Campbell Biology Ch. 6 - 10 Test Bank
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1. Campbell's Biology, 9e (Reece et al.) Answer: C
Chapter 6 A Tour of the Cell Topic: Concept 6.1
This chapter introduces the topics of microscopy and
cell fractionation, followed by a review of the cell
and the major organelles and structures of eukaryotic
cells. A challenge with this chapter is to keep this
data from simply being a list of parts. In addition to
the structure and function of individual organelles,
questions probe student understanding of the cell
as a dynamic, interconnected system: the flow of
membrane and proteins in the endomembrane sys-
tem to the plasma membrane; the flow of informa-
tion from the nucleus to the cytoplasm; and the con-
nection between the cytoskeleton, the plasma mem-
brane, and the extracellular matrix. An evolutionary
perspective goes beyond structural distinctions be-
tween prokaryotes and eukaryotes to examine theo-
ries concerning the evolutionary origins of eukary-
otes and key eukaryotic cell structures.
Multipl
2. Skill: Knowledge/Comprehension Answer: C
Topic: Concept 6.1
2) The advantage of light microscopy over electron
microscopy is that
A) light microscopy provides for higher magnification
than electron microscopy.
B) light microscopy provides for higher resolving
power than electron microscopy.
C) light microscopy allows one to view dynamic
processes in living cells.
D) light microscopy provides higher contrast than
electron microscopy.
E) specimen preparation for light microcopy does not
produce artifacts.
3.
, Campbell Biology Ch. 6 - 10 Test Bank
Study online at https://quizlet.com/_g11tvf
Skill: Knowledge/Comprehension Answer: D
Topic: Concept 6.1
3) A primary objective of cell fractionation is to
A) view the structure of cell membranes.
B) sort cells based on their size and weight.
C) determine the size of various organelles.
D) separate the major organelles so that their partic-
ular functions can be determined.
E) separate lipid-soluble from water-soluble mole-
cules.
4. Skill: Knowledge/Comprehension Answer: B
Topic: Concept 6.1
4) In the fractionation of homogenized cells using
centrifugation, the primary factor that determines
whether a specific cellular component ends up in the
supernatant or the pellet is
A) the relative solubility of the component.
B) the size and weight of the component.
C) the percentage of carbohydrates in the compo-
nent.
D) the presence or absence of nucleic acids in the
component.
E) the presence or absence of lipids in the compo-
nent.
5. Skill: Knowledge/Comprehension Answer: E
5) Which of the following correctly lists the order in Topic: Concept 6.1
which cellular components will be found in the pellet
when homogenized cells are treated with increasing-
ly rapid spins in a centrifuge?
A) ribosomes, nucleus, mitochondria
B) chloroplasts, ribosomes, vacuoles
C) nucleus, ribosomes, chloroplasts
D) vacuoles, ribosomes, nucleus
E) nucleus, mitochondria, ribosomes
6.
, Campbell Biology Ch. 6 - 10 Test Bank
Study online at https://quizlet.com/_g11tvf
Skill: Application/Analysis Answer: A
Topic: Concept 6.1
6) Green fluorescent protein (GFP) can be used to
fluorescently label a specific protein in cells by ge-
netically engineering cells to synthesize the target
protein fused to GFP. What is the advantage of using
GFP fusions to visualize specific proteins, instead of
staining cells with fluorescently labeled probes that
bind to the target protein?
A) GFP fusions enable one to track changes in the
location of the protein in living cells; staining usually
requires preserved cells.
B) GFP fusions enable higher resolution than stain-
ing with fluorescent probes.
C) GFP permits the position of the protein in the cell
more precisely than fluorescent probes.
D) GFP permits visualization of protein-protein inter-
actions; fluorescent probes do not.
E) GFP fusions are not subject to artifacts; fluores-
cent probes may introduce background artifacts.
7. Skill: Application/Analysis Answer: C
Topic: Concept 6.1
7) What is the reason that a modern electron micro-
scope (TEM) can resolve biological images to the
subnanometer level, as opposed to tens of nanome-
ters achievable for the best super-resolution light mi-
croscope?
A) The focal length of the electron microscope is sig-
nificantly longer.
B) Contrast is enhanced by staining with atoms of
heavy metal.
C) Electron beams have much shorter wavelengths
than visible light.
D) The electron microscope has a much greater ratio
of image size to real size.
E) The electron microscope cannot image whole cells
at one time.
, Campbell Biology Ch. 6 - 10 Test Bank
Study online at https://quizlet.com/_g11tvf
8. Skill: Application/Analysis Answer: A
Topic: Concept 6.1
8) What technique would be most appropriate to use
to observe the movements of condensed chromo-
somes during cell division?
A) light microscopy
B) scanning electron microscopy
C) transmission electron microscopy
D) confocal fluorescence microscopy
E) super-resolution fluorescence microscopy
9. Skill: Synthesis/Evaluation Answer: E
Topic: Concept 6.2
9) All of the following are part of a prokaryotic cell
except
A) DNA.
B) a cell wall.
C) a plasma membrane.
D) ribosomes.
E) an endoplasmic reticulum.
10. Skill: Knowledge/Comprehension Answer: C
Topic: Concept 6.2
10) The volume enclosed by the plasma membrane of
plant cells is often much larger than the correspond-
ing volume in animal cells. The most reasonable ex-
planation for this observation is that
A) plant cells are capable of having a much higher
surface-to-volume ratio than animal cells.
B) plant cells have a much more highly convoluted
(folded) plasma membrane than animal cells.
C) plant cells contain a large vacuole that reduces the
volume of the cytoplasm.
D) animal cells are more spherical, whereas plant
cells are elongated.
E) plant cells can have lower surface-to-volume ratios
than animal cells because plant cells synthesize their
own nutrients.
Study online at https://quizlet.com/_g11tvf
1. Campbell's Biology, 9e (Reece et al.) Answer: C
Chapter 6 A Tour of the Cell Topic: Concept 6.1
This chapter introduces the topics of microscopy and
cell fractionation, followed by a review of the cell
and the major organelles and structures of eukaryotic
cells. A challenge with this chapter is to keep this
data from simply being a list of parts. In addition to
the structure and function of individual organelles,
questions probe student understanding of the cell
as a dynamic, interconnected system: the flow of
membrane and proteins in the endomembrane sys-
tem to the plasma membrane; the flow of informa-
tion from the nucleus to the cytoplasm; and the con-
nection between the cytoskeleton, the plasma mem-
brane, and the extracellular matrix. An evolutionary
perspective goes beyond structural distinctions be-
tween prokaryotes and eukaryotes to examine theo-
ries concerning the evolutionary origins of eukary-
otes and key eukaryotic cell structures.
Multipl
2. Skill: Knowledge/Comprehension Answer: C
Topic: Concept 6.1
2) The advantage of light microscopy over electron
microscopy is that
A) light microscopy provides for higher magnification
than electron microscopy.
B) light microscopy provides for higher resolving
power than electron microscopy.
C) light microscopy allows one to view dynamic
processes in living cells.
D) light microscopy provides higher contrast than
electron microscopy.
E) specimen preparation for light microcopy does not
produce artifacts.
3.
, Campbell Biology Ch. 6 - 10 Test Bank
Study online at https://quizlet.com/_g11tvf
Skill: Knowledge/Comprehension Answer: D
Topic: Concept 6.1
3) A primary objective of cell fractionation is to
A) view the structure of cell membranes.
B) sort cells based on their size and weight.
C) determine the size of various organelles.
D) separate the major organelles so that their partic-
ular functions can be determined.
E) separate lipid-soluble from water-soluble mole-
cules.
4. Skill: Knowledge/Comprehension Answer: B
Topic: Concept 6.1
4) In the fractionation of homogenized cells using
centrifugation, the primary factor that determines
whether a specific cellular component ends up in the
supernatant or the pellet is
A) the relative solubility of the component.
B) the size and weight of the component.
C) the percentage of carbohydrates in the compo-
nent.
D) the presence or absence of nucleic acids in the
component.
E) the presence or absence of lipids in the compo-
nent.
5. Skill: Knowledge/Comprehension Answer: E
5) Which of the following correctly lists the order in Topic: Concept 6.1
which cellular components will be found in the pellet
when homogenized cells are treated with increasing-
ly rapid spins in a centrifuge?
A) ribosomes, nucleus, mitochondria
B) chloroplasts, ribosomes, vacuoles
C) nucleus, ribosomes, chloroplasts
D) vacuoles, ribosomes, nucleus
E) nucleus, mitochondria, ribosomes
6.
, Campbell Biology Ch. 6 - 10 Test Bank
Study online at https://quizlet.com/_g11tvf
Skill: Application/Analysis Answer: A
Topic: Concept 6.1
6) Green fluorescent protein (GFP) can be used to
fluorescently label a specific protein in cells by ge-
netically engineering cells to synthesize the target
protein fused to GFP. What is the advantage of using
GFP fusions to visualize specific proteins, instead of
staining cells with fluorescently labeled probes that
bind to the target protein?
A) GFP fusions enable one to track changes in the
location of the protein in living cells; staining usually
requires preserved cells.
B) GFP fusions enable higher resolution than stain-
ing with fluorescent probes.
C) GFP permits the position of the protein in the cell
more precisely than fluorescent probes.
D) GFP permits visualization of protein-protein inter-
actions; fluorescent probes do not.
E) GFP fusions are not subject to artifacts; fluores-
cent probes may introduce background artifacts.
7. Skill: Application/Analysis Answer: C
Topic: Concept 6.1
7) What is the reason that a modern electron micro-
scope (TEM) can resolve biological images to the
subnanometer level, as opposed to tens of nanome-
ters achievable for the best super-resolution light mi-
croscope?
A) The focal length of the electron microscope is sig-
nificantly longer.
B) Contrast is enhanced by staining with atoms of
heavy metal.
C) Electron beams have much shorter wavelengths
than visible light.
D) The electron microscope has a much greater ratio
of image size to real size.
E) The electron microscope cannot image whole cells
at one time.
, Campbell Biology Ch. 6 - 10 Test Bank
Study online at https://quizlet.com/_g11tvf
8. Skill: Application/Analysis Answer: A
Topic: Concept 6.1
8) What technique would be most appropriate to use
to observe the movements of condensed chromo-
somes during cell division?
A) light microscopy
B) scanning electron microscopy
C) transmission electron microscopy
D) confocal fluorescence microscopy
E) super-resolution fluorescence microscopy
9. Skill: Synthesis/Evaluation Answer: E
Topic: Concept 6.2
9) All of the following are part of a prokaryotic cell
except
A) DNA.
B) a cell wall.
C) a plasma membrane.
D) ribosomes.
E) an endoplasmic reticulum.
10. Skill: Knowledge/Comprehension Answer: C
Topic: Concept 6.2
10) The volume enclosed by the plasma membrane of
plant cells is often much larger than the correspond-
ing volume in animal cells. The most reasonable ex-
planation for this observation is that
A) plant cells are capable of having a much higher
surface-to-volume ratio than animal cells.
B) plant cells have a much more highly convoluted
(folded) plasma membrane than animal cells.
C) plant cells contain a large vacuole that reduces the
volume of the cytoplasm.
D) animal cells are more spherical, whereas plant
cells are elongated.
E) plant cells can have lower surface-to-volume ratios
than animal cells because plant cells synthesize their
own nutrients.
