CM 2500 / CM 2501 CM 2500 Structural Principles and Practices Final Exam - Part 2 Module 7- Beam Design for Kirby Hebert Q and A Louisiana State University

allCM2500/CM2501forKirby Hebert / Module7:BeamDesign|ColumnsandBuckling / FinalExam-Part2
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Information
Determinethemagnitudeanddirectionofallsupportreactionsforthepin-jointedstructureshown below.
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w = 600 lb/ft.
vt vt vt




Question 1 v t




Correct v t v t 1.00pointsoutof1.00
vt vt vt vt




Ay=

Selectone: vt




a. 1350lbs.↑ vt vt




b. 5400lbs.→ vt vt




c. 5400lbs.↓ vt vt




d. 1800lbs.↑ vt vt

, Question 2 v t




Correct v t v t 1.00pointsoutof1.00
vt vt vt vt




Ax=

Selectone:vt




a. 7200lbs.→ vt vt




b. 5400lbs.→ vt vt




c. 7200lbs.← vt vt




d. 5400lbs.← vt vt




Question 3 v t




Correct v t v t 1.00pointsoutof1.00
vt vt vt vt




Dy=

Selectone:vt




a. 4050lbs.↑ vt vt




b. 5400lbs.↑ vt vt




c. 5400lbs.↓ vt vt




d. 1800lbs.↑ vt vt




Question 4 v t




Incorrect v t 0.00pointsoutof1.00
vt vt vt vt




Dx=

Selectone:vt




a. 7200lbs.→ vt vt




b. 5400lbs.→ vt vt




c. 7200lbs.← vt vt




d. 5400lbs.← vt vt