APM2611 Assignment 4 Solutions 2026
Full Solutions By TA tutor iQ level
UNISA
DUE DATE: 23-09-2026
, APM2611 Assignment 04 – Full Solutions
QUESTION 1
1.1 Fourier Series of f(x) = |x| on [−π, π]
The Fourier series is:
∞
𝑎0
𝑓(𝑥) = + ∑(𝑎𝑛 cos 𝑛𝑥 + 𝑏𝑛 sin 𝑛𝑥)
2
𝑛=1
Compute a₀:
1 𝜋 2 𝜋 2 𝑥2 𝜋 2 𝜋2
𝑎0 = ∫ ∣ 𝑥 ∣ 𝑑𝑥 = ∫ 𝑥 𝑑𝑥 = ⋅ ∣ = ⋅ =𝜋
𝜋 −𝜋 𝜋 0 𝜋 2 0 𝜋 2
Compute aₙ:
Since |x| is even, the product |x|cos(nx) is even, and |x|sin(nx) is odd.
1 𝜋 2 𝜋
𝑎𝑛 = ∫ ∣ 𝑥 ∣ cos 𝑛𝑥 𝑑𝑥 = ∫ 𝑥cos 𝑛𝑥 𝑑𝑥
𝜋 −𝜋 𝜋 0
Integrate by parts: let u = x, dv = cos(nx)dx → du = dx, v = sin(nx)/n
𝜋
2 𝑥sin 𝑛𝑥 𝜋 sin 𝑛𝑥
= [ 𝑛 ∣0 − ∫
𝜋 0
𝑛 𝑑𝑥]
2 1 cos 𝑛𝑥 𝜋 2 1
= [0 + ⋅ ∣0 ] = ⋅ 2 [cos(𝑛𝜋) − 1]
𝜋 𝑛 𝑛 𝜋 𝑛
2
= 2 [(−1)𝑛 − 1]
𝜋𝑛
• If n is even: 𝑎𝑛 = 0
2 4
• If n is odd: 𝑎𝑛 = 𝜋𝑛2 (−2) = − 𝜋𝑛2
Compute bₙ:
Since |x|sin(nx) is odd:
1 𝜋
𝑏𝑛 = ∫ ∣ 𝑥 ∣ sin 𝑛𝑥 𝑑𝑥 = 0
𝜋 −𝜋
Full Solutions By TA tutor iQ level
UNISA
DUE DATE: 23-09-2026
, APM2611 Assignment 04 – Full Solutions
QUESTION 1
1.1 Fourier Series of f(x) = |x| on [−π, π]
The Fourier series is:
∞
𝑎0
𝑓(𝑥) = + ∑(𝑎𝑛 cos 𝑛𝑥 + 𝑏𝑛 sin 𝑛𝑥)
2
𝑛=1
Compute a₀:
1 𝜋 2 𝜋 2 𝑥2 𝜋 2 𝜋2
𝑎0 = ∫ ∣ 𝑥 ∣ 𝑑𝑥 = ∫ 𝑥 𝑑𝑥 = ⋅ ∣ = ⋅ =𝜋
𝜋 −𝜋 𝜋 0 𝜋 2 0 𝜋 2
Compute aₙ:
Since |x| is even, the product |x|cos(nx) is even, and |x|sin(nx) is odd.
1 𝜋 2 𝜋
𝑎𝑛 = ∫ ∣ 𝑥 ∣ cos 𝑛𝑥 𝑑𝑥 = ∫ 𝑥cos 𝑛𝑥 𝑑𝑥
𝜋 −𝜋 𝜋 0
Integrate by parts: let u = x, dv = cos(nx)dx → du = dx, v = sin(nx)/n
𝜋
2 𝑥sin 𝑛𝑥 𝜋 sin 𝑛𝑥
= [ 𝑛 ∣0 − ∫
𝜋 0
𝑛 𝑑𝑥]
2 1 cos 𝑛𝑥 𝜋 2 1
= [0 + ⋅ ∣0 ] = ⋅ 2 [cos(𝑛𝜋) − 1]
𝜋 𝑛 𝑛 𝜋 𝑛
2
= 2 [(−1)𝑛 − 1]
𝜋𝑛
• If n is even: 𝑎𝑛 = 0
2 4
• If n is odd: 𝑎𝑛 = 𝜋𝑛2 (−2) = − 𝜋𝑛2
Compute bₙ:
Since |x|sin(nx) is odd:
1 𝜋
𝑏𝑛 = ∫ ∣ 𝑥 ∣ sin 𝑛𝑥 𝑑𝑥 = 0
𝜋 −𝜋