IOP2601 ASSIGNMENT 2 GUIDE FOR YEAR 2023

IOP 2601 ASSIGNMENT 2 (679079 ) SUGGESTED SOLUTIONS

QUESTION 1

1.1 Probability BONGO winning first prize
TOTAL NUMBER OF ENTRIES = 50
Number of entries submitted (BONGO) = 20
20
Therefore probability = 50 = 0.4




1.2 Probability VUYI winning Second prize
TOTAL NUMBER OF ENTRIES = 50 – 1=49
Number of entries submitted (VHUYI) = 15
15
Therefore probability = 49= 0.31




1.3 Probability BONGO and VHUYI winning first and second prize =
(Prob BONGO winning 1st prize x Prob VHUYI winning 2nd prize) + (Prob BONGO
winning 2nd prize x Prob VHUYI winning 1st prize)
20 15
= (0.4 x 0.31) + (49 𝑥 )
50

= (0.4 x 0.31) + (0.41 x 0.3)
=0.12 + 0.12
= 0.24




1
TUTOR:ADDIE
CONTACT:062 914 2414

, QUESTION 2

2.1 P(X <10) (smaller proportion)

µ = 18,ð = 9 N = 45

𝑋−µ
Z= 10 18
𝜎

10−18
=
9

−8
=
9

= Ф 0.89 (smaller proportion)

= 0.18473



2.2 P(X > 20)

𝑋−µ
Z=
𝜎

20−18
=
9

2
= 18 20
9

= Ф 0.22 (smaller proportion)

= 0.4129 x 100%

= 41.29%




2
TUTOR:ADDIE
CONTACT:062 914 2414