CLS 380 – C10 (Exam 2) Questions and Answers with Detailed Solutions | Comprehensive Study Guide | Latest 2026 Edition

CLS 380 - C10 (EXAM 2) QUESTIONS AND
hh hh hh hh hh hh hh



ANSWERS 100% PASS
hh hh hh




Precipitation hh - hh correct hh answer--
combining hh soluble h h antigen h h with h h soluble h h antibody h h to hh make hh visible, h h insoluble h h complexes


Agglutination hh - hh correct h h answer--
when hh particulate h h antigens h h aggregate h h to h h form h h larger h h complexes h h when h h a h h specific h h antibody h h is
h h present




Affinity hh - hh correct h h answer--
initial hhforce hhof hhattraction hhexisting hhbetween hha hhsingle hhFab hhsite hhon hhan hhantibody hhmolecule hhand hha
hhsingle hhepito h h pe hhon hhcorresponding hhantigen



-
strength hhof hhattraction hhdepends hhon hhspecificity hhof hhantibody hhfor hha hhparticular hhantigen hh(how hhwell
hhthey hhfit hhtog h h ether)



- h h higher h h affinity h h = h h more h h sensitivity


Cross-Reactivity hh - hh correct hh answer--
when hh antibodies h h react h h with h h antigens h h resembling hh the h h original h h antigen h h (that h h induced h h antibody
h h production)




Avidity hh- hhcorrect hhanswer-- hhsum hhof hhaffinities hhof hhall hhindividual
hhantibody- hhantigen hhcombining hhsites hh(overall hhstrength hhof hhthe hhbinding)



- force hh that h h keeps h h the h h molecules h h together h h after h h binding h h happens
- more h h bonds h h formed h h = h h higher h h avidity h h (ex. h h IgM h h > h h IgG)
- can h h compensate h h for h h low h h affinity


Law hhof hhMass hhAction hh- hhcorrect h h answer-- hhfree hhreactants hhare hhin hhequilibrium hhwith hhbound
hh reactants h h K hh= hh(AgAb)/(Ab)(Ag)
- with hhincreased h h avidity, hh K hh increases, h h (Ab)(Ag) h h decreases hh because hh they h h can't h h dissociate hh as h h easily


What hhare hhthe hhideal hhconditions hhin hhthe hhlab hhfor hhaffinity hhand hhavidity? hhWhy? hh-
hhcorrect hhanswer-- h h high hhaffinity hhand hhhigh hhavidity



- forms h h more h h antigen-antibody h h complexes hh and h h test h h is hh more h h sensitive

, Optimal hhPrecipitation hh- hhcorrect hhanswer-- hhwhen hhrelative hhamounts hhof hhantigen hhand
hhantibody- hhbinding hhsites hhare hhequal




Zone hh of h h Antibody h h Excess h h - hh correct h h answer--
higher hh antibody h h concentration h h compared h h to h h antigen h h concentration
- small h h immune h h complexes h h with h h little/no h h precipitation


Zone hh of h h Antigen hh Excess h h - h h correct h h answer--
higher hh antigen h h concentration h h compared h h to h h antibody h h concentration
- little/no hh precipitation


Zone hh of h h Equivalence h h - h h correct h h answer--
number h h of h h multivalent h h sites h h of h h antigen h h and h h antibody h h are h h about h h equal
-
precipitation h h happens h h from h h random, h h reversible hhreactions h h of h h antibodies h h binding hhto h h more hhthan
h h one h h antige hhn hh(forms hhlattice)




Prozone hh - h h correct h h answer-- h h when h h there h h is h h a h h large hh antibody h h excess
- antigen h h combines h h with h h only h h 1-2 h h antibody h h molecules
- no h h cross-linkages h h are hh formed
- undetectable hh precipitation


Postzone h h - hh correct h h answer-- h h large h h antigen h h excess
- every h h available h h antibody h h site h h is h h bound h h to h h single h h antigen
- no h h cross h h linkages h h are h h formed
- no h h lattice h h network hh formed, h h no h h precipitation


How h h can h h we h h fix h h a h h false-negative h h result h h in h h the h h prozone? h h - h h correct h h answer--
diluting hhout hhthe hhantibody hhuntil hhequivalence hhis hhreached hhand hhperforming hhthe hhtest hhagain hh(can
hhproduce hha hhpo h h sitive hhresult)