Solution Manual for Precalculus A Right Triangle Approach 5th Edition by Marvin Bittinger Judith Beecher Judith Penna All Chapters.

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Ch.g2 FunctionsgandgTheirgGraphs
2.1 Functions
1 Determineg Whetherg ag Relationg Representsg ag Function

MULTIPLEg CHOICE.g Chooseg theg oneg alternativeg thatg bestg completesg theg statementg org answersg theg question.

Determineg whetherg theg relationg representsg ag function.g Ifg itg isg ag function,g stateg theg domaing andg range.
1)

4g →g g 8
9g →g 18
14g →g 28
19g →g 38

A) function B) function C) notgag function
domain:g {4,g9,g 14,g19 domain:{8,g 18,g 28,g38
} }
range:g {8,g18,g28,g38} range:g {4,g 9,g 14,g 19}

2)

Alice snake
gBra gcatgd
dgCa og
rl
A) function B) function C) notgag function
domain:g{Alice,gBrad,gCarl domain:g{snake,gcat,gdog
}grange:g{snake,gcat,gdog} }grange:g {Alice,gBrad,g Ca
rl}
3)

Alice catg
gBra dog
dgCa
rl
range:g {11,g6
A) function B) function
,g2,g18}
domain:g{Alice,gBrad,gCarl}gr domain:g{cat,gdog}g range:g{Alice,gBr
ange:g{cat,gdog} ad,gCarl}

4)g {(-3,g-6),g(0,g5),g(5,g-5),g(7,g-1)}
A) function B)g function
domain:g {-3,g 0,g 5,g 7} domain:g {-6,g5,g-5,g-1}
range:g {-6,g 5,g-5,g-1} range:g {-3,g 0,g 5,g 7}

5)g {(19,g -2),g (3,g-
1),g (3,g 0),g (4,g 1),g (12,g 3)} B) function
A) function domain:g {-2,g -1,g 0,g 1,g 3}
domain:g {19,g 4,g 3,g12} range:g {19,g4,g 3,g 12}
range:g{-2,g-1,g0,g 1,g3}

6)g {(-3,g11),g (- B) function
2,g6),g (0,g2),g (2,g6),g (4,g18)} domain:g {11,g 6,g2,g 18}
A) function range:g {-3,g -2,g 0,g 2,g 4}
domain:g {-3,g -2,g 0,g 2,g 4}
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C) notgag function




C)g notgag function




C)g notgag function




C) notgag function




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3g g
8thgEditiongSullivan
7)g {(7.55,g15.75),g (7.555,g -15.7),g (g ,g 0),g (0.43,g -7)}
7g
A) function B) function C) notgag function
g3g
domain:g {7.55,g7.555,g ,g 0.4 domain:g {15.75,g -15.7,g 0,g -
7}
3} g3g
7 range:g {7.55,g7.555,g ,g0.43
range:g {15.75,g -15.7,g 0,g -7} }
7

Determineg whetherg theg equationg definesg yg asg ag functiong ofg x.
8) yg =gx2
A) function B)g notgag function

g1
9) yg =g
x
A) function B)g notgag function

10) yg =g|x|
A) function B)g notgag function

11) y2g=g4g-gx2
A) function B)g notgag function

12) yg=g± 1g-g4x
A) function B)g notgag function

13) xg=gy2
A) function B)g notgag function

14) y2g+gxg=g7
A) function B)g notgag function

15) yg =g5x2g-g2xg +g9
A) function B)g notgag function

g5xg-g3
16) yg=g
xg-g1
A)g function B)g notgag function

17) x2g +g3y2g=g1
A) function B)g notgag function

18) xg+g5yg =g3
A) function B)g notgag function

19) -9xg+gx2g+g32g=gy
A) function B)g notgag function




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2 Findg theg Valueg ofg ag Functio
n

MULTIPLEg CHOICE.g Chooseg theg oneg alternativeg thatg bestg completesg theg statementg org answersg theg question.

Findg theg valueg forg theg function.
1) Findgf(-2)gwhengf(x)g=gx2g-g4xg-g6.
A) 6 B)g18 C)g 2 D)g -10

x2g-g8g
2) Findgf(-1)gwhengf(x)g=g .
xg-g3
g7 g9 g1 g9
A) 4 B) -g C) -g D) -g
4 4 2

3) Findg f(-9)g wheng f(x)g =g |x|-g 6.
A) 3 B)g-15 C)g15 D)g-3


4) Findg f(0)g wheng f(x)g = x2g+g6x.
A) 0 B)g 6 C) 42 D) 6

5) Findgf(-x)gwhengf(x)g=g3x2g-g3xg-g1.
A) 3x2g +g3xg-g1 B)g-3x2g+g3xg+g1 C)g 3x2g+g3xg+g1 D)g -3x2g +g 3xg-g1

g g x
6) Findgf(-x)gwhengf(x)g =g .
x2g+g7
g g -xg g g -xg x g g -x
A) 2g B) 2g C) D)
x +g7 x -g7 -x2g+g7 -x2g+g7


7) Findg-f(x)gwhengf(x)g =g-2x2g-g4xg-g5.
A) 2x2g+g4xg+g5 B)g-2x2g +g 4xg-g5 C)g-2x2g+g4xg+g5 D)g 2x2g+g4xg-g5

8) Findg-f(x)gwhengf(x)g=g|x|g-g6.
A) -|x|g+g 6 B)g|-x|g-g6 C)g-|x|g-g6 D)g|-x|g+g6

9) Findg f(xg -g 1)g wheng f(x)g =g 2x2g -g 4xg +g 5.
A) 2x2g-g8xg+g11 B)g-8x2g+g2xg+g11 C)g 2x2g-g8xg+g3 D)g 2x2g+g6xg+g3

x2g-g2g
10) Findgf(xg+g1)gwhengf(x)g=g .
xg+g4
x2g+g2xg- x2g+g2xg+ x2g+g2xg- x2g-g1
A) g1 B) g3 C) g1 D) xg+g5
xg+g5 xg+g5 xg-g3


11) Findg f(2x)g wheng f(x)g =g -3x2g +g 3xg -g 4.
A) -12x2g+g6xg-g4 B)g-6x2g+g6xg-g4 C)g-6x2g+g6xg-g8 D)g-12x2g+g6xg-g8


12) Findg f(2x)g wheng f(x)g = 5x2g+g7x.
A) 20x2g+g14 B) 2 5x2g +g7 C) 10x2g+g14 D) 10x2g+g28
x x x x



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