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WGU D425 REVIEW SET FULL SOLUTION SOLVED QUESTIONS 2026 GRADED A+.

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WGU D425 REVIEW SET FULL SOLUTION SOLVED QUESTIONS 2026 GRADED A+.

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WGU D425
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Institución
WGU D425
Grado
WGU D425

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Subido en
21 de enero de 2026
Número de páginas
28
Escrito en
2025/2026
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Examen
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WGU D425 REVIEW SET FULL SOLUTION
SOLVED QUESTIONS 2026 GRADED A+.



◍ convert 12.5g in to kilograms. enter answer in kg. Answer: 0.0125


◍ calculate the density of an object that has a mass of 19.378 and a
volume of 15ml. enter as g/ml. Answer:


◍ a substance has a mass of 42.10g. if the density of the substance is
known to be 2.431g/ml what volume of substance is present. Answer:


◍ several samples of a metal weighed and placed into a graduated
cylinder filled with water to measure their volume by water
displacement. Answer:


◍ several samples of metal were weighed and placed into the
graduated cylinder filled water to measure their volume by water
displacement q. Answer:


◍ Dimensional Analysis Ex.
how many centimeters are there in 3.55m
quantity given: 3.55m
3.55m * (100cm/1m)=. Answer: 3.55m=355cm

,◍ Density converted between mass and volume of a substance
30.2ml sample of ethyl alcohol with a mass of 23.71002g
p=23.71002g/30.2ml=0.7851
p=. Answer: p=0.785g/ml


◍ Find mass of and object. density of alcohol is 0.7892g/mL, so
alcohol is 0.7892g per 1ml. determine the mass of alcohol for 2.0mL
use
2.0mL*(0.7892g/1mL)=. Answer: 1.5784g=1.5g


◍ Density = mass/__________. Answer: volume


◍ Density of an object?
mass of 2.4019 and volume of 1.40mL
2.4019g/1.40mL=. Answer: density = 1.7156g/mL= 1.72g/ml


◍ Density of an object?
volume of 32mL and a mass of 12.24g
12.24g/32mL. Answer: density= 0.3825g/mL=0.38g/mL


◍ density of an object?
mass of 78.2g/14.2cm^3. Answer: density= 5.507g/cm= 5.51g/cm^3


◍ density of an object?

, 22.57cm^3/55g. Answer: density= 2.43686g/cm^3= 2.4g/cm^3


◍ density of an object?
85g/35mL. Answer: density= 2.42857 g/mL= 2.4g/mL


◍ what is the mass of 25.0mL of octane, with a density of 0.702 g/cm
-Given:25.0mL
conversion factors:
1.1mL
2.0.0702=1cm^3 (mL->cm^3->g)
25.0mL*1cm^3/mL*0.702g=. Answer: density= 17.55g= 17.6g


◍ the density of titanium is 4.51g/cm^3. What is the volume in cubic
inches of 3.5Ib of titanium?
conversion factors:
1) 2,2Ib=1Kg
2) 1Kg=10^3g
3) 4.51g= 1cm^3
4) 2.54cm= 1 in Find in^3
Ib-> Kg -> g-> cm^3 -> in^3
3.5Ib* 1Kg/2.2Ib*10^3g/1Kg*1cm^3/4.51g*1in/2.54cm
must multiply (1in/2.54cm)^3=1in^3/16.387cm^3
3.5Ib*1Kg/2.2Ib*10^3g/1Kg*1cm^3*1in^3*16.38cm^3. Answer:
density= 21.53in^3= 22in^3
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