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MATH 101 EXAM 2 STUDY GUIDE

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Escrito en
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MATH 101 EXAM 2 STUDY GUIDE

Institución
MAT 101
Grado
MAT 101

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MATH 101 EXAM 2 STUDY GUIDE

apportionment - Answers - divide objects that are the same but each person or state
gets a different amount

state - Answers - a party having a stake in the apportionment

seat - Answers - the set of (M) identical, indivisible objects that are being divided among
the (N) states

population - Answers - a set of (N) positive numbers which denote the states' respective
populations

we write P = p1 + p2 + · · · + pN
- where P is the total population
- pN are the states' populations

apportionment method - Answers - a systematic procedure that guarantees a division of
M seats to N states

standard divisor (SD) - Answers - the ratio of population to seats

in other words,
SD = TOTAL POPULATION/NUMBER OF SEATS

standard quota (SQ) - Answers - (of a state) the exact fractional number of seats that
the state would get if fractions were allowed

we denote these q1, q2, ··· ,qN

SQ = STATE POPULATION/STANDARD DIVISOR

lower quota - Answers - the standard quota rounded down

**if you always allocate the lower quota, will you never allocate too many seats

upper quota - Answers - the standard quota rounded up

Hamilton's method - Answers - 1. allocate the Lower Quota
2. give the surplus seats to the state with the largest fractional parts until no more
surplus seats remain

**the maximum number of seats that could be allocated to a population using Hamilton's
method is one more than the lower quota

, Jefferson's method - Answers - 1. find a modified divisor (D) so that the lower quotas
add up to the number of seats
2. apportion to each state its modified lower quota

**removes issue of surplus seats

modified divisor - Answers - D < Standard Divisor

Try it (guess and check)
- adjust up if total seats assigned is more than total seats available
- adjust down if total seats assigned is still less than total seats available

Huntington-Hill method - Answers - uses a modified divisor, but uses the geometric
mean to determine a cut-off point

geometric mean - Answers - found by multiplying the numbers together and then taking
the square root of these numbers

quota rule - Answers - a state's apportionment should be either its upper quota or its
lower quota

**Jefferson's can violate upper quota
**Huntington-Hill can violate upper and lower quota
** Hamilton's doesn't violate this rule

Alabama paradox - Answers - a paradox in which the number of seats being
apportioned is increased and this results in a state getting apportioned fewer seats

**only Hamilton's can create this paradox

new states paradox - Answers - a paradox in which a new state with its fair share of
seats is added into the computation and this results in another state's apportionment
being affected in any way

**only Hamilton's can create this paradox

population paradox - Answers - a paradox in which a state's population increases and
this results in the state being apportioned fewer seats

**only Hamilton's can create this paradox

adjacent vertex - Answers - any two vertices connected by an edge

isolated vertex - Answers - no edges connecting the vertex (needs disconnected graph)

degree - Answers - number of edges meeting at the vertex

Escuela, estudio y materia

Institución
MAT 101
Grado
MAT 101

Información del documento

Subido en
27 de marzo de 2026
Número de páginas
5
Escrito en
2025/2026
Tipo
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