WGU D427 Objective Assessment (New 2026/ 2027 Update) Data Management – Applications Review| Questions & Answers| Grade A| 100% Correct (Verified Solutions)

WGUl D427l Objectivel Assessmentl (Newl
2026/l 2027l Update)l Datal Managementl –l
Applicationsl Review|l Questionsl &l
Answers|l Gradel A|l 100%l Correctl
(Verifiedl Solutions)

QUESTION
A(n)l _____l isl al queryl thatl isl embeddedl (orl nested)l insidel anotherl query.
l a.l alias
l b.l operator
l c.l subqueryl
l d.l view

Answer:
c.l subquery



QUESTION
Alll changesl tol al tablel structurel arel madel usingl thel _____l command,l followedl byl al
keywordl thatl producesl thel specificl changesl al userl wantsl tol make.
⦁l ALTERl TABLE
⦁l UPDATEl TABLE
⦁l COMMITl TABLE
⦁l DELETEl TABLE

Answer:
⦁l ALTERl TABLE



QUESTION
Thel SQLl aggregatel functionl thatl givesl thel numberl ofl rowsl containingl non-nulll valuesl
forl al givenl columnl isl _____.
l a.l COUNTl
l b.l MIN
l c.l MAXl

,l d.l SUM

Answer:
COUNT



QUESTION
Thel _____l conditionl ofl al JOINl isl generallyl composedl ofl anl equalityl comparisonl
betweenl thel foreignl keyl andl thel primaryl keyl ofl relatedl tables.

Answer:
ON



QUESTION
Whichl kindl ofl relationshipl isl displayedl inl thel entity-relationshipl diagraml below?
⦁l Binaryl one-to-one
⦁l Unaryl many-to-many
⦁l Ternaryl one-to-one
⦁l Binaryl one-to-many
⦁l Unaryl one-to-one

Answer:
⦁l Binaryl one-to-many



QUESTION
Whichl kindl ofl relationshipl isl displayedl inl thel entity-relationshipl diagraml below?
⦁l Binaryl one-to-one
⦁l Unaryl many-to-many
⦁l Ternaryl one-to-one
⦁l Binaryl many-to-many
⦁l Unaryl one-to-one

Answer:
⦁l Binaryl many-to-many



QUESTION
Whichl kindl ofl relationshipl isl displayedl inl thel entity-relationshipl diagraml below?
⦁l Binaryl one-to-one

,⦁l Unaryl many-to-many
⦁l Ternaryl one-to-one
⦁l Binaryl many-to-many
⦁l Unaryl one-to-one

Answer:
⦁l Binaryl one-to-one



QUESTION
Whichl datal typel canl bel designatedl tol allowl forl storagel ofl dates
⦁l VARCHAR
⦁l INTEGER
⦁l DECIMAL
⦁l TIMESTAMP/DATE

Answer:
⦁l TIMESTAMP/DATE



QUESTION
Whichl queryl wouldl producel al resultl setl thatl listedl alll ofl thel patients,l regardlessl ofl
whetherl theyl hadl anl appointmentl inl thel Examl tablel orl not.l

A.l SELECTl patient_id,l first_name,l last_name,l exam_date
FROMl Patientl RIGHTl JOINl Exam
ONl Patient.patient_idl =l Exam.patient_id;
B.l SELECTl patient_id,l first_name,l last_name,l birthdate,l exam_date
FROMl Patientl LEFTl JOINl Exam
ONl Patient.patient_idl =l Exam.patient_id;
C.l SELECTl patient_id,l first_name,l last_name,l birthdate,l exam_date
FROMl Patientl INNERl JOINl Exam
ONl Patient.patient_idl =l Exam.exam_id;
D.l SELECTl patient_id,l first_name,l last_name,l birthdate,l exam_date
FROMl Patientl JOINl Exam
ONl Patient.patient_idl =l Exam.patient_id;

Answer:
B.l SELECTl patient_id,l first_name,l last_name,l birthdate,l exam_date
FROMl Patientl LEFTl JOINl Exam
ONl Patient.patient_idl =l Exam.patient_id;

, QUESTION
Whichl queryl wouldl producel al resultl setl thatl listedl alll ofl thel Modell Types,l regardlessl
ofl whetherl al modell wasl assignedl tol thatl type.l

A.l SELECTl model_id,l lname,l Models.model_type_id,l hourly_fee
FROMl Models
RIGHTl JOINl Model_Type
ONl Models.model_type_idl =l Model_Type.model_type_id;l
B.l SELECTl model_id,l lname,l Models.model_type_id,l hourly_fee
FROMl Models
LEFTl JOINl Model_Type
ONl Models.model_type_idl =l Model_Type.model_type_id;
C.l SELECTl model_id,l lname,l Models.model_type_id,l hourly_fee
FROMl Models
INNERl JOINl Model_Type
ONl Models.model_type_idl =l Model_Type.model_type_id;l
D.l SELECTl model_id,l lname,l Models.model_type_id,l hourly_fee
FROMl Models
JOINl Model_Type
ONl Models.model_type_idl =l Model_Type.model_type_id;

Answer:
A.l SELECTl model_id,l lname,l Models.model_type_id,l hourly_fee
FROMl Models
RIGHTl JOINl Model_Type
ONl Models.model_type_idl =l Model_Type.model_type_id;



QUESTION
Usingl Q39l tables,l writel al queryl tol listl alll modell IDs,l thel modell typel theyl arel
assignedl andl theirl hourlyl fees.

Answer:
SELECTl Models.model_id,l Models.model_type_id,l Model_Type.hourly_fee
FROMl Models
INNERl JOINl Model_Type
ONl Models.model_type_idl =l Model_Type.model_type_id;



QUESTION