Physics (Mock Mark Scheme, 40 Questions)
Marking key:
M = method / correct approach
A = accuracy / correct value/unit
B = independent physics point
ECF = error carried forward
Extended answers: Level 1–3 depending on clarity, depth, and correct physics points
Section A – Short Answer / Definitions (Q1–10)
Q1. Define density.
1 mark: mass per unit volume of a substance. (B)
Q2. State Newton’s second law.
1 mark: F=maF = maF=ma; force is proportional to acceleration and acts in direction of
acceleration. (B)
Q3. What is terminal velocity?
1 mark: constant velocity when drag equals weight. (B)
Q4. Define pressure.
1 mark: force per unit area. (B)
Q5. State the principle of conservation of energy.
1 mark: energy cannot be created or destroyed, only transformed. (B)
Q6. Define the specific heat capacity of a substance.
1 mark: energy required to raise 1 kg of the substance by 1 K. (B)
Q7. State Ohm’s law.
1 mark: current through a conductor is proportional to voltage across it, at constant
temperature. (B)
, Q8. Define frequency of a wave.
1 mark: number of cycles per second. (B)
Q9. Define work done.
1 mark: force × distance in direction of force. (B)
Q10. State Archimedes’ principle.
1 mark: upthrust equals weight of fluid displaced. (B)
Section B – Calculations / Numerical Questions (Q11–25)
Q11. A 2 kg block accelerates at 3 m/s². Calculate the force.
M1: F=maF = maF=ma
A1: F=2×3=6 NF = 2 × 3 = 6 \, NF=2×3=6N
Q12. A wave has frequency 50 Hz and wavelength 2 m. Find speed.
M1: v=fλv = f \lambdav=fλ
A1: v=50×2=100 m/sv = 50 × 2 = 100 \, m/sv=50×2=100m/s
Q13. A resistor of 10 Ω carries 2 A. Find the power.
M1: P=I2RP = I^2 RP=I2R
A1: P=4×10=40 WP = 4 × 10 = 40 \, WP=4×10=40W
Q14. Particle moves in circle of radius 0.5 m at 4 m/s. Find centripetal acceleration.
M1: ac=v2/ra_c = v^2 / rac=v2/r
A1: ac=16/0.5=32 m/s2a_c = .5 = 32 \, m/s^2ac=16/0.5=32m/s2
Q15. A 3 kg mass falls 10 m. Calculate change in gravitational potential energy.
M1: ΔEp=mgh\Delta E_p = m g hΔEp=mgh
A1: 3×9.81×10≈294.3 J3 × 9.81 × 10 ≈ 294.3 \, J3×9.81×10≈294.3J
Q16. Find current in 12 V circuit with resistance 6 Ω.
M1: I=V/RI = V/RI=V/R
A1: I=12/6=2 AI = 12/6 = 2 \, AI=12/6=2A