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ECD2601 PORTFOLIO Examination |CLEAR CONCISE ANSWERS|- DUE 7 October 2025

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ECD2601 PORTFOLIO Examination |CLEAR CONCISE ANSWERS|- DUE 7 October 2025 100% COMPLETE ANSWERS










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October 2, 2025
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ECD2601
PORTFOLIO

Examination
DUE: 7 October 2025

, PORTFOLIO EXAMINATION
07 OCTOBER 2025
SEMESTER COURSE
ENGINEERING GRAPHICS FOR ELECTRICAL DESIGN PROJECTS




Question 1: Rectifier Design (20 Marks)


1.1 Half-Wave Rectifier Design and Simulation (10 Marks)

Design and Explanation: A Half-wave rectifier is the simplest form of rectifier that
converts an AC voltage to a pulsating DC voltage. It uses a single diode to allow only
one half-cycle (either positive or negative) of the AC input voltage to pass through to the
load.

Components for an EasyEDA design:

• AC Voltage Source: To provide the input signal (e.g., a sin(𝑡) source with a
peak voltage 𝑉𝑝 ).

• Diode (D1): A standard signal or power diode (e.g., 1N4001).

• Load Resistor (𝑅𝐿 ): To represent the load (e.g., 1kΩ).

• Ground: Reference point.

Design Schematic: In EasyEDA, you would connect the components in series: AC
Source → Diode (anode to source, cathode to load) → Load Resistor → Ground.

Simulation Waveform: The output voltage (𝑉𝑜𝑢𝑡 ) across the load resistor will be:

• Positive half-cycle: 𝑉𝑜𝑢𝑡 ≈ 𝑉𝑖𝑛 − 0.7V (assuming a silicon diode) - a pulsating
positive voltage.

• Negative half-cycle: 𝑉𝑜𝑢𝑡 ≈ 0V (the diode is reverse-biased and acts as an open
circuit).

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