Choose the correct values for the APA style summary.
We computed a single sample t test and d to compare the sample mean (M = _____, SD
= _____) to _____, t(_____) = _____, p = _____, d = _____.
Give this one a try later!
M= 5.38
SD=.81
to 5
t(29)= 2.57
p=0.02
d=.47
Create a point and whisker plot. According to this graph, what is the highest score in
the data set?
A. 5.7
,B. 5.0
C. 5.3
Give this one a try later!
A. 5.7
Choose the correct two-tailed null hypothesis.
A. Walking will improve mood ratings.
B. Walking will not improve mood ratings.
C. Walking will influence mood ratings.
D. Walking will not influence mood ratings.
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D. Walking will not influence mood ratings.
Choose the correct APA style summary statement.
A. An independent t test was conducted to compare mood ratings for people in a
walking program (M = 4.04, SD = .74) to those in the control group (M = 3.66, SD = .96),
t (148) = 5.65, p = .007, d = .45.
B. An independent t test was conducted to compare mood ratings for people in a
walking program (M = 4.04, SD = .74) to those in the control group (M = 3.66, SD = .96),
t (138.95) = 2.73, p = .007, d = .45.
C. An independent t test was conducted to compare mood ratings for people in a
walking program (M = 4.04, SD = .74) to those in the control group (M = 3.66, SD = .96),
t (138.95) = 5.65, p = .007, d = .45.
D. An independent t test was conducted to compare mood ratings for people in a
, walking program (M = 4.04, SD = .74) to those in the control group (M = 3.66, SD = .96),
t (148) = 5.65, p = .019, 95% CI [.11, .66], d = .45, [.12, .77].
Give this one a try later!
B. An independent t test was conducted to compare mood ratings for
people in a walking program (M = 4.04, SD = .74) to those in the control
group (M = 3.66, SD = .96), t (138.95) = 2.73, p = .007, d = .45.
Independent t-test
Does taking a walk during a lunch break help improve the moods of workers? A
researcher team tested this hypothesis by conducting a study with 150 employees
working at a clothing factory. All employees at the factory take a one hour break for
lunch. What they did during that hour was determined by which experimental
condition they were randomly assigned to. In the experimental condition, employees
spent half of their lunch hour walking on an indoor track at the manufacturing plant. In
the control condition, employees did not go on a walk during their lunch break. After
three months, all employees completed a measure of mood called the PANAS-SF.
The PANAS consists of ten positive words (e.g., enthusiastic, proud) and ten negative
words (e.g., afraid, irritable). For each word, participants indicate the extent to which
they feel that feeling/emotion on a five point scale where 1 = not at all and 5 =
extremely. The researchers then computed the average for the positive words and
negative words for each participant.
To test the homogeneity of variance assumption, you will need to compute Levene's
test. What are you comparing with this test?
A. The two standard deviations
B. The two sample means
C. The two population means
D. The two effect sizes
Give this one a try later!
We computed a single sample t test and d to compare the sample mean (M = _____, SD
= _____) to _____, t(_____) = _____, p = _____, d = _____.
Give this one a try later!
M= 5.38
SD=.81
to 5
t(29)= 2.57
p=0.02
d=.47
Create a point and whisker plot. According to this graph, what is the highest score in
the data set?
A. 5.7
,B. 5.0
C. 5.3
Give this one a try later!
A. 5.7
Choose the correct two-tailed null hypothesis.
A. Walking will improve mood ratings.
B. Walking will not improve mood ratings.
C. Walking will influence mood ratings.
D. Walking will not influence mood ratings.
Give this one a try later!
D. Walking will not influence mood ratings.
Choose the correct APA style summary statement.
A. An independent t test was conducted to compare mood ratings for people in a
walking program (M = 4.04, SD = .74) to those in the control group (M = 3.66, SD = .96),
t (148) = 5.65, p = .007, d = .45.
B. An independent t test was conducted to compare mood ratings for people in a
walking program (M = 4.04, SD = .74) to those in the control group (M = 3.66, SD = .96),
t (138.95) = 2.73, p = .007, d = .45.
C. An independent t test was conducted to compare mood ratings for people in a
walking program (M = 4.04, SD = .74) to those in the control group (M = 3.66, SD = .96),
t (138.95) = 5.65, p = .007, d = .45.
D. An independent t test was conducted to compare mood ratings for people in a
, walking program (M = 4.04, SD = .74) to those in the control group (M = 3.66, SD = .96),
t (148) = 5.65, p = .019, 95% CI [.11, .66], d = .45, [.12, .77].
Give this one a try later!
B. An independent t test was conducted to compare mood ratings for
people in a walking program (M = 4.04, SD = .74) to those in the control
group (M = 3.66, SD = .96), t (138.95) = 2.73, p = .007, d = .45.
Independent t-test
Does taking a walk during a lunch break help improve the moods of workers? A
researcher team tested this hypothesis by conducting a study with 150 employees
working at a clothing factory. All employees at the factory take a one hour break for
lunch. What they did during that hour was determined by which experimental
condition they were randomly assigned to. In the experimental condition, employees
spent half of their lunch hour walking on an indoor track at the manufacturing plant. In
the control condition, employees did not go on a walk during their lunch break. After
three months, all employees completed a measure of mood called the PANAS-SF.
The PANAS consists of ten positive words (e.g., enthusiastic, proud) and ten negative
words (e.g., afraid, irritable). For each word, participants indicate the extent to which
they feel that feeling/emotion on a five point scale where 1 = not at all and 5 =
extremely. The researchers then computed the average for the positive words and
negative words for each participant.
To test the homogeneity of variance assumption, you will need to compute Levene's
test. What are you comparing with this test?
A. The two standard deviations
B. The two sample means
C. The two population means
D. The two effect sizes
Give this one a try later!
