PHY1604
ASSIGNMENT 4 2021
QUESTION 1
𝐿𝑒𝑡: 𝑅1 = 𝑏𝑟𝑒𝑎𝑡ℎ𝑖𝑛𝑔 𝑟𝑎𝑡𝑒 𝑖𝑛 𝑡ℎ𝑒 𝑠𝑝𝑎𝑐𝑒𝑐𝑟𝑎𝑓𝑡
𝑅2 = 𝑏𝑟𝑒𝑎𝑡ℎ𝑖𝑛𝑔 𝑟𝑎𝑡𝑒 𝑎𝑡 𝑒𝑎𝑟𝑡ℎ
∆𝑡 = 𝛾∆𝑡𝑝
1
𝛾=
2
√1 − 𝑣2
𝑐
𝑛𝑢𝑚𝑏𝑒𝑟 𝑜𝑓 𝑏𝑟𝑒𝑎𝑡ℎ𝑠
𝑅1 =
∆𝑡𝑝
𝑛𝑢𝑚𝑏𝑒𝑟 𝑜𝑓 𝑏𝑟𝑒𝑎𝑡ℎ𝑠
𝑅2 =
∆𝑡
𝑇ℎ𝑒 𝑛𝑢𝑚𝑏𝑒𝑟 𝑜𝑓 𝑏𝑟𝑒𝑎𝑡ℎ𝑠 𝑑𝑜𝑒𝑠 𝑛𝑜𝑡 𝑐ℎ𝑎𝑛𝑔𝑒 , 𝑏𝑢𝑡 𝑡ℎ𝑒 𝑡𝑖𝑚𝑒 𝑖𝑛𝑡𝑒𝑟𝑣𝑎𝑙𝑠 𝑎𝑟𝑒 𝑑𝑖𝑓𝑓𝑒𝑟𝑒𝑛𝑡.
𝑅1 ∆𝑡𝑝 = 𝑅2 ∆𝑡
𝑅1 ∆𝑡𝑝
𝑅2 =
∆𝑡
∆𝑡𝑝 ∆𝑡𝑝 1
𝑅2 = 𝑅1 ∴ =
∆𝑡 ∆𝑡 𝛾
𝑅1
𝑅2 =
𝛾
𝑅1 = 8.0 𝑏𝑟𝑒𝑎𝑡ℎ𝑠 𝑝𝑒𝑟 𝑚𝑖𝑛𝑢𝑡𝑒
1
𝛾= ∴ 𝑣 = 0.975𝑐
2
√1 − 𝑣2
𝑐
, 1
𝛾=
2
√1 − (0.975𝑐)
𝑐2
1
𝛾=
2𝑐 2
√1 − (0.975)
2
𝑐
1
𝛾=
√1 − (0.975)2
𝛾 = 4.5
𝑅1
𝑅2 =
𝛾
8
𝑅2 =
4.5
𝑅2 = 1.78 𝑏𝑟𝑒𝑎𝑡ℎ𝑠 𝑝𝑒𝑟 𝑚𝑖𝑛𝑢𝑡𝑒
𝐴𝑠 𝑚𝑜𝑛𝑖𝑡𝑜𝑟𝑒𝑑 𝑜𝑛 𝑒𝑎𝑟𝑡ℎ 𝑡ℎ𝑒 𝑏𝑟𝑒𝑎𝑡ℎ𝑖𝑛𝑔 𝑟𝑎𝑡𝑒 = 1.78 𝑏𝑟𝑒𝑎𝑡ℎ𝑠 𝑝𝑒𝑟 𝑚𝑖𝑛𝑢𝑡𝑒
QUESTION 2
∆𝑡 = 𝛾∆𝑡𝑝
∆𝑡
𝑊𝑒 𝑎𝑟𝑒 𝑡𝑜𝑙𝑑: ∆𝑡𝑝 =
2
∆𝑡 = 𝛾∆𝑡𝑝
∆𝑡
∆𝑡 = 𝛾 ( )
2
𝛾=2
𝑝𝑟𝑒𝑙 = 𝛾𝑚𝑣⃗
𝑚𝑣⃗ = 𝑛𝑜𝑛𝑟𝑒𝑙𝑎𝑡𝑖𝑣𝑖𝑠𝑡𝑖𝑐 𝑚𝑜𝑚𝑒𝑛𝑡𝑢𝑚 = 1.3 × 1013 𝑘𝑔. 𝑚/𝑠
𝑝𝑟𝑒𝑙 = 2(1.3 × 1013 )
𝑝𝑟𝑒𝑙 = 2.6 × 1013 𝑘𝑔. 𝑚/𝑠
𝑅𝑒𝑙𝑎𝑡𝑖𝑣𝑖𝑠𝑡𝑖𝑐 𝑚𝑜𝑚𝑒𝑛𝑡𝑢𝑚 𝑜𝑓 𝑡ℎ𝑒 𝑠𝑝𝑎𝑐𝑒𝑠𝑐𝑎𝑓𝑡 = 2.6 × 1013 𝑘𝑔. 𝑚/𝑠
ASSIGNMENT 4 2021
QUESTION 1
𝐿𝑒𝑡: 𝑅1 = 𝑏𝑟𝑒𝑎𝑡ℎ𝑖𝑛𝑔 𝑟𝑎𝑡𝑒 𝑖𝑛 𝑡ℎ𝑒 𝑠𝑝𝑎𝑐𝑒𝑐𝑟𝑎𝑓𝑡
𝑅2 = 𝑏𝑟𝑒𝑎𝑡ℎ𝑖𝑛𝑔 𝑟𝑎𝑡𝑒 𝑎𝑡 𝑒𝑎𝑟𝑡ℎ
∆𝑡 = 𝛾∆𝑡𝑝
1
𝛾=
2
√1 − 𝑣2
𝑐
𝑛𝑢𝑚𝑏𝑒𝑟 𝑜𝑓 𝑏𝑟𝑒𝑎𝑡ℎ𝑠
𝑅1 =
∆𝑡𝑝
𝑛𝑢𝑚𝑏𝑒𝑟 𝑜𝑓 𝑏𝑟𝑒𝑎𝑡ℎ𝑠
𝑅2 =
∆𝑡
𝑇ℎ𝑒 𝑛𝑢𝑚𝑏𝑒𝑟 𝑜𝑓 𝑏𝑟𝑒𝑎𝑡ℎ𝑠 𝑑𝑜𝑒𝑠 𝑛𝑜𝑡 𝑐ℎ𝑎𝑛𝑔𝑒 , 𝑏𝑢𝑡 𝑡ℎ𝑒 𝑡𝑖𝑚𝑒 𝑖𝑛𝑡𝑒𝑟𝑣𝑎𝑙𝑠 𝑎𝑟𝑒 𝑑𝑖𝑓𝑓𝑒𝑟𝑒𝑛𝑡.
𝑅1 ∆𝑡𝑝 = 𝑅2 ∆𝑡
𝑅1 ∆𝑡𝑝
𝑅2 =
∆𝑡
∆𝑡𝑝 ∆𝑡𝑝 1
𝑅2 = 𝑅1 ∴ =
∆𝑡 ∆𝑡 𝛾
𝑅1
𝑅2 =
𝛾
𝑅1 = 8.0 𝑏𝑟𝑒𝑎𝑡ℎ𝑠 𝑝𝑒𝑟 𝑚𝑖𝑛𝑢𝑡𝑒
1
𝛾= ∴ 𝑣 = 0.975𝑐
2
√1 − 𝑣2
𝑐
, 1
𝛾=
2
√1 − (0.975𝑐)
𝑐2
1
𝛾=
2𝑐 2
√1 − (0.975)
2
𝑐
1
𝛾=
√1 − (0.975)2
𝛾 = 4.5
𝑅1
𝑅2 =
𝛾
8
𝑅2 =
4.5
𝑅2 = 1.78 𝑏𝑟𝑒𝑎𝑡ℎ𝑠 𝑝𝑒𝑟 𝑚𝑖𝑛𝑢𝑡𝑒
𝐴𝑠 𝑚𝑜𝑛𝑖𝑡𝑜𝑟𝑒𝑑 𝑜𝑛 𝑒𝑎𝑟𝑡ℎ 𝑡ℎ𝑒 𝑏𝑟𝑒𝑎𝑡ℎ𝑖𝑛𝑔 𝑟𝑎𝑡𝑒 = 1.78 𝑏𝑟𝑒𝑎𝑡ℎ𝑠 𝑝𝑒𝑟 𝑚𝑖𝑛𝑢𝑡𝑒
QUESTION 2
∆𝑡 = 𝛾∆𝑡𝑝
∆𝑡
𝑊𝑒 𝑎𝑟𝑒 𝑡𝑜𝑙𝑑: ∆𝑡𝑝 =
2
∆𝑡 = 𝛾∆𝑡𝑝
∆𝑡
∆𝑡 = 𝛾 ( )
2
𝛾=2
𝑝𝑟𝑒𝑙 = 𝛾𝑚𝑣⃗
𝑚𝑣⃗ = 𝑛𝑜𝑛𝑟𝑒𝑙𝑎𝑡𝑖𝑣𝑖𝑠𝑡𝑖𝑐 𝑚𝑜𝑚𝑒𝑛𝑡𝑢𝑚 = 1.3 × 1013 𝑘𝑔. 𝑚/𝑠
𝑝𝑟𝑒𝑙 = 2(1.3 × 1013 )
𝑝𝑟𝑒𝑙 = 2.6 × 1013 𝑘𝑔. 𝑚/𝑠
𝑅𝑒𝑙𝑎𝑡𝑖𝑣𝑖𝑠𝑡𝑖𝑐 𝑚𝑜𝑚𝑒𝑛𝑡𝑢𝑚 𝑜𝑓 𝑡ℎ𝑒 𝑠𝑝𝑎𝑐𝑒𝑠𝑐𝑎𝑓𝑡 = 2.6 × 1013 𝑘𝑔. 𝑚/𝑠