Calculus I
TASK 1 – Passed
Limits and Continuity
Western Governors University
, 𝑥−2 𝑥−2
A. Given 𝑓(𝑥) = 2 , Li 2 Or Explain W ℎy Tℎe Lim it Does Not Exist.
Fin m
d
𝑥 −3𝑥+2
𝑥 −3𝑥+2 𝑥 →
1
Substitution & Cℎeck:
lim𝑥−2=1−2= −1 = 𝑢𝑛𝑑𝑒𝑓𝑖𝑛𝑒𝑑 Direct substitution is inconclusive
22
because f(x) is defined as −1 wℎere x
𝑥 → 1 𝑥 −3𝑥+21 −3(1)+20 0
=1. Tℎerefore, furtℎer investigation is
needed using tℎe grapℎ and table of values.
Table Of Values:
𝑥−2
x 𝑓(𝑥) = 2
𝑥 −3𝑥+2
0.9 -10
0.99 -100
0.999 -1000 𝑥−2
x 𝑓(𝑥) = 2
0.9999 -10000
𝑥 −3𝑥+2
1.01 100
1.001 1000
1.0001 10000
1.00001 100000
Lim 𝑥−2 =− ∞ Based On Tℎe Grapℎ And Table Of Values, We Can
− 2
Tℎe Left Side Of Tℎe Function Is Undefined At X = 1 And
𝑥→ 1 𝑥 −3𝑥+2
Continues Toward Negative Infinity.
Lim 𝑥−2 = ∞ Based On Tℎe Grapℎ And Table Of Values, We Can
+ 2
Tℎe Rigℎt Side Of Tℎe Function Is Undefined At X = 1 And
𝑥→ 1 𝑥 −3𝑥+2
Continues Toward Positive Infinity.
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