .
4. How many significant figures are in the measurement 0.003040?
A) 4
B) 5
C) 6
D) 7
Correct Answer: A) 4

,Rationale: The leading zeros are not significant. The digits 3, 0, 4, and 0 are significant. The zero
between the 3 and 4 is significant, and the trailing zero is significant because the number
contains a decimal point .
5. Convert 25°C to Kelvin.
A) 25 K
B) 248 K
C) 298 K
D) 248 K
Correct Answer: C) 298 K
Rationale: The conversion formula is K = °C + 273. Therefore, 25 + 273 = 298 K .
6. Convert 98.6°F to Celsius.
A) 37.0°C
B) 210°C
C) 32.0°C
D) 104°C
Correct Answer: A) 37.0°C
Rationale: The conversion formula is °C = (°F - 32) / 1.8. Therefore, (98.6 - 32) / 1.8 = 37.0°C .
7. A 2.50 L sample of a gas at 25°C is heated to 75°C at constant pressure. What is the new
volume?
A) 0.833 L
B) 7.50 L
C) 2.92 L
D) 2.14 L
Correct Answer: C) 2.92 L
Rationale: Charles's Law states V1/T1 = V2/T2. Temperatures must be in Kelvin. T1 = 298 K,
T2 = 348 K. V2 = (2.50 L)(348 K) / 298 K = 2.92 L .
8. A gas occupies 10.0 L at a pressure of 2.00 atm. If the volume is decreased to 5.00 L at
constant temperature, what is the new pressure?
A) 0.500 atm
B) 1.00 atm
C) 2.00 atm
D) 4.00 atm
Correct Answer: D) 4.00 atm
Rationale: Boyle's Law states P1V1 = P2V2. Therefore, (2.00 atm)(10.0 L) = P2(5.00 L) → P2 =
4.00 atm .

, 9. Which of the following functional groups is characteristic of a carboxylic acid?
A) -OH
B) -COOH
C) -NH2
D) -COH
Correct Answer: B) -COOH
Rationale: The carboxyl group (-COOH) contains both a carbonyl and a hydroxyl group and is
the defining functional group of carboxylic acids .
10. A polymer made from many monomers of glucose linked together is called a:
A) Nucleic acid
B) Protein
C) Polypeptide
D) Polysaccharide
Correct Answer: D) Polysaccharide
Rationale: Polysaccharides are polymers composed of monosaccharide (sugar) monomers, such
as glucose. Starch and cellulose are common examples found in biological systems .
11. The primary function of carbohydrates in a biological system is:
A) Catalyzing biochemical reactions
B) Storing energy
C) Encoding genetic information
D) Transporting lipids
Correct Answer: B) Storing energy
Rationale: Carbohydrates are primarily used as a source of energy. They can be broken down to
release glucose, which is used in cellular respiration to produce ATP .
12. The intermolecular forces that are most important in holding nonpolar molecules like n-
octane (C8H18) in a liquid state are:
A) Hydrogen bonds
B) Ionic bonds
C) Van der Waals interactions
D) Covalent bonds
Correct Answer: C) Van der Waals interactions
Rationale: n-octane is a nonpolar molecule, so it does not form hydrogen bonds (which require
O-H or N-H bonds) or ionic bonds. The primary intermolecular attractions are the weak,
temporary dipole-induced dipole forces known as Van der Waals or London dispersion forces .
13. Which type of reaction involves the breakdown of a polymer into its monomers by the
addition of water?
A) Condensation

Información del documento

Subido en
28 de julio de 2026
Número de páginas
28
Escrito en
2025/2026
Tipo
Examen
Contiene
Preguntas y respuestas
$15.99

¿Documento equivocado? Cámbialo gratis Dentro de los 14 días posteriores a la compra y antes de descargarlo, puedes elegir otro documento. Puedes gastar el importe de nuevo.
Escrito por estudiantes que aprobaron
Inmediatamente disponible después del pago
Leer en línea o como PDF

Vendido
0
Seguidores
0
Artículos
104
Última venta
-


Por qué los estudiantes eligen Stuvia

Creado por compañeros estudiantes, verificado por reseñas

Calidad en la que puedes confiar: escrito por estudiantes que aprobaron y evaluado por otros que han usado estos resúmenes.

¿No estás satisfecho? Elige otro documento

¡No te preocupes! Puedes elegir directamente otro documento que se ajuste mejor a lo que buscas.

Paga como quieras, empieza a estudiar al instante

Sin suscripción, sin compromisos. Paga como estés acostumbrado con tarjeta de crédito y descarga tu documento PDF inmediatamente.

Student with book image

“Comprado, descargado y aprobado. Así de fácil puede ser.”

Alisha Student

Preguntas frecuentes