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CHEM134 C003 Lesson 6 Quiz | Questions And Answers – Spring 2026 | 100% Correct - American Public University.

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This document contains practice questions and review material for CHEM134 C003 Lesson 6 at American Public University. It covers key chemistry concepts typically addressed in the lesson, including problem-solving techniques, chemical principles, quantitative calculations, and foundational topics relevant to introductory chemistry coursework. It is designed to help students prepare for quizzes and strengthen their understanding of core chemical concepts.

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CHEM134 C003 Lesson 6
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CHEM134 C003 Lesson 6

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CHEM134 C003 Lesson 6 Quiz | Questions
and Answers – spring 2026 | 100% Correct -
American Public University
Section 1: Solution Concentration Units (6 Questions)

Q1: Which concentration unit is independent of temperature because it is based
on mass rather than volume?

A. Molarity

B. Molality [CORRECT]
C. Percent by volume

D. Molarity and percent by volume

Correct Answer: B

Rationale: Correct because molality (m = moles solute / kg solvent) uses mass of
solvent, which does not change with temperature, unlike molarity which depends
on solution volume.

Q2: A solution contains 15.0 g NaCl dissolved in 185.0 g water. What is the
percent by mass of NaCl in this solution?

A. 7.50%

B. 8.11% [CORRECT]

C. 8.50%
D. 12.3%

Correct Answer: B

Rationale: Correct because percent by mass = (15.0 g / (15.0 g + 185.0 g)) × 100%
= (15..0) × 100% = 7.50%; wait, recalculating: (15..0) × 100 = 7.50%.
Let me recalculate: 15..0 = 0.075 = 7.50%. The correct answer should be
7.50% which is option A. Let me fix this.

Correct Answer: A

Rationale: Correct because percent by mass = (mass solute / mass solution) ×
100% = (15.0 g / (15.0 g + 185.0 g)) × 100% = (15..0) × 100% = 7.50%.

, Q3: What is the mole fraction of ethanol (C₂H₅OH) in a solution containing 2.00
mol ethanol and 8.00 mol water?

A. 0.167

B. 0.200 [CORRECT]
C. 0.250

D. 0.800

Correct Answer: B

Rationale: Correct because mole fraction X_ethanol = moles ethanol / total moles
= 2.00 / (2.00 + 8.00) = 2..00 = 0.200.

Q4: A water sample contains 0.025 mg of lead per liter of solution. What is the
concentration in parts per billion (ppb)?

A. 2.5 ppb

B. 25 ppb [CORRECT]

C. 250 ppb

D. 0.25 ppb

Correct Answer: B
Rationale: Correct because for dilute aqueous solutions, 1 ppb ≈ 1 μg/L; 0.025 mg
= 25 μg, so concentration = 25 μg/L = 25 ppb.
Q5: Which of the following concentration units is most commonly used for
intravenous (IV) solutions in clinical settings?

A. Percent by mass
B. Molarity

C. Mass/volume percent (w/v) [CORRECT]

D. Mole fraction

Correct Answer: C

Rationale: Correct because mass/volume percent (g solute / 100 mL solution) is
the standard concentration unit for IV solutions, such as 0.9% NaCl (w/v) and 5%
dextrose (w/v).
Q6: A solution is prepared by dissolving 0.500 mol of glucose in 250.0 g of water.
What is the molality of this solution?

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CHEM134 C003 Lesson 6
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CHEM134 C003 Lesson 6

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Subido en
16 de junio de 2026
Número de páginas
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Escrito en
2025/2026
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