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Microbiology BIOD 171 Module 2 Exam Microbial Growth Metabolism Genetics Control Actual Exam 2026/2027 – Portage Learning – Complete Questions and Answers with Detailed Rationales – Pass Guaranteed – A+ Graded

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Master your Portage Learning BIOD 171 Microbiology Module 2 Exam on Microbial Growth, Metabolism, Genetics, and Control with this comprehensive actual exam resource for the 2026/2027 academic year. This complete guide covers bacterial growth requirements, culture methods, microbial metabolic pathways, enzyme function, bacterial genetics including DNA replication and gene transfer, and physical/chemical control methods. Each question includes detailed rationales to reinforce microbiological principles and laboratory applications. Backed by our Pass Guarantee. Download now.

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Institución
Microbiology BIOD 171
Grado
Microbiology BIOD 171

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Microbiology BIOD 171 Module 2 Exam Microbial
Growth Metabolism Genetics Control Actual Exam
2026/2027 – Portage Learning – Complete
Questions and Answers with Detailed Rationales –
Pass Guaranteed – A+ Graded



==================================================
PART A: Microbial Growth Requirements & Bacterial Reproduction
(12 Questions)

Q1: A bacterial culture isolated from a hot spring in Yellowstone National Park grows
optimally at 75°C but cannot grow below 60°C. How should this organism be classified?
A. Psychrophile

B. Mesophile

C. Thermophile [CORRECT]

D. Facultative psychrophile

Correct Answer: C

Rationale: Thermophiles grow optimally between 50-80°C, matching the hot spring
habitat and 75°C optimum described. Psychrophiles (A) prefer cold (<15°C), while
mesophiles (B) prefer moderate temperatures (20-45°C) like human pathogens.
"Facultative psychrophile" (D) is not standard terminology; psychrophiles are typically

,obligate. Portage Tip: Remember temperature ranges—psychro (cold), meso (middle),
thermo (heat), hyperthermo (extreme heat >80°C).

Q2 (Generation Time Math): Escherichia coli has a generation time of 20 minutes under
optimal conditions. If a culture starts with 5 × 10³ cells/mL, how many cells will be
present after 2 hours of exponential growth?
A. 5 × 10⁴ cells/mL

B. 1.6 × 10⁵ cells/mL

C. 3.2 × 10⁵ cells/mL [CORRECT]

D. 6.4 × 10⁶ cells/mL

Correct Answer: C

Rationale: Formula: Nt = N0 × 2ⁿ where n = total time ÷ generation time = 120 min ÷ 20
min = 6 generations. Calculation: 5 × 10³ × 2⁶ = 5 × 10³ × 64 = 320 × 10³ = 3.2 × 10⁵
cells/mL. Option A represents only 3.3 generations (1 log increase). Option D incorrectly
calculates 2⁷ (7 generations). Portage Tip: Always calculate n first, then apply the
exponent before multiplying by initial population.

Q3 (SATA): Which of the following microorganisms would be classified as obligate
anaerobes? (Select all that apply.)
A. Clostridium botulinum [CORRECT]

B. Mycobacterium tuberculosis

C. Bacteroides fragilis [CORRECT]

D. Staphylococcus aureus

E. Clostridium tetani [CORRECT]

F. Pseudomonas aeruginosa

, Correct Answer: A, C, E

Rationale: Obligate anaerobes cannot grow in oxygen and include Clostridium species
(A, E) and Bacteroides (C), which lack superoxide dismutase and catalase. M.
tuberculosis (B) and P. aeruginosa (F) are obligate aerobes requiring oxygen. S. aureus
(D) is a facultative anaerobe capable of fermentative or respiratory metabolism. Portage
Tip: Remember Clostridia (tetani, botulinum, perfringens) are classic obligate anaerobes
found in soil and anaerobic wounds.

Q4: During which phase of the bacterial growth curve are cells most susceptible to
antibiotics that target cell wall synthesis (such as penicillin)?
A. Lag phase

B. Log (exponential) phase [CORRECT]

C. Stationary phase

D. Death phase

Correct Answer: B

Rationale: The log phase is characterized by rapid binary fission and active
peptidoglycan synthesis, making cells most vulnerable to beta-lactam antibiotics that
inhibit cell wall formation. Lag phase (A) involves metabolic preparation without
division; stationary phase (C) involves slowed metabolism and spore formation; death
phase (D) involves cell lysis but antibiotics are less effective against dormant cells.
Portage Tip: "Log = susceptible, Stationary = resistant" is the rule for antibiotic
susceptibility testing.

Q5: A bacterium isolated from a lemon juice factory (pH 2.5) grows optimally at pH 3.0
but cannot grow above pH 6.0. This organism is best described as:
A. Neutrophile

Escuela, estudio y materia

Institución
Microbiology BIOD 171
Grado
Microbiology BIOD 171

Información del documento

Subido en
4 de abril de 2026
Número de páginas
28
Escrito en
2025/2026
Tipo
Examen
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