ALEKS Basic Math Placement Test Review questions with answers.

ALEKS Basic Math Placement Test |\ |\ |\ |\ |\




Review questions with answers |\ |\ |\




how to find domain with a given equation - CORRECT
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ANSWERS ✔✔-if a fraction, set denom. to zero, then solve
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-in equation, plug in 0 for x
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*usually can be a + or - solution*
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(-) + (-)= ...
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(-) x (-)= ...
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(-) divided by a (-)= ... - CORRECT ANSWERS ✔✔(-)
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(+)
(+)


quotient - CORRECT ANSWERS ✔✔division
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adding and subtracting fractions - CORRECT ANSWERS
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✔✔-make denoms the same |\ |\ |\




-add/subtract numerators |\

, multiplying fractions - CORRECT ANSWERS ✔✔just |\ |\ |\ |\ |\ |\



multiply numerators across and denoms across and
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simplify


dividing fraction - CORRECT ANSWERS ✔✔multiply by
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reciprocal (change second fraction to reciprocal) |\ |\ |\ |\ |\




multiplying/dividing/adding mixed fractions - CORRECT |\ |\ |\ |\ |\



ANSWERS ✔✔turn them into regular fractions (multiplying |\ |\ |\ |\ |\ |\



# by denom, adding it to num, keeping denom the same)
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and continue
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subtracting mixed fractions - CORRECT ANSWERS |\ |\ |\ |\ |\ |\



✔✔*first: make denoms the same* |\ |\ |\ |\




set up as if you're subtracting two large numbers (on top
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and on bottom) |\ |\




how to solve problems like 5-2 (1/3) - CORRECT ANSWERS
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✔✔1) make problem 5- (2 (1/3))
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2) separate : 5- 2- (1/3) to get: 3- (1/3)
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3) rewrite whole #: 2+1- (1/3)
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4) rewrite as: 2 + (3/3) - (1/3) to ed up with:
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2 (2/3)
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