Escrito por estudiantes que aprobaron Inmediatamente disponible después del pago Leer en línea o como PDF ¿Documento equivocado? Cámbialo gratis 4,6 TrustPilot
logo-home
Examen

SOLUTIONS MANUAL for Introduction to Cryptography with Coding Theory, 3rd edition by Wade Trappe, Lawrence Washington.

Puntuación
-
Vendido
-
Páginas
62
Grado
A+
Subido en
28-04-2026
Escrito en
2025/2026

MASTER CRYPTOGRAPHY AND CODING THEORY WITH CONFIDENCE using the official Instructor's Solutions Manual for Introduction to Cryptography with Coding Theory, 3rd Edition by Wade Trappe (Rutgers University) and Lawrence C. Washington (University of Maryland), published by Pearson (2021) . This textbook has been the definitive resource in cryptography education, covering a broad spectrum of topics from classical ciphers to post-q uantum cryptography, with a lively and conversational tone that mixes applied and theoretical aspects . The solutions manual provides detailed, step-by-step solutions to the end-of-chapter problems, making it an indispensable resource for instructors, teaching assistants, cybersecurity students, computer science majors, mathematics students, and self-learners. Important Note: The official instructor's solutions manual is protected by copyright and is typically provided only to qualified instructors by the publisher . The 3rd edition textbook includes a new section at the back of the book with answers to most odd-numbered problems . Students seeking the complete manual should check with their course instructor. The solutions below are representative examples from the 2nd edition manual that demonstrate the solution methodology used throughout both editions

Mostrar más Leer menos
Institución
SOLUTION MANUAL
Grado
SOLUTION MANUAL

Vista previa del contenido

1

, SOLUTIONS FOR CHAPTER 1

Q.1.1 DMS with source probabilities : {0.30 0.25 0.20 0.15 0.10}
1
Entropy H(X) =  p i log
i pi
= 0.30 log 1/0.30 + 0.25 log 1/0.25 + ……………
= 2.228 bits
qi
Q.1.2 Define D(p q) =
p i
log (1)
i pi

pi, qi – probability distributions of discrete source X.

q  qi 
D(p q) = p i log pi  P  i− 1 [using identity ln x  x – 1]
i i i  pi 
=  (q i − pi ) = 0
i

 D(p q)  0

Put qi = 1/n in (1) where n = cardinality of the distance source.

D(p q) =  p log p
i
i i +  p log n
i
i


 p log pi i + log n = − H ( X ) + log n  0
= i
− H ( X )  log n

H(X) = log n for uniform probability distribution. Hence proved that entropy of a
discrete source is maximum when output symbols are equally probable. The
quantity D(p q) is called the Kullback-Leibler Distance.

Q.1.3 The plots are given below:




2

,"Copyrighted Material" -"Additional resource material supplied with the book Information, Theory, Coding an3d
Cryptography, Second Edition written by Ranjan Bose & published by McGraw-Hill Education (India) Pvt. Ltd. This
resource material is for Instructor's use only."



3


2
y = x -1
1
y = ln(x)
0


-1


-2


-3
0 0.5 1 1.5 2 2.5 3 3.5


Q 1.4 Consider two probability distributions: {p0, p1, , pK-1} and {q0, q1, , qK-1}.
K −1  qk  1 K −1  qk 
We have  pk log2   =  pk ln p  . Use ln x  1 – x,
p ln 2 k =0
k =0  k  k
 qk   1 K −1 p  qk 
 pk log2  p ln 2  k p −1
K −1


k =0  k k =0  k 
K −1
1
  (qk − pk )
ln 2 k=0
1  K −1
  q k −  pk  = 0
K −1

ln 2  k =0 k =0 
K −1  qk 
Thus,  pk log2    0 . (1)
p
k =0  k
n m P(xi , y j )
Now, I(X; Y) =  P( xi , y j )log P(x )P( y ) (2)
i=1 j =1 i j



From (1) and (2) we can conclude (after basic manipulations) that I(X;Y)  0. The
equality holds if and only if P(xi , x j ) = P(xi )P(x j ) , i.e., when the input and output
symbols of the channel are statistically independent.




3

, "Copyrighted Material" -"Additional resource material supplied with the book Information, Theory, Coding an4d
Cryptography, Second Edition written by Ranjan Bose & published by McGraw-Hill Education (India) Pvt. Ltd. This
resource material is for Instructor's use only."


