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Examen

Solutions Manual for Cryptography and Network Security: Principles and Practice – 8th Edition (William Stallings) | Network Security Problem Solutions 2026/2027

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This complete solutions manual for Cryptography and Network Security: Principles and Practice, 8th Edition by William Stallings provides detailed, step-by-step solutions to end-of-chapter exercises, review questions, and security-related problem sets. It covers symmetric and asymmetric cryptography, block and stream ciphers, authentication mechanisms, digital signatures, key management, network security protocols, public key infrastructure, wireless security, and cybersecurity fundamentals. Ideal for cybersecurity, computer science, information technology, and network security programs, supporting assignments, technical problem-solving, and exam preparation for 2026/2027 academic ption authentication digital signatures

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, CHAPTER 2 INTRODUCTION TO NUMBER
THEORY
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ANSWERS TO QUESTIONS
d
2.1 A nonzero b is a divisor of a if a = mb for some m, where a, b, and m
yg
are integers. That is, b is a divisor of a if there is no remainder on
division.

2.2 It means that b is a divisor of a.
en
2.3 In modular arithmetic, all arithmetic operations are performed modulo
some integer.
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2.4 An integer p > 1 is a prime number if and only if its only divisors are ±1
and ±p.

2.5 Euler's totient function, written f(n), is the number of positive integers
s2
less than n and relatively prime to n.

2.6 The algorithm takes a candidate integer n as input and returns the
result "composite" if n is definitely not a prime, and the result
47
"inconclusive" if n may or may not be a prime. If the algorithm is
repeatedly applied to a number and repeatedly returns inconclusive,
then the probability that the number is actually prime increases with
each inconclusive test. The probability required to accept a number as
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prime can be set as close to 1.0 as desired by increasing the number of
tests made.

2.7 If r and n are relatively prime integers with n > 0. and if f(n) is the
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least positive exponent m such that am º 1 mod n, then r is called a
primitive root modulo n.

2.8 The two terms are synonymous.
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ANSWERS TO PROBLEMS
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2.1 The equation is the same. For integer a < 0, a will either be an integer
multiple of n of fall between two consecutive multiples qn and (q + 1)n,
?
where q < 0. The remainder satisfies the condition 0 ≤ r ≤ n.
-8-
© 2020 Pearson Education, Inc., Hoboken, NJ. All rights reserved. This material is protected under all copyright laws as they currently exist.
No portion of this material may be reproduced, in any form or by any means, without permission in writing from the publisher.

, 2.2 In this diagram, q is a negative integer.

n
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(q+1)n a qn –3n –2n –n

–2 –1 0
r
d
2.3 a. 2 b. 3 c. 4 There are other correct answers.
yg
2.4 Section 2.3 defines the relationship: a = n ´ ëa/nû + (a mod n). Thus,
we can define the mod operator as: a mod n = a – n ´ ëa/nû.
a. 5 mod 3 = 5 – 3 ë5/3û = 2
en
b. 5 mod –3 = 5 – (–3) ë5/(–3)û = –1
c. –5 mod 3 = –5 – 3 ë(–5)/3û = 1
d. –5 mod –3 = –5 – (–3) ë(–5)/(–3)û = –2

2.5 a = b
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2.6 Recall Figure 2.1 and that any integer a can be written in the form
s2
a = qn + r

where q is some integer and r one of the numbers
47
0, 1, 2, . . ., n – 1

Using the second definition, no two of the remainders in the above list
are congruent (mod n), because the difference between them is less
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than n and therefore n does not divide that difference. Therefore, two
numbers that are not congruent (mod n) must have different
remainders. So we conclude that n divides (a – b) if and only if a and b
are numbers that have the same remainder when divided by n.
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2.7 1, 2, 4, 6, 16, 12
??
? ?
-9-
© 2020 Pearson Education, Inc., Hoboken, NJ. All rights reserved. This material is protected under all copyright laws as they currently exist.
No portion of this material may be reproduced, in any form or by any means, without permission in writing from the publisher.

Información del documento

Subido en
19 de junio de 2026
Número de páginas
137
Escrito en
2025/2026
Tipo
Examen
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