JUNIOR ASSOCIATES PRE-EXAMINATION TRAINING FOR ELIGIBLE CANDIDATES QUANTITATIVE APTITUDE – SET
– 2 COMPLETELY UPDATED 2026 EDITION |VERIFIED QUESTIONS & 100% ACCURATE ANSWERS | GUARANTEED A+
PERFORMANCE
1|Page
1) The concentration of Honey and sugar syrup in 3 different brands D, E and F is 2:1,
7:4 and 6:7 respectively. If 1.5 kg of D is mixed with 2.6 kg F, then how much E is
required to make the ratio 4:3?
(a) 2.13
(b) 2.2
(c) 2.45
(d) 2.47
(e) 2.33
- ANSWER: (b)
Explanation:
We can take ‘y’ kg of E, to get to the equation:
2 6 7
1.5 ∗ + 2.6 ∗ +𝑦∗
13 713 11 4
1.5 ∗ + 2.6 ∗ +𝑦∗ 4 = 3
3 13 11
On simplifying,
7𝑦
2.2 +
11 4
4𝑦 = 3
1.9 +
11
On solving this we get y=2.2
2) If there is a string of 2m tightly binding 3 circles of equal radii as shown in the
figure, then what is the radii of the circles?
2
(a)
3+𝜋
3
(b)
𝜋
(c) 𝜋
31
(d)
3+𝜋
(e) None of the above -
1
,JUNIOR ASSOCIATES PRE-EXAMINATION TRAINING FOR ELIGIBLE CANDIDATES QUANTITATIVE APTITUDE – SET
– 2 COMPLETELY UPDATED 2026 EDITION |VERIFIED QUESTIONS & 100% ACCURATE ANSWERS | GUARANTEED A+
PERFORMANCE
2|Page
ANSWER: (d)
Let the radii of circle be ‘x’ metre. Since all 3 circles have equal radii, we will get an
equilateral triangle when connecting their centres. At A, Arc DE will subtend 120° since
there are 2 right angles OAE and BAD and 60° at OAB. Now, AB = DC =2x.
and arc DE = 120 2𝜋𝑥 = 2𝜋𝑥. Since the figure is symmetric, total length of string will be
360 3
3 (2𝜋𝑥 + 2𝑥) = 2
3
,JUNIOR ASSOCIATES PRE-EXAMINATION TRAINING FOR ELIGIBLE CANDIDATES QUANTITATIVE APTITUDE – SET
– 2 COMPLETELY UPDATED 2026 EDITION |VERIFIED QUESTIONS & 100% ACCURATE ANSWERS | GUARANTEED A+
PERFORMANCE
2
, JUNIOR ASSOCIATES PRE-EXAMINATION TRAINING FOR ELIGIBLE CANDIDATES QUANTITATIVE APTITUDE – SET
– 2 COMPLETELY UPDATED 2026 EDITION |VERIFIED QUESTIONS & 100% ACCURATE ANSWERS | GUARANTEED A+
PERFORMANCE
3|Page
1
Solving for x, we get x=
3+𝜋
3) Find the remainder when 5 + 52 + 53 + … + 5666 is divided by 6
(a) 0
(b) 1
(c) 2
(d) 4
(e) 5
- ANSWER: (a)
Explanation:
The remainder when 5 is divided by 6 is 5 The
remainder when 25 is divided by 6 is 1 The
remainder when 125 is divided by 6 is 5 The
remainder when 625 is divided by 6 is 1
Hence, Remainder for 5 + 25 is 0
Remainder for 5 + 25 + 125 + 625 will be 0 and so on
Since 666 is an even number, remainder for 5 + 52 + 53 + … + 5666 will be 0
4) The average weight of 12 men, 12 women and 20 children is 30kg. If the men and
women eat at a party to gain 0.55 and 0.35 kg per person respectively, then how
many hours do the children would have to play for the group’s average weight to
remain the same if for every half hour of play, the children lose 0.08kg?