Q.1.5 Source X has infinitely large set of outputs P(xi) = 2-i, i = 1, 2, 3, ………
k k k k k k k k k k k k k k k k

1
H(X) = p(x ) log = 2−i log 2−i
k k k

k k k k k k k k k k k
k k

i
i=1 p(xi i=1

) k




= k
 i=1
i .2 −i k k = 2bits k k




Q.1.6 Given: P(xi) = p(1-p)i-1 k k k i = 1, 2, 3, ……..
k k k k k




H(X)= −p(1− p)i−1 logp(1− p)i−1 i
k k k k k k
k
k k k k k k




= −p(1− p)i−1 log p + (i−1) log(1− p)
k k
k
k k k k k k k k k k k


i


= − plog pp(1− p)i−1 − plog(1− p) (i−1) (1− p)i−1
k k k k k
k
k k k k k k k k k k k k k


i=1 i
1− p 1
= − plog p  − plog(1− p)
k k k

k k k k k k k k k



p p2 k



 1− p plog p − (1− p)log(1− p) k k k k k k k k k k k k k 1
= −log p −
k  log(1− p) =
k k k k k k k = k k H(p) bits
k k k



 p  p k k
p


Q 1.7 Hint: Same approach as the previous two problems.
k k k k k k k k k




Q 1.8 Yes it is uniquely decodable code because each symbol is coded uniquely.
k k k k k k k k k k k k k




Q 1.9 The relative entropy or Kullback Leibler distance between two probability mass
k k k k k k k k k k k k



functions p(x) and q(x) is defined as
k k k k k k k



 p(x)  k k


D( p||q )=  p(x)log  . (1.76)
 q(x) 
k k k k k k k

xX k k




(i) Showthat D ( p ||q) is non negative. k k k k k k k




 p(x)   q(x)  k k k k



Solution: − D ( p || q)= −p(x)log
k k k k k k
k
 = p(x)log  k k k k
k
k k k


q(x) p(x)
  xX  
k k
xX

 logp(x)
q(x)
(from Jensen’s Inequality: Ef(X) f(EX))
k k

k k k k k k k
k



xX p(x)

= logq(x) = log(1) = 0.
k k
k
k k k k


xX



Thus, − D(p ||q) 0 or D ( p ||q) 0. k k k k k k k k k k k k k k




4

Libro relacionado

Escuela, estudio y materia

Institución
SOLUTION MANUAL
Grado
SOLUTION MANUAL

Información del documento

Subido en
28 de abril de 2026
Número de páginas
62
Escrito en
2025/2026
Tipo
Examen
Contiene
Preguntas y respuestas

Temas

$21.99
Accede al documento completo:

¿Documento equivocado? Cámbialo gratis Dentro de los 14 días posteriores a la compra y antes de descargarlo, puedes elegir otro documento. Puedes gastar el importe de nuevo.
Escrito por estudiantes que aprobaron
Inmediatamente disponible después del pago
Leer en línea o como PDF

Conoce al vendedor

Seller avatar
Los indicadores de reputación están sujetos a la cantidad de artículos vendidos por una tarifa y las reseñas que ha recibido por esos documentos. Hay tres niveles: Bronce, Plata y Oro. Cuanto mayor reputación, más podrás confiar en la calidad del trabajo del vendedor.
StuviaHero01 Chamberlain College Of Nursing
Seguir Necesitas iniciar sesión para seguir a otros usuarios o asignaturas
Vendido
152
Miembro desde
1 año
Número de seguidores
7
Documentos
3616
Última venta
2 días hace
TESTBANKS & SOLUTION MANUALS

TESTBANKS & SOLUTION MANUALS if in any need of a Test bank and Solution Manual, fell free to Message me . All the best in your Studies

4.0

27 reseñas

5
16
4
4
3
2
2
1
1
4

Por qué los estudiantes eligen Stuvia

Creado por compañeros estudiantes, verificado por reseñas

Calidad en la que puedes confiar: escrito por estudiantes que aprobaron y evaluado por otros que han usado estos resúmenes.

¿No estás satisfecho? Elige otro documento

¡No te preocupes! Puedes elegir directamente otro documento que se ajuste mejor a lo que buscas.

Paga como quieras, empieza a estudiar al instante

Sin suscripción, sin compromisos. Paga como estés acostumbrado con tarjeta de crédito y descarga tu documento PDF inmediatamente.

Student with book image

“Comprado, descargado y aprobado. Así de fácil puede ser.”

Alisha Student

Preguntas frecuentes