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MCAT AAMC practice exam Chem Phys Exam Questions & Answers |2026| ELABORATED &DETAILED ANSWERS!!

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MCAT AAMC practice exam Chem Phys Exam Questions & Answers |2026| ELABORATED &DETAILED ANSWERS!!

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5/16/26, 8:42 AM MCAT AAMC practice exam Chem Phys Exam Questions & Answers |2026| ELABORATED &DETAILED ANSWERS!! Flashcards | …




MCAT AAMC practice exam Chem Phys Exam
Questions & Answers |2026| ELABORATED
&DETAILED ANSWERS!!

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Terms in this set (56)



What quantity of Compound 1 M=mol/v
(483.5g) must be provided to
prepare 100.00 mL of solution with a 1 umol=0.000001 moles (1x10^-6)
concentration equal to Ki (60.3uM)?
2.92mg




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,5/16/26, 8:42 AM MCAT AAMC practice exam Chem Phys Exam Questions & Answers |2026| ELABORATED &DETAILED ANSWERS!! Flashcards | …



If only [I] is increased, then [ESI] or Solution: The correct answer is C.
[EI] increases. This is an example of: A. The Bose-Einstein Principle states that a
A. the Bose-Einstein Principle. collection of atoms cooled close to absolute zero
B. the Heisenberg Uncertainty will coalesce into a single quantum state.
Principle. B. The Heisenberg Uncertainty Principle states that
C. the Le Châtelier's Principle. one cannot know both the momentum and position
D. the Pauli Exclusion Principle. of an object with absolute certainty.
C. Le Châtelier's Principle states that in a reversible
process, the application of stress to the system will
cause the system to respond in a way that will
relieve this stress. In this case, the reversible
process is E + I forming EI or ES + I forming ESI. In
either case, increasing [I] induces stress of the
system, and the system relieves that stress by
converting I to either more EI or ESI.
D. The Pauli Exclusion Principle states that two or
more identical fermions, e.g. electrons, cannot
occupy the same quantum state.


Which structural change to Solution: The correct answer is A.
Compound 1 would make it more A. Nitrogen in the benzene ring would have a lone
water soluble? pair that could accept a hydrogen bond from
A. Replacing benzene CH with N in water, thus increasing the solubility of the
the ring compound.
B. Replacing C=O with C=CH2 B. Replacing C=O with C=CH2 would decrease the
C. Replacing N-N=N with CH- polarity of the compound and make it less water
CH=CH soluble.
D. Replacing NH with NCH3 C. Replacing N−N=N with CH−CH=CH would
decrease the polarity of the compound and make it
less water soluble.
D. Replacing NH with NCH3 removes a hydrogen
bond donor, thus decreasing water solubility.




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In μM•s-1 and μM, what should the Neither is affected by a change in I, therefore they
approximate values of kcat/KM and will stay the same (150 and 60.3). Ki is the
Ki be, respectively, when [I] = 180 equilibrium constant and is never affected by
μM? increasing I.


What functional group Solution: The correct answer is A.
transformation occurs in the product A. This is two-electron reduction of a ketone to an
of the reaction catalyzed by Na+- alcohol, which is the reaction catalyzed by Na+-
NQR (NADH and ubiquinone)? NQR.
A. RC(=O)R → RCH(OH)R A. This is the reaction catalyzed by a phosphatase.
B. ROPO32- → ROH + Pi A. This is the reaction catalyzed by a protease or
C. RC(=O)NHR'→ RCOOH + R'NH2 amidase.
D. RC(=O)OR'→ RCOOH + R'OH A. This is the reaction catalyzed by an esterase.




What is the chemical structure of a Solution: The correct answer is B.
component found in four of the five A. This is the structure of adenine. It is only found in
cofactors (flavins) used by Na+- FAD.
NQR? B. This is the structure of flavin, found in four of the
five cofactors used by Na+-NQR.
C. This is the structure of ubiquinone. It is a
substrate, but not a cofactor.
D. This is the structure of histidine. It is an amino
acid, not a cofactor.




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