CHEM 1111 Final Exam Study Guide With
Complete Solutions
A beaker has a mass of 77.275 g
a. Calculate this mass in mg
b. Calculate this mass in lb. - ANSWER a. 77.275 g * 1000 mg/g = 77257
b. 77.275 g * 1 lb/454 g = 0.17021 lb
The combined total mass in grams of a beaker and pure water is 95.175 g
a. Find the weight of the water if the empty beaker weighs 54.795 g
b. Find the volume of the water in liters. (Hint: water has a density of 1 g/mL) - ANSWER
a. 95.175 g - 54.795 g = 40.380 g
b. density = mass/volume
volume = mass/density
V= 40.38 g/ 1g/mL --> 40.380 g (1 mL/1 g)(1L/1000mL)= 0.04038 L
What is the total mass in grams of a series of samples that have masses of 753 mg,
51.227 g, and 0.437 kg? - ANSWER 753 mg * 1g/1000mg = 0.753 g
0.437 kg * 1000 g/1 kg = 437 g
0.753 g + 437 g + 51.227 g = 488.98 g
What is the density (g/mL) of a solid with a mass of 4.75 g and a volume of 6.20 mL? -
, ANSWER D = 4.75g/6.20 mL = 0.76613 g/mL
Find the mass (g) of a 257 mL sample with a specific gravity of 1.75 - ANSWER mass=
density*volume
m= (1.75g/mL)(257mL) = 449.75g = 4.50x10^2 g
specific gravity= density of substance/density of water
1.75= D/1.00g/mL --> D=1.75 g/mL
How much time is required to administer 200 mL of glucose IV solution if the flow rate is
5 mL/min? - ANSWER Time= 200mL/5 mL/min = 40 min
If the blood contains 10.5 mg/dL of calcium and the human body normally contains 6
quarts of blood, what mass of calcium (in grams) will be found in the total blood
volume? - ANSWER 6qts ( 1 gal/4qts) (3.78L/1 gal) (10 dL/1L) = 56.7 dL
10.5mg/dL (56.7dL/1) = 595.35 mg (1g/1000mg) = 0.595 g
A patient needs 0.50 grams of a medication two times per day. How many 250 mg
tablets must the patient take per day? - ANSWER 0.5 g * 2 = 1 g of medication per day
250 mg * 1g/1000mg = 0.25 g of med. in one pill
0.25*4= 1 g
4 tablets per day
Write the balanced chemical equation for the formation of magnesium oxide from
Complete Solutions
A beaker has a mass of 77.275 g
a. Calculate this mass in mg
b. Calculate this mass in lb. - ANSWER a. 77.275 g * 1000 mg/g = 77257
b. 77.275 g * 1 lb/454 g = 0.17021 lb
The combined total mass in grams of a beaker and pure water is 95.175 g
a. Find the weight of the water if the empty beaker weighs 54.795 g
b. Find the volume of the water in liters. (Hint: water has a density of 1 g/mL) - ANSWER
a. 95.175 g - 54.795 g = 40.380 g
b. density = mass/volume
volume = mass/density
V= 40.38 g/ 1g/mL --> 40.380 g (1 mL/1 g)(1L/1000mL)= 0.04038 L
What is the total mass in grams of a series of samples that have masses of 753 mg,
51.227 g, and 0.437 kg? - ANSWER 753 mg * 1g/1000mg = 0.753 g
0.437 kg * 1000 g/1 kg = 437 g
0.753 g + 437 g + 51.227 g = 488.98 g
What is the density (g/mL) of a solid with a mass of 4.75 g and a volume of 6.20 mL? -
, ANSWER D = 4.75g/6.20 mL = 0.76613 g/mL
Find the mass (g) of a 257 mL sample with a specific gravity of 1.75 - ANSWER mass=
density*volume
m= (1.75g/mL)(257mL) = 449.75g = 4.50x10^2 g
specific gravity= density of substance/density of water
1.75= D/1.00g/mL --> D=1.75 g/mL
How much time is required to administer 200 mL of glucose IV solution if the flow rate is
5 mL/min? - ANSWER Time= 200mL/5 mL/min = 40 min
If the blood contains 10.5 mg/dL of calcium and the human body normally contains 6
quarts of blood, what mass of calcium (in grams) will be found in the total blood
volume? - ANSWER 6qts ( 1 gal/4qts) (3.78L/1 gal) (10 dL/1L) = 56.7 dL
10.5mg/dL (56.7dL/1) = 595.35 mg (1g/1000mg) = 0.595 g
A patient needs 0.50 grams of a medication two times per day. How many 250 mg
tablets must the patient take per day? - ANSWER 0.5 g * 2 = 1 g of medication per day
250 mg * 1g/1000mg = 0.25 g of med. in one pill
0.25*4= 1 g
4 tablets per day
Write the balanced chemical equation for the formation of magnesium oxide from