(a) 2
(b) 3
(c) 4
(d) 5
– 2 COMPLETELY UPDATED 2026 EDITION |VERIFIED QUESTIONS & 100% ACCURATE ANSWERS | GUARANTEED A+
PERFORMANCE
1|Page
1) The concentration of Honey and sugar syrup in 3 different brands D, E and F is 2:1,
7:4 and 6:7 respectively. If 1.5 kg of D is mixed with 2.6 kg F, then how much E is
required to make the ratio 4:3?
(a) 2.13
(b) 2.2
(c) 2.45
(d) 2.47
(e) 2.33
- ANSWER: (b)
Explanation:
We can take ‘y’ kg of E, to get to the equation:
2 6 7
1.5 ∗ + 2.6 ∗ +𝑦∗
13 713 11 4
1.5 ∗ + 2.6 ∗ +𝑦∗ 4 = 3
3 13 11
On simplifying,
7𝑦
2.2 +
11 4
4𝑦 = 3
1.9 +
11
On solving this we get y=2.2
2) If there is a string of 2m tightly binding 3 circles of equal radii as shown in the
figure, then what is the radii of the circles?
2
(a)
3+𝜋
3
(b)
𝜋
(c) 𝜋
31
(d)
3+𝜋
(e) None of the above -
1
,JUNIOR ASSOCIATES PRE-EXAMINATION TRAINING FOR ELIGIBLE CANDIDATES QUANTITATIVE APTITUDE – SET
– 2 COMPLETELY UPDATED 2026 EDITION |VERIFIED QUESTIONS & 100% ACCURATE ANSWERS | GUARANTEED A+
PERFORMANCE
2|Page
ANSWER: (d)
Let the radii of circle be ‘x’ metre. Since all 3 circles have equal radii, we will get an
equilateral triangle when connecting their centres. At A, Arc DE will subtend 120° since
there are 2 right angles OAE and BAD and 60° at OAB. Now, AB = DC =2x.
and arc DE = 120 2𝜋𝑥 = 2𝜋𝑥. Since the figure is symmetric, total length of string will be
360 3
3 (2𝜋𝑥 + 2𝑥) = 2
3
,JUNIOR ASSOCIATES PRE-EXAMINATION TRAINING FOR ELIGIBLE CANDIDATES QUANTITATIVE APTITUDE – SET
– 2 COMPLETELY UPDATED 2026 EDITION |VERIFIED QUESTIONS & 100% ACCURATE ANSWERS | GUARANTEED A+
PERFORMANCE
2
, JUNIOR ASSOCIATES PRE-EXAMINATION TRAINING FOR ELIGIBLE CANDIDATES QUANTITATIVE APTITUDE – SET
– 2 COMPLETELY UPDATED 2026 EDITION |VERIFIED QUESTIONS & 100% ACCURATE ANSWERS | GUARANTEED A+
PERFORMANCE
3|Page
1
Solving for x, we get x=
3+𝜋
3) Find the remainder when 5 + 52 + 53 + … + 5666 is divided by 6
(a) 0
(b) 1
(c) 2
(d) 4
(e) 5
- ANSWER: (a)
Explanation:
The remainder when 5 is divided by 6 is 5 The
remainder when 25 is divided by 6 is 1 The
remainder when 125 is divided by 6 is 5 The
remainder when 625 is divided by 6 is 1
Hence, Remainder for 5 + 25 is 0
Remainder for 5 + 25 + 125 + 625 will be 0 and so on
Since 666 is an even number, remainder for 5 + 52 + 53 + … + 5666 will be 0
4) The average weight of 12 men, 12 women and 20 children is 30kg. If the men and
women eat at a party to gain 0.55 and 0.35 kg per person respectively, then how
many hours do the children would have to play for the group’s average weight to
remain the same if for every half hour of play, the children lose 0.08kg?
(a) 2
(b) 3
(c) 4
(d) 5
